python argparse: unrecognized arguments
up vote
20
down vote
favorite
When I run parsePlotSens.py -s bw hehe, it says that hehe is an unrecognized argument. However, if I run parsePlotSens.py hehe -s bw, it's OK. Ideally, I would like it work for both cases.
Any tips? The following is my code:
if __name__ == '__main__' :
parser = argparse.ArgumentParser(prog='parsePlotSens');
parser.add_argument('-s', '--sort', nargs =1, action = 'store', choices = ['mcs', 'bw'], default='mcs', help=sorthelp)
parser.add_argument('filename', nargs ='+', action = 'store')
option = parser.parse_args(sys.argv)
python argparse
edited Dec 11 '17 at 21:56
alex
2,46053166
asked Jun 15 '13 at 0:14
Yan Zhu
1,27021330
add a comment |
up vote
20
down vote
favorite
When I run parsePlotSens.py -s bw hehe, it says that hehe is an unrecognized argument. However, if I run parsePlotSens.py hehe -s bw, it's OK. Ideally, I would like it work for both cases.
Any tips? The following is my code:
if __name__ == '__main__' :
parser = argparse.ArgumentParser(prog='parsePlotSens');
parser.add_argument('-s', '--sort', nargs =1, action = 'store', choices = ['mcs', 'bw'], default='mcs', help=sorthelp)
parser.add_argument('filename', nargs ='+', action = 'store')
option = parser.parse_args(sys.argv)
python argparse
edited Dec 11 '17 at 21:56
alex
2,46053166
asked Jun 15 '13 at 0:14
Yan Zhu
1,27021330
add a comment |
up vote
20
down vote
favorite
up vote
20
down vote
favorite
When I run parsePlotSens.py -s bw hehe, it says that hehe is an unrecognized argument. However, if I run parsePlotSens.py hehe -s bw, it's OK. Ideally, I would like it work for both cases.
Any tips? The following is my code:
if __name__ == '__main__' :
parser = argparse.ArgumentParser(prog='parsePlotSens');
parser.add_argument('-s', '--sort', nargs =1, action = 'store', choices = ['mcs', 'bw'], default='mcs', help=sorthelp)
parser.add_argument('filename', nargs ='+', action = 'store')
option = parser.parse_args(sys.argv)
python argparse
edited Dec 11 '17 at 21:56
alex
2,46053166
asked Jun 15 '13 at 0:14
Yan Zhu
1,27021330
When I run parsePlotSens.py -s bw hehe, it says that hehe is an unrecognized argument. However, if I run parsePlotSens.py hehe -s bw, it's OK. Ideally, I would like it work for both cases.
Any tips? The following is my code:
if __name__ == '__main__' :
parser = argparse.ArgumentParser(prog='parsePlotSens');
parser.add_argument('-s', '--sort', nargs =1, action = 'store', choices = ['mcs', 'bw'], default='mcs', help=sorthelp)
parser.add_argument('filename', nargs ='+', action = 'store')
option = parser.parse_args(sys.argv)
python argparse
python argparse
edited Dec 11 '17 at 21:56
alex
2,46053166
asked Jun 15 '13 at 0:14
Yan Zhu
1,27021330
edited Dec 11 '17 at 21:56
alex
2,46053166
asked Jun 15 '13 at 0:14
Yan Zhu
1,27021330
edited Dec 11 '17 at 21:56
alex
2,46053166
edited Dec 11 '17 at 21:56
alex
2,46053166
edited Dec 11 '17 at 21:56
alex
2,46053166
2,46053166
asked Jun 15 '13 at 0:14
Yan Zhu
1,27021330
asked Jun 15 '13 at 0:14
Yan Zhu
1,27021330
asked Jun 15 '13 at 0:14
Yan Zhu
1,27021330
1,27021330
add a comment |
add a comment |
4 Answers
4
active
oldest
votes
up vote
37
down vote
accepted
Do not pass sys.argv as an argument to parse_args. Just use
option = parser.parse_args()
If you do pass sys.argv to parse_args, then the path or name of the script itself is the first item in sys.argv and thus becomes the value of option.filename. The hehe then becomes an unknown argument.
If you omit sys.argv then parse_args parses sys.argv as expected.
answered Jun 15 '13 at 0:35
unutbu
539k9911541222
11
Alternatively you can call parser.parse_args(sys.argv[1:]). Internally argparse does just that.
