XSLT copy from external document











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In XSLT 2.0 I am transforming a tei-xml document into HTML. In that transformationI need content from another document: I want to copy/transform a small set of nodes from the second document into the HTML output.



While processing the principal tei document I get the id and assign it to a variable:



<xsl:variable name="licenseid" select="./replace(@corresp,'#','')"/>


Then I go out to the other document and fetch the node using the variable, with the returned node assigned to a variable:



<xsl:variable name="licenseloc" select="doc(concat($somepath,'includes_sourcedesc.xml'))//tei:list[@type='copyright_type']/tei:item[@xml:id=$licenseid]"/>


This node I obtain looks like this:



<list type="copyright_type">
<item xml:id="copyright-cc-by-nc-sa-4.0">
<desc xml:lang="en">This work is made by available the author under the
<ref target="http://creativecommons.org/licenses/by-nc-sa/4.0/">Creative Commons Attribution-NonCommercial-ShareAlike
4.0 International License</ref>.</desc>
</item>
</list>


And I want to transform it (from desc) to this:



<span>This work is made by available by the author under the 
<a href="http://creativecommons.org/licenses/by-nc-sa/4.0/">Creative Commons Attribution-NonCommercial-ShareAlike
4.0 International License</a>.</span>


If this were in my 'current' tei document I would handle it through templates, but I'm unsure how to copy and transform the nested layers from within a different 'current' document.










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  • 2




    You can use <xsl:apply-templates select="$licenseloc"/> (if needed with a mode="some-mode") and then write templates as usual for the element(s).
    – Martin Honnen
    Nov 9 at 22:25










  • @MartinHonnen well now that you say it, it's obvious. I was locked into the idea that templates must concern the 'current file' instead of thinking with 'nodes'. Thanks very much.
    – jbrehr
    Nov 10 at 9:56















up vote
0
down vote

favorite












In XSLT 2.0 I am transforming a tei-xml document into HTML. In that transformationI need content from another document: I want to copy/transform a small set of nodes from the second document into the HTML output.



While processing the principal tei document I get the id and assign it to a variable:



<xsl:variable name="licenseid" select="./replace(@corresp,'#','')"/>


Then I go out to the other document and fetch the node using the variable, with the returned node assigned to a variable:



<xsl:variable name="licenseloc" select="doc(concat($somepath,'includes_sourcedesc.xml'))//tei:list[@type='copyright_type']/tei:item[@xml:id=$licenseid]"/>


This node I obtain looks like this:



<list type="copyright_type">
<item xml:id="copyright-cc-by-nc-sa-4.0">
<desc xml:lang="en">This work is made by available the author under the
<ref target="http://creativecommons.org/licenses/by-nc-sa/4.0/">Creative Commons Attribution-NonCommercial-ShareAlike
4.0 International License</ref>.</desc>
</item>
</list>


And I want to transform it (from desc) to this:



<span>This work is made by available by the author under the 
<a href="http://creativecommons.org/licenses/by-nc-sa/4.0/">Creative Commons Attribution-NonCommercial-ShareAlike
4.0 International License</a>.</span>


If this were in my 'current' tei document I would handle it through templates, but I'm unsure how to copy and transform the nested layers from within a different 'current' document.










share|improve this question




















  • 2




    You can use <xsl:apply-templates select="$licenseloc"/> (if needed with a mode="some-mode") and then write templates as usual for the element(s).
    – Martin Honnen
    Nov 9 at 22:25










  • @MartinHonnen well now that you say it, it's obvious. I was locked into the idea that templates must concern the 'current file' instead of thinking with 'nodes'. Thanks very much.
    – jbrehr
    Nov 10 at 9:56













up vote
0
down vote

favorite









up vote
0
down vote

favorite











In XSLT 2.0 I am transforming a tei-xml document into HTML. In that transformationI need content from another document: I want to copy/transform a small set of nodes from the second document into the HTML output.



