Swift Linear Interpolation and UpSampling











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I have a stream of metrics that are unevenly sampled. I want to linearly interpolate and upsample these metrics to a specific sampling frequency. I have tried to use the Accelerate Framework and the SIMD framework but I am not really sure what to do.



The problem itself is as follows:



let original_times:[Double] = [0.0, 2.0, 3.0, 6.0, 10.0]
let original_values: [Double] = [50.0, 20.0, 30.0, 40.0, 10.0]
let new_times:[Double] = [0.0, 1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0]


So I am looking for a way to find the new_values through some sort of linear interpolation method.










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    1












    I have a stream of metrics that are unevenly sampled. I want to linearly interpolate and upsample these metrics to a specific sampling frequency. I have tried to use the Accelerate Framework and the SIMD framework but I am not really sure what to do.



    The problem itself is as follows:



    let original_times:[Double] = [0.0, 2.0, 3.0, 6.0, 10.0]
    let original_values: [Double] = [50.0, 20.0, 30.0, 40.0, 10.0]
    let new_times:[Double] = [0.0, 1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0]


    So I am looking for a way to find the new_values through some sort of linear interpolation method.










    share|improve this question
























      up vote
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      down vote

      favorite
      1









      up vote
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      I have a stream of metrics that are unevenly sampled. I want to linearly interpolate and upsample these metrics to a specific sampling frequency. I have tried to use the Accelerate Framework and the SIMD framework but I am not really sure what to do.



      The problem itself is as follows:



      let original_times:[Double] = [0.0, 2.0, 3.0, 6.0, 10.0]
      let original_values: [Double] = [50.0, 20.0, 30.0, 40.0, 10.0]
      let new_times:[Double] = [0.0, 1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0]


      So I am looking for a way to find the new_values through some sort of linear interpolation method.










      share|improve this question













      I have a stream of metrics that are unevenly sampled. I want to linearly interpolate and upsample these metrics to a specific sampling frequency. I have tried to use the Accelerate Framework and the SIMD framework but I am not really sure what to do.



      The problem itself is as follows:



      let original_times:[Double] = [0.0, 2.0, 3.0, 6.0, 10.0]
      let original_values: [Double] = [50.0, 20.0, 30.0, 40.0, 10.0]
      let new_times:[Double] = [0.0, 1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0]


      So I am looking for a way to find the new_values through some sort of linear interpolation method.







      arrays swift interpolation accelerate-framework linear-interpolation






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 8 at 16:54









      Samyak Shah

      83




      83
























          2 Answers
          2






          active

          oldest

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          up vote
          1
          down vote



          accepted










          vDSP_vgenpD will do the job for you. Pass it the original times and values, and it will populate an array with the interpolated values. For example:



          import Accelerate

          let original_times:[Double] = [0.0, 2.0, 3.0, 6.0, 10.0]
          let original_values: [Double] = [50.0, 20.0, 30.0, 40.0, 10.0]

          var new_values = [Double](repeating: 0,
          count: 11)

          let stride = vDSP_Stride(1)

          vDSP_vgenpD(original_values, stride,
          original_times, stride,
          &new_values, stride,
          vDSP_Length(new_values.count),
          vDSP_Length(original_values.count))


          You can get an array of time / value tuples with:



          let result = new_values.enumerated().map{ return $0 }


          That looks like:



          enter image description here






          share|improve this answer






























            up vote
            0
            down vote













            Interpolation is a wide field (see. Wikipedia : https://en.wikipedia.org/wiki/Interpolation)



            The simplest method is a linear interpolation like this.



            class LinearInterpolation {

            private var n : Int
            private var x : [Double]
            private var y : [Double]
            init (x: [Double], y: [Double]) {
            assert(x.count == y.count)
            self.n = x.count-1
            self.x = x
            self.y = y
            }

            func Interpolate(t: Double) -> Double {
            if t <= x[0] { return y[0] }
            for i in 1...n {
            if t <= x[i] {
            let ans = (t-x[i-1]) * (y[i] - y[i-1]) / (x[i]-x[i-1]) + y[i-1]
            return ans
            }
            }
            return y[n]
            }


            }



            Usage:



                let original_times:[Double] = [0.0, 2.0, 3.0, 6.0, 10.0]
            let original_values: [Double] = [50.0, 20.0, 30.0, 40.0, 10.0]
            let new_times:[Double] = [0.0, 1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0]
            let ipol = LinearInterpolation(x: original_times, y: original_values)
            for t in new_times {
            let y = ipol.Interpolate(t: t)
            print("t: (t) y: (y)")
            }


            In your Usecase with something like audio data you should take a look at Fourier analysis.