– MarioVilas
Dec 14 '13 at 1:54
add a comment |
up vote
5
down vote
Also, as a complement to unutbu's answer, storing the arguments in a dictionary this way makes the tests easy:
args = vars(parser.parse_args())
print args
Prints the dictionary:
{'sort': ['bw'], 'filename': ['hehe']}
Like :
if args['sort'] == 'bw':
# code here
...
answered Jun 15 '13 at 0:24
Gauthier Boaglio
7,68523567
add a comment |
up vote
4
down vote
You can get around this by allowing unknown arguments
Replace
args = parser.parse_args()
with
args, unknown = parser.parse_known_args()
answered Jan 2 at 7:58
FacePalm
2,37922230
add a comment |
up vote
0
down vote
My situation not same with the question, but the error is same.
My situation:
- I have a remote dev(SFTP) with windows pycharm, and upload to run with linux.
the python command have some line break with
in my bash file, like
python args_config.py
--arg1="hello"
--arg2="world"
and raise a python argparse: unrecognized arguments args not found error.
the problem is the bash file line breaking is different in windows and linux,
just setting with pycharm File -> Line Separators -> LF - Unix and OS X (n)
upload to linux and run bash file, it works!
answered Nov 10 at 8:56
Colin Wang
15124
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
37
down vote
accepted
Do not pass sys.argv as an argument to parse_args. Just use
option = parser.parse_args()
If you do pass sys.argv to parse_args, then the path or name of the script itself is the first item in sys.argv and thus becomes the value of option.filename. The hehe then becomes an unknown argument.
If you omit sys.argv then parse_args parses sys.argv as expected.
answered Jun 15 '13 at 0:35
unutbu
539k9911541222
11
Alternatively you can call parser.parse_args(sys.argv[1:]). Internally argparse does just that.
– MarioVilas
Dec 14 '13 at 1:54
add a comment |
up vote
37
down vote
accepted
Do not pass sys.argv as an argument to parse_args. Just use
option = parser.parse_args()
If you do pass sys.argv to parse_args, then the path or name of the script itself is the first item in sys.argv and thus becomes the value of option.filename. The hehe then becomes an unknown argument.
If you omit sys.argv then parse_args parses sys.argv as expected.
answered Jun 15 '13 at 0:35
unutbu
539k9911541222
11
Alternatively you can call parser.parse_args(sys.argv[1:]). Internally argparse does just that.
– MarioVilas
Dec 14 '13 at 1:54
add a comment |
up vote
37
down vote
accepted
up vote
37
down vote
accepted
Do not pass sys.argv as an argument to parse_args. Just use
option = parser.parse_args()
If you do pass sys.argv to parse_args, then the path or name of the script itself is the first item in sys.argv and thus becomes the value of option.filename. The hehe then becomes an unknown argument.
If you omit sys.argv then parse_args parses sys.argv as expected.
answered Jun 15 '13 at 0:35
unutbu
539k9911541222
Do not pass sys.argv as an argument to parse_args. Just use
option = parser.parse_args()
If you do pass sys.argv to parse_args, then the path or name of the script itself is the first item in sys.argv and thus becomes the value of option.filename. The hehe then becomes an unknown argument.
If you omit sys.argv then parse_args parses sys.argv as expected.
answered Jun 15 '13 at 0:35
unutbu
539k9911541222
answered Jun 15 '13 at 0:35
unutbu
539k9911541222
answered Jun 15 '13 at 0:35
unutbu
539k9911541222
answered Jun 15 '13 at 0:35
unutbu
539k9911541222
539k9911541222
11
Alternatively you can call parser.parse_args(sys.argv[1:]). Internally argparse does just that.
– MarioVilas
Dec 14 '13 at 1:54
add a comment |
11
Alternatively you can call parser.parse_args(sys.argv[1:]). Internally argparse does just that.
– MarioVilas
Dec 14 '13 at 1:54
11
11
Alternatively you can call parser.parse_args(sys.argv[1:]). Internally argparse does just that.
– MarioVilas
Dec 14 '13 at 1:54
Alternatively you can call parser.parse_args(sys.argv[1:]). Internally argparse does just that.
– MarioVilas
Dec 14 '13 at 1:54
add a comment |
up vote
5
down vote
Also, as a complement to unutbu's answer, storing the arguments in a dictionary this way makes the tests easy:
args = vars(parser.parse_args())
print args
Prints the dictionary:
{'sort': ['bw'], 'filename': ['hehe']}
Like :
if args['sort'] == 'bw':
# code here
...
answered Jun 15 '13 at 0:24
Gauthier Boaglio
7,68523567
add a comment |
up vote
5
down vote
Also, as a complement to unutbu's answer, storing the arguments in a dictionary this way makes the tests easy:
args = vars(parser.parse_args())
print args
Prints the dictionary:
{'sort': ['bw'], 'filename': ['hehe']}
Like :
if args['sort'] == 'bw':
# code here
...
