how to convert excel serial date number to date in Oracle SQL











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1
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I was trying to covert same Excel date format to dd/mm/yyyy format. But I am not getting the correct result.




43236 16-May-18
43249 29-May-18
43238 18-May-18
43228 8-May-18
43238 18-May-18


I am using the below query




SELECT to_date('31-12-1899','dd-mm-yyyy')+43236 FROM dual
UNION ALL
SELECT to_date('31-12-1899','dd-mm-yyyy')+43249 FROM dual
UNION ALL
SELECT to_date('31-12-1899','dd-mm-yyyy')+43238 FROM dual
UNION ALL
SELECT to_date('31-12-1899','dd-mm-yyyy')+43228 FROM dual
UNION ALL
SELECT to_date('31-12-1899','dd-mm-yyyy')+43238 FROM dual;



I am getting the below result which is not correct




17-MAY-18
30-MAY-18
19-MAY-18
09-MAY-18
19-MAY-18


Please help me on that. I am using Oracle 11g R2.










share|improve this question




















  • 2




    what is your expected output
    – fa06
    Nov 8 at 9:24






  • 1




    How is 43238 supposed to return 18-May-18 and 20-May-18 at the same time (line 3 and 5)?
    – Codo
    Nov 8 at 9:39










  • Sorry for the confusion.. I have edited the post..
    – SwapnaSubham Das
    Nov 8 at 11:02















up vote
1
down vote

favorite












I was trying to covert same Excel date format to dd/mm/yyyy format. But I am not getting the correct result.




43236 16-May-18
43249 29-May-18
43238 18-May-18
43228 8-May-18
43238 18-May-18


I am using the below query




SELECT to_date('31-12-1899','dd-mm-yyyy')+43236 FROM dual
UNION ALL
SELECT to_date('31-12-1899','dd-mm-yyyy')+43249 FROM dual
UNION ALL
SELECT to_date('31-12-1899','dd-mm-yyyy')+43238 FROM dual
UNION ALL
SELECT to_date('31-12-1899','dd-mm-yyyy')+43228 FROM dual
UNION ALL
SELECT to_date('31-12-1899','dd-mm-yyyy')+43238 FROM dual;



I am getting the below result which is not correct




17-MAY-18
30-MAY-18
19-MAY-18
09-MAY-18
19-MAY-18


Please help me on that. I am using Oracle 11g R2.










share|improve this question




















  • 2




    what is your expected output
    – fa06
    Nov 8 at 9:24






  • 1




    How is 43238 supposed to return 18-May-18 and 20-May-18 at the same time (line 3 and 5)?
    – Codo
    Nov 8 at 9:39










  • Sorry for the confusion.. I have edited the post..
    – SwapnaSubham Das
    Nov 8 at 11:02













up vote
1
down vote

favorite









up vote
1
down vote

favorite











I was trying to covert same Excel date format to dd/mm/yyyy format. But I am not getting the correct result.




43236 16-May-18
43249 29-May-18
43238 18-May-18
43228 8-May-18
43238 18-May-18


I am using the below query




SELECT to_date('31-12-1899','dd-mm-yyyy')+43236 FROM dual
UNION ALL
SELECT to_date('31-12-1899','dd-mm-yyyy')+43249 FROM dual
UNION ALL
SELECT to_date('31-12-1899','dd-mm-yyyy')+43238 FROM dual
UNION ALL
SELECT to_date('31-12-1899','dd-mm-yyyy')+43228 FROM dual
UNION ALL
SELECT to_date('31-12-1899','dd-mm-yyyy')+43238 FROM dual;



I am getting the below result which is not correct




17-MAY-18
30-MAY-18
19-MAY-18
09-MAY-18
19-MAY-18


Please help me on that. I am using Oracle 11g R2.










share|improve this question















I was trying to covert same Excel date format to dd/mm/yyyy format. But I am not getting the correct result.