While processing the principal tei document I get the id and assign it to a variable:



<xsl:variable name="licenseid" select="./replace(@corresp,'#','')"/>


Then I go out to the other document and fetch the node using the variable, with the returned node assigned to a variable:



<xsl:variable name="licenseloc" select="doc(concat($somepath,'includes_sourcedesc.xml'))//tei:list[@type='copyright_type']/tei:item[@xml:id=$licenseid]"/>


This node I obtain looks like this:



<list type="copyright_type">
<item xml:id="copyright-cc-by-nc-sa-4.0">
<desc xml:lang="en">This work is made by available the author under the
<ref target="http://creativecommons.org/licenses/by-nc-sa/4.0/">Creative Commons Attribution-NonCommercial-ShareAlike
4.0 International License</ref>.</desc>
</item>
</list>


And I want to transform it (from desc) to this:



<span>This work is made by available by the author under the 
<a href="http://creativecommons.org/licenses/by-nc-sa/4.0/">Creative Commons Attribution-NonCommercial-ShareAlike
4.0 International License</a>.</span>


If this were in my 'current' tei document I would handle it through templates, but I'm unsure how to copy and transform the nested layers from within a different 'current' document.










share|improve this question















In XSLT 2.0 I am transforming a tei-xml document into HTML. In that transformationI need content from another document: I want to copy/transform a small set of nodes from the second document into the HTML output.



While processing the principal tei document I get the id and assign it to a variable:



<xsl:variable name="licenseid" select="./replace(@corresp,'#','')"/>


Then I go out to the other document and fetch the node using the variable, with the returned node assigned to a variable:



<xsl:variable name="licenseloc" select="doc(concat($somepath,'includes_sourcedesc.xml'))//tei:list[@type='copyright_type']/tei:item[@xml:id=$licenseid]"/>


This node I obtain looks like this:



<list type="copyright_type">
<item xml:id="copyright-cc-by-nc-sa-4.0">
<desc xml:lang="en">This work is made by available the author under the
<ref target="http://creativecommons.org/licenses/by-nc-sa/4.0/">Creative Commons Attribution-NonCommercial-ShareAlike
4.0 International License</ref>.</desc>
</item>
</list>


And I want to transform it (from desc) to this:



<span>This work is made by available by the author under the 
<a href="http://creativecommons.org/licenses/by-nc-sa/4.0/">Creative Commons Attribution-NonCommercial-ShareAlike
4.0 International License</a>.</span>


If this were in my 'current' tei document I would handle it through templates, but I'm unsure how to copy and transform the nested layers from within a different 'current' document.







xslt xslt-2.0






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share|improve this question













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share|improve this question








edited Nov 9 at 21:42

























asked Nov 9 at 21:24









jbrehr

110112




110112








  • 2




    You can use <xsl:apply-templates select="$licenseloc"/> (if needed with a mode="some-mode") and then write templates as usual for the element(s).
    – Martin Honnen
    Nov 9 at 22:25










  • @MartinHonnen well now that you say it, it's obvious. I was locked into the idea that templates must concern the 'current file' instead of thinking with 'nodes'. Thanks very much.
    – jbrehr
    Nov 10 at 9:56














  • 2




    You can use <xsl:apply-templates select="$licenseloc"/> (if needed with a mode="some-mode") and then write templates as usual for the element(s).
    – Martin Honnen
    Nov 9 at 22:25










  • @MartinHonnen well now that you say it, it's obvious. I was locked into the idea that templates must concern the 'current file' instead of thinking with 'nodes'. Thanks very much.
    – jbrehr
    Nov 10 at 9:56








2




2




You can use <xsl:apply-templates select="$licenseloc"/> (if needed with a mode="some-mode") and then write templates as usual for the element(s).
– Martin Honnen
Nov 9 at 22:25




You can use <xsl:apply-templates select="$licenseloc"/> (if needed with a mode="some-mode") and then write templates as usual for the element(s).
– Martin Honnen
Nov 9 at 22:25












@MartinHonnen well now that you say it, it's obvious. I was locked into the idea that templates must concern the 'current file' instead of thinking with 'nodes'. Thanks very much.
– jbrehr
Nov 10 at 9:56




@MartinHonnen well now that you say it, it's obvious. I was locked into the idea that templates must concern the 'current file' instead of thinking with 'nodes'. Thanks very much.
– jbrehr
Nov 10 at 9:56

















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