answered Jun 15 '13 at 0:24
Gauthier Boaglio
7,68523567
add a comment |
up vote
5
down vote
up vote
5
down vote
Also, as a complement to unutbu's answer, storing the arguments in a dictionary this way makes the tests easy:
args = vars(parser.parse_args())
print args
Prints the dictionary:
{'sort': ['bw'], 'filename': ['hehe']}
Like :
if args['sort'] == 'bw':
# code here
...
answered Jun 15 '13 at 0:24
Gauthier Boaglio
7,68523567
Also, as a complement to unutbu's answer, storing the arguments in a dictionary this way makes the tests easy:
args = vars(parser.parse_args())
print args
Prints the dictionary:
{'sort': ['bw'], 'filename': ['hehe']}
Like :
if args['sort'] == 'bw':
# code here
...
answered Jun 15 '13 at 0:24
Gauthier Boaglio
7,68523567
edited Jun 15 '13 at 0:41
answered Jun 15 '13 at 0:24
Gauthier Boaglio
7,68523567
answered Jun 15 '13 at 0:24
Gauthier Boaglio
7,68523567
answered Jun 15 '13 at 0:24
Gauthier Boaglio
7,68523567
7,68523567
add a comment |
add a comment |
up vote
4
down vote
You can get around this by allowing unknown arguments
Replace
args = parser.parse_args()
with
args, unknown = parser.parse_known_args()
answered Jan 2 at 7:58
FacePalm
2,37922230
add a comment |
up vote
4
down vote
You can get around this by allowing unknown arguments
Replace
args = parser.parse_args()
with
args, unknown = parser.parse_known_args()
answered Jan 2 at 7:58
FacePalm
2,37922230
add a comment |
up vote
4
down vote
up vote
4
down vote
You can get around this by allowing unknown arguments
Replace
args = parser.parse_args()
with
args, unknown = parser.parse_known_args()
answered Jan 2 at 7:58
FacePalm
2,37922230
You can get around this by allowing unknown arguments
Replace
args = parser.parse_args()
with
args, unknown = parser.parse_known_args()
answered Jan 2 at 7:58
FacePalm
2,37922230
answered Jan 2 at 7:58
FacePalm
2,37922230
answered Jan 2 at 7:58
FacePalm
2,37922230
answered Jan 2 at 7:58
FacePalm
2,37922230
2,37922230
add a comment |
add a comment |
up vote
0
down vote
My situation not same with the question, but the error is same.
My situation:
- I have a remote dev(SFTP) with windows pycharm, and upload to run with linux.
the python command have some line break with
in my bash file, like
python args_config.py
--arg1="hello"
--arg2="world"
and raise a python argparse: unrecognized arguments args not found error.
the problem is the bash file line breaking is different in windows and linux,
just setting with pycharm File -> Line Separators -> LF - Unix and OS X (n)
upload to linux and run bash file, it works!
answered Nov 10 at 8:56
Colin Wang
15124
add a comment |
up vote
0
down vote
My situation not same with the question, but the error is same.
My situation:
- I have a remote dev(SFTP) with windows pycharm, and upload to run with linux.
the python command have some line break with
in my bash file, like
python args_config.py
--arg1="hello"
--arg2="world"
and raise a python argparse: unrecognized arguments args not found error.
the problem is the bash file line breaking is different in windows and linux,
just setting with pycharm File -> Line Separators -> LF - Unix and OS X (n)
upload to linux and run bash file, it works!
answered Nov 10 at 8:56
Colin Wang
15124
add a comment |
up vote
0
down vote
up vote
0
down vote
My situation not same with the question, but the error is same.
My situation:
- I have a remote dev(SFTP) with windows pycharm, and upload to run with linux.
the python command have some line break with
in my bash file, like
python args_config.py
--arg1="hello"
--arg2="world"
and raise a python argparse: unrecognized arguments args not found error.
the problem is the bash file line breaking is different in windows and linux,
just setting with pycharm File -> Line Separators -> LF - Unix and OS X (n)
upload to linux and run bash file, it works!
answered Nov 10 at 8:56
Colin Wang
15124
My situation not same with the question, but the error is same.
My situation:
- I have a remote dev(SFTP) with windows pycharm, and upload to run with linux.
the python command have some line break with
in my bash file, like
python args_config.py
--arg1="hello"
--arg2="world"
and raise a python argparse: unrecognized arguments args not found error.
the problem is the bash file line breaking is different in windows and linux,
just setting with pycharm File -> Line Separators -> LF - Unix and OS X (n)
upload to linux and run bash file, it works!
answered Nov 10 at 8:56
Colin Wang
15124
answered Nov 10 at 8:56
Colin Wang
15124
answered Nov 10 at 8:56
Colin Wang
15124
answered Nov 10 at 8:56
Colin Wang
15124
15124
add a comment |
add a comment |
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