43236 16-May-18
43249 29-May-18
43238 18-May-18
43228 8-May-18
43238 18-May-18


I am using the below query




SELECT to_date('31-12-1899','dd-mm-yyyy')+43236 FROM dual
UNION ALL
SELECT to_date('31-12-1899','dd-mm-yyyy')+43249 FROM dual
UNION ALL
SELECT to_date('31-12-1899','dd-mm-yyyy')+43238 FROM dual
UNION ALL
SELECT to_date('31-12-1899','dd-mm-yyyy')+43228 FROM dual
UNION ALL
SELECT to_date('31-12-1899','dd-mm-yyyy')+43238 FROM dual;



I am getting the below result which is not correct




17-MAY-18
30-MAY-18
19-MAY-18
09-MAY-18
19-MAY-18


Please help me on that. I am using Oracle 11g R2.







sql oracle oracle11g






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 8 at 11:01

























asked Nov 8 at 9:22









SwapnaSubham Das

1189




1189








  • 2




    what is your expected output
    – fa06
    Nov 8 at 9:24






  • 1




    How is 43238 supposed to return 18-May-18 and 20-May-18 at the same time (line 3 and 5)?
    – Codo
    Nov 8 at 9:39










  • Sorry for the confusion.. I have edited the post..
    – SwapnaSubham Das
    Nov 8 at 11:02














  • 2




    what is your expected output
    – fa06
    Nov 8 at 9:24






  • 1




    How is 43238 supposed to return 18-May-18 and 20-May-18 at the same time (line 3 and 5)?
    – Codo
    Nov 8 at 9:39










  • Sorry for the confusion.. I have edited the post..
    – SwapnaSubham Das
    Nov 8 at 11:02








2




2




what is your expected output
– fa06
Nov 8 at 9:24




what is your expected output
– fa06
Nov 8 at 9:24




1




1




How is 43238 supposed to return 18-May-18 and 20-May-18 at the same time (line 3 and 5)?
– Codo
Nov 8 at 9:39




How is 43238 supposed to return 18-May-18 and 20-May-18 at the same time (line 3 and 5)?
– Codo
Nov 8 at 9:39












Sorry for the confusion.. I have edited the post..
– SwapnaSubham Das
Nov 8 at 11:02




Sorry for the confusion.. I have edited the post..
– SwapnaSubham Das
Nov 8 at 11:02












3 Answers
3






active

oldest

votes

















up vote
1
down vote













You're simply off by 1. Use 30 Dec 1899 (instead of 31 Dec 1899) as the reference date for index 0.



SELECT to_date('31-12-1899','dd-mm-yyyy') + 43236 FROM dual


The reason it's 30 Dec 1899 and not 1 Jan 1900 is twofold:




  1. In Excel, 1 Jan 1900 is saved as 1 (and not as 0 as an IT guy would expect).

  2. Excel treats the year 1900 has a leap year even though it wasn't. Therefore, Excel also has a number for 29 Feb 1900, which did not exist.






share|improve this answer




























    up vote
    0
    down vote













    If I understand correctly you can try to use TO_DATE and set language culture then TO_CHAR for your expected format.



    select TO_CHAR(TO_DATE('16-May-18','DD-Mon-YY', 'nls_date_language = american'),'DD/mm/yyyy')
    from dual


    or like this.



    SELECT TO_CHAR(to_date('31-12-1899','dd-mm-yyyy')+43236,'DD/mm/yyyy') FROM dual


    sqlfiddle






    share|improve this answer




























      up vote
      0
      down vote













      You can try below using to_char() function



      select to_char(TO_date('31-12-1899', 'dd-mm-yyyy')+43236,'DD/MM/YYYY')  from dual





      share|improve this answer





















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        3 Answers
        3






        active

        oldest

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        3 Answers
        3






        active

        oldest

        votes









        active

        oldest

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        active

        oldest

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        up vote
        1
        down vote













        You're simply off by 1. Use 30 Dec 1899 (instead of 31 Dec 1899) as the reference date for index 0.



        SELECT to_date('31-12-1899','dd-mm-yyyy') + 43236 FROM dual


        The reason it's 30 Dec 1899 and not 1 Jan 1900 is twofold:




        1. In Excel, 1 Jan 1900 is saved as 1 (and not as 0 as an IT guy would expect).

        2. Excel treats the year 1900 has a leap year even though it wasn't. Therefore, Excel also has a number for 29 Feb 1900, which did not exist.






        share|improve this answer

























          up vote
          1
          down vote













          You're simply off by 1. Use 30 Dec 1899 (instead of 31 Dec 1899) as the reference date for index 0.



          SELECT to_date('31-12-1899','dd-mm-yyyy') + 43236 FROM dual


          The reason it's 30 Dec 1899 and not 1 Jan 1900 is twofold:




          1. In Excel, 1 Jan 1900 is saved as 1 (and not as 0 as an IT guy would expect).

          2. Excel treats the year 1900 has a leap year even though it wasn't. Therefore, Excel also has a number for 29 Feb 1900, which did not exist.






          share|improve this answer























            up vote
            1
            down vote










            up vote
            1
            down vote









            You're simply off by 1. Use 30 Dec 1899 (instead of 31 Dec 1899) as the reference date for index 0.