            share|improve this answer





















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              2 Answers
              2






              active

              oldest

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              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes








              up vote
              1
              down vote



              accepted










              vDSP_vgenpD will do the job for you. Pass it the original times and values, and it will populate an array with the interpolated values. For example:



              import Accelerate

              let original_times:[Double] = [0.0, 2.0, 3.0, 6.0, 10.0]
              let original_values: [Double] = [50.0, 20.0, 30.0, 40.0, 10.0]

              var new_values = [Double](repeating: 0,
              count: 11)

              let stride = vDSP_Stride(1)

              vDSP_vgenpD(original_values, stride,
              original_times, stride,
              &new_values, stride,
              vDSP_Length(new_values.count),
              vDSP_Length(original_values.count))


              You can get an array of time / value tuples with:



              let result = new_values.enumerated().map{ return $0 }


              That looks like:



              enter image description here






              share|improve this answer



























                up vote
                1
                down vote



                accepted










                vDSP_vgenpD will do the job for you. Pass it the original times and values, and it will populate an array with the interpolated values. For example:



                import Accelerate

                let original_times:[Double] = [0.0, 2.0, 3.0, 6.0, 10.0]
                let original_values: [Double] = [50.0, 20.0, 30.0, 40.0, 10.0]

                var new_values = [Double](repeating: 0,
                count: 11)

                let stride = vDSP_Stride(1)

                vDSP_vgenpD(original_values, stride,
                original_times, stride,
                &new_values, stride,
                vDSP_Length(new_values.count),
                vDSP_Length(original_values.count))


                You can get an array of time / value tuples with:



                let result = new_values.enumerated().map{ return $0 }


                That looks like:



                enter image description here






                share|improve this answer

























                  up vote
                  1
                  down vote



                  accepted







                  up vote
                  1
                  down vote



                  accepted






                  vDSP_vgenpD will do the job for you. Pass it the original times and values, and it will populate an array with the interpolated values. For example:



                  import Accelerate

                  let original_times:[Double] = [0.0, 2.0, 3.0, 6.0, 10.0]
                  let original_values: [Double] = [50.0, 20.0, 30.0, 40.0, 10.0]

                  var new_values = [Double](repeating: 0,
                  count: 11)

                  let stride = vDSP_Stride(1)

                  vDSP_vgenpD(original_values, stride,
                  original_times, stride,
                  &new_values, stride,
                  vDSP_Length(new_values.count),
                  vDSP_Length(original_values.count))


                  You can get an array of time / value tuples with:



                  let result = new_values.enumerated().map{ return $0 }


                  That looks like:



                  enter image description here






                  share|improve this answer














                  vDSP_vgenpD will do the job for you. Pass it the original times and values, and it will populate an array with the interpolated values. For example:



                  import Accelerate

                  let original_times:[Double] = [0.0, 2.0, 3.0, 6.0, 10.0]
                  let original_values: [Double] = [50.0, 20.0, 30.0, 40.0, 10.0]

                  var new_values = [Double](repeating: 0,
                  count: 11)

                  let stride = vDSP_Stride(1)

                  vDSP_vgenpD(original_values, stride,
                  original_times, stride,
                  &new_values, stride,
                  vDSP_Length(new_values.count),
                  vDSP_Length(original_values.count))


                  You can get an array of time / value tuples with:



                  let result = new_values.enumerated().map{ return $0 }


                  That looks like:



                  enter image description here







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 15 at 15:07

























                  answered Nov 15 at 9:29









                  Simon Gladman

                  2,3291014




                  2,3291014
























                      up vote
                      0
                      down vote













                      Interpolation is a wide field (see. Wikipedia : https://en.wikipedia.org/wiki/Interpolation)



                      The simplest method is a linear interpolation like this.



                      class LinearInterpolation {

                      private var n : Int
                      private var x : [Double]
                      private var y : [Double]
                      init (x: [Double], y: [Double]) {
                      assert(x.count == y.count)
                      self.n = x.count-1
                      self.x = x
                      self.y = y
                      }

                      func Interpolate(t: Double) -> Double {
                      if t <= x[0] { return y[0] }
                      for i in 1...n {
                      if t <= x[i] {
                      let ans = (t-x[i-1]) * (y[i] - y[i-1]) / (x[i]-x[i-1]) + y[i-1]
                      return ans
                      }
                      }
                      return y[n]
                      }


                      }



                      Usage:



                          let original_times:[Double] = [0.0, 2.0, 3.0, 6.0, 10.0]
                      let original_values: [Double] = [50.0, 20.0, 30.0, 40.0, 10.0]
                      let new_times:[Double] = [0.0, 1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0]
                      let ipol = LinearInterpolation(x: original_times, y: original_values)
                      for t in new_times {
                      let y = ipol.Interpolate(t: t)
                      print("t: (t) y: (y)")
                      }


                      In your Usecase with something like audio data you should take a look at Fourier analysis.






                      share|improve this answer

























                        up vote
                        0
                        down vote













                        Interpolation is a wide field (see. Wikipedia : https://en.wikipedia.org/wiki/Interpolation)



                        The simplest method is a linear interpolation like this.



                        class LinearInterpolation {

                        private var n : Int
                        private var x : [Double]
                        private var y : [Double]
                        init (x: [Double], y: [Double]) {
                        assert(x.count == y.count)
                        self.n = x.count-1
                        self.x = x
                        self.y = y
                        }

                        func Interpolate(t: Double) -> Double {
                        if t <= x[0] { return y[0] }
                        for i in 1...n {
                        if t <= x[i] {
                        let ans = (t-x[i-1]) * (y[i] - y[i-1]) / (x[i]-x[i-1]) + y[i-1]
                        return ans
                        }
                        }
                        return y[n]
                        }


                        }



                        Usage:



                            let original_times:[Double] = [0.0, 2.0, 3.0, 6.0, 10.0]
                        let original_values: [Double] = [50.0, 20.0, 30.0, 40.0, 10.0]
                        let new_times:[Double] = [0.0, 1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0]
                        let ipol = LinearInterpolation(x: original_times, y: original_values)
                        for t in new_times {
                        let y = ipol.Interpolate(t: t)
                        print("t: (t) y: (y)")
                        }


                        In your Usecase with something like audio data you should take a look at Fourier analysis.






                        share|improve this answer























                          up vote
                          0
                          down vote










                          up vote
                          0
                          down vote









                          Interpolation is a wide field (see. Wikipedia : https://en.wikipedia.org/wiki/Interpolation)



                          The simplest method is a linear interpolation like this.



                          class LinearInterpolation {

                          private var n : Int
                          private var x : [Double]
                          private var y : [Double]
                          init (x: [Double], y: [Double]) {
                          assert(x.count == y.count)
                          self.n = x.count-1
                          self.x = x
                          self.y = y
                          }

                          func Interpolate(t: Double) -> Double {
                          if t <= x[0] { return y[0] }
                          for i in 1...n {
                          if t <= x[i] {
                          let ans = (t-x[i-1]) * (y[i] - y[i-1]) / (x[i]-x[i-1]) + y[i-1]
                          return ans
                          }
                          }
                          return y[n]
                          }


                          }



                          Usage:



                              let original_times:[Double] = [0.0, 2.0, 3.0, 6.0, 10.0]
                          let original_values: [Double] = [50.0, 20.0, 30.0, 40.0, 10.0]
                          let new_times:[Double] = [0.0, 1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0]
                          let ipol = LinearInterpolation(x: original_times, y: original_values)
                          for t in new_times {
                          let y = ipol.Interpolate(t: t)
                          print("t: (t) y: (y)")
                          }


                          In your Usecase with something like audio data you should take a look at Fourier analysis.






                          share|improve this answer












                          Interpolation is a wide field (see. Wikipedia : https://en.wikipedia.org/wiki/Interpolation)



                          The simplest method is a linear interpolation like this.



                          class LinearInterpolation {

                          private var n : Int
                          private var x : [Double]
                          private var y : [Double]
                          init (x: [Double], y: [Double]) {
                          assert(x.count == y.count)
                          self.n = x.count-1
                          self.x = x
                          self.y = y
                          }

                          func Interpolate(t: Double) -> Double {
                          if t <= x[0] { return y[0] }
                          for i in 1...n {
                          if t <= x[i] {
                          let ans = (t-x[i-1]) * (y[i] - y[i-1]) / (x[i]-x[i-1]) + y[i-1]
                          return ans
                          }
                          }
                          return y[n]
                          }


                          }



                          Usage:



                              let original_times:[Double] = [0.0, 2.0, 3.0, 6.0, 10.0]
                          let original_values: [Double] = [50.0, 20.0, 30.0, 40.0, 10.0]
                          let new_times:[Double] = [0.0, 1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0]
                          let ipol = LinearInterpolation(x: original_times, y: original_values)
                          for t in new_times {
                          let y = ipol.Interpolate(t: t)
                          print("t: (t) y: (y)")
                          }


                          In your Usecase with something like audio data you should take a look at Fourier analysis.







                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Nov 8 at 17:55









                          Stephan Januar

                          713




                          713






























                               

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