            SELECT to_date('31-12-1899','dd-mm-yyyy') + 43236 FROM dual


            The reason it's 30 Dec 1899 and not 1 Jan 1900 is twofold:




            1. In Excel, 1 Jan 1900 is saved as 1 (and not as 0 as an IT guy would expect).

            2. Excel treats the year 1900 has a leap year even though it wasn't. Therefore, Excel also has a number for 29 Feb 1900, which did not exist.






            share|improve this answer












            You're simply off by 1. Use 30 Dec 1899 (instead of 31 Dec 1899) as the reference date for index 0.



            SELECT to_date('31-12-1899','dd-mm-yyyy') + 43236 FROM dual


            The reason it's 30 Dec 1899 and not 1 Jan 1900 is twofold:




            1. In Excel, 1 Jan 1900 is saved as 1 (and not as 0 as an IT guy would expect).

            2. Excel treats the year 1900 has a leap year even though it wasn't. Therefore, Excel also has a number for 29 Feb 1900, which did not exist.







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 8 at 11:47









            Codo

            49.8k11110146




            49.8k11110146
























                up vote
                0
                down vote













                If I understand correctly you can try to use TO_DATE and set language culture then TO_CHAR for your expected format.



                select TO_CHAR(TO_DATE('16-May-18','DD-Mon-YY', 'nls_date_language = american'),'DD/mm/yyyy')
                from dual


                or like this.



                SELECT TO_CHAR(to_date('31-12-1899','dd-mm-yyyy')+43236,'DD/mm/yyyy') FROM dual


                sqlfiddle






                share|improve this answer

























                  up vote
                  0
                  down vote













                  If I understand correctly you can try to use TO_DATE and set language culture then TO_CHAR for your expected format.



                  select TO_CHAR(TO_DATE('16-May-18','DD-Mon-YY', 'nls_date_language = american'),'DD/mm/yyyy')
                  from dual


                  or like this.



                  SELECT TO_CHAR(to_date('31-12-1899','dd-mm-yyyy')+43236,'DD/mm/yyyy') FROM dual


                  sqlfiddle






                  share|improve this answer























                    up vote
                    0
                    down vote










                    up vote
                    0
                    down vote









                    If I understand correctly you can try to use TO_DATE and set language culture then TO_CHAR for your expected format.



                    select TO_CHAR(TO_DATE('16-May-18','DD-Mon-YY', 'nls_date_language = american'),'DD/mm/yyyy')
                    from dual


                    or like this.



                    SELECT TO_CHAR(to_date('31-12-1899','dd-mm-yyyy')+43236,'DD/mm/yyyy') FROM dual


                    sqlfiddle






                    share|improve this answer












                    If I understand correctly you can try to use TO_DATE and set language culture then TO_CHAR for your expected format.



                    select TO_CHAR(TO_DATE('16-May-18','DD-Mon-YY', 'nls_date_language = american'),'DD/mm/yyyy')
                    from dual


                    or like this.



                    SELECT TO_CHAR(to_date('31-12-1899','dd-mm-yyyy')+43236,'DD/mm/yyyy') FROM dual


                    sqlfiddle







                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Nov 8 at 9:31









                    D-Shih

                    23.9k61331




                    23.9k61331






















                        up vote
                        0
                        down vote













                        You can try below using to_char() function



                        select to_char(TO_date('31-12-1899', 'dd-mm-yyyy')+43236,'DD/MM/YYYY')  from dual





                        share|improve this answer

























                          up vote
                          0
                          down vote













                          You can try below using to_char() function



                          select to_char(TO_date('31-12-1899', 'dd-mm-yyyy')+43236,'DD/MM/YYYY')  from dual





                          share|improve this answer























                            up vote
                            0
                            down vote










                            up vote
                            0
                            down vote









                            You can try below using to_char() function



                            select to_char(TO_date('31-12-1899', 'dd-mm-yyyy')+43236,'DD/MM/YYYY')  from dual





                            share|improve this answer












                            You can try below using to_char() function



                            select to_char(TO_date('31-12-1899', 'dd-mm-yyyy')+43236,'DD/MM/YYYY')  from dual






                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered Nov 8 at 9:34









                            fa06

                            8,2821715




                            8,2821715






























                                 

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