OCaml User-Defined Type and Function Return Error
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I was writing a function with user-defined types in OCaml when I encountered an error message that I don't understand.
I'm currently using the OCaml interactive toplevel and also Visual Studio Code to write my code. The strange thing is that when I run the code in Visual Studio Code, it compiles fine but encounters the error in the interactive toplevel.
The OCaml code that I am referring to is as follows:
type loc = int;;
type id = string;;
type value =
| Num of int
| Bool of bool
| Unit
| Record of (id -> loc)
;;
type memory = (loc * value) list;;
exception NotInMemory;;
let rec memory_lookup : (memory * loc) -> value
= fun (mem, l) ->
match mem with
| -> raise NotInMemory
| hd :: tl -> (match hd with
| (x, a) -> if x = l then a else (memory_lookup (tl, l))
)
;;
The code that I wrote is basically my rudimentary attempt at implementing/emulating looking up memory and returning corresponding values.
Here's an example input:
memory1 = [ (1, Num 1) ; (2, Bool true) ; (3, Unit) ];;
Here's the expected output:
memory_lookup (memory1, 2);;
- : value = Bool true
However, here's the actual output:
Characters: 179-180:
| (x, a) -> if x = l then "a" else (memory_lookup (tl, l)))
Error: This expression has type value/1076
but an expression was expected of type value/1104
(Just for clarification: the error is regarding character a
)
Does anybody know what type value/1076
and type value/1104
mean? Also, if there is anything wrong with the code that I wrote, would anybody be kind enough to point it out?
Thank you.
error-handling ocaml valueerror
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up vote
0
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favorite
I was writing a function with user-defined types in OCaml when I encountered an error message that I don't understand.
I'm currently using the OCaml interactive toplevel and also Visual Studio Code to write my code. The strange thing is that when I run the code in Visual Studio Code, it compiles fine but encounters the error in the interactive toplevel.
The OCaml code that I am referring to is as follows:
type loc = int;;
type id = string;;
type value =
| Num of int
| Bool of bool
| Unit
| Record of (id -> loc)
;;
type memory = (loc * value) list;;
exception NotInMemory;;
let rec memory_lookup : (memory * loc) -> value
= fun (mem, l) ->
match mem with
| -> raise NotInMemory
| hd :: tl -> (match hd with
| (x, a) -> if x = l then a else (memory_lookup (tl, l))
)
;;
The code that I wrote is basically my rudimentary attempt at implementing/emulating looking up memory and returning corresponding values.
Here's an example input:
memory1 = [ (1, Num 1) ; (2, Bool true) ; (3, Unit) ];;
Here's the expected output:
memory_lookup (memory1, 2);;
- : value = Bool true
However, here's the actual output:
Characters: 179-180:
| (x, a) -> if x = l then "a" else (memory_lookup (tl, l)))
Error: This expression has type value/1076
but an expression was expected of type value/1104
(Just for clarification: the error is regarding character a
)
Does anybody know what type value/1076
and type value/1104
mean? Also, if there is anything wrong with the code that I wrote, would anybody be kind enough to point it out?
Thank you.
error-handling ocaml valueerror
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I was writing a function with user-defined types in OCaml when I encountered an error message that I don't understand.
I'm currently using the OCaml interactive toplevel and also Visual Studio Code to write my code. The strange thing is that when I run the code in Visual Studio Code, it compiles fine but encounters the error in the interactive toplevel.
The OCaml code that I am referring to is as follows:
type loc = int;;
type id = string;;
type value =
| Num of int
| Bool of bool
| Unit
| Record of (id -> loc)
;;
type memory = (loc * value) list;;
exception NotInMemory;;
let rec memory_lookup : (memory * loc) -> value
= fun (mem, l) ->
match mem with
| -> raise NotInMemory
| hd :: tl -> (match hd with
| (x, a) -> if x = l then a else (memory_lookup (tl, l))
)
;;
The code that I wrote is basically my rudimentary attempt at implementing/emulating looking up memory and returning corresponding values.
Here's an example input:
memory1 = [ (1, Num 1) ; (2, Bool true) ; (3, Unit) ];;
Here's the expected output:
memory_lookup (memory1, 2);;
- : value = Bool true
However, here's the actual output:
Characters: 179-180:
| (x, a) -> if x = l then "a" else (memory_lookup (tl, l)))
Error: This expression has type value/1076
but an expression was expected of type value/1104
(Just for clarification: the error is regarding character a
)
Does anybody know what type value/1076
and type value/1104
mean? Also, if there is anything wrong with the code that I wrote, would anybody be kind enough to point it out?
Thank you.
error-handling ocaml valueerror
I was writing a function with user-defined types in OCaml when I encountered an error message that I don't understand.
I'm currently using the OCaml interactive toplevel and also Visual Studio Code to write my code. The strange thing is that when I run the code in Visual Studio Code, it compiles fine but encounters the error in the interactive toplevel.
The OCaml code that I am referring to is as follows:
type loc = int;;
type id = string;;
type value =
| Num of int
| Bool of bool
| Unit
| Record of (id -> loc)
;;
type memory = (loc * value) list;;
exception NotInMemory;;
let rec memory_lookup : (memory * loc) -> value
= fun (mem, l) ->
match mem with
| -> raise NotInMemory
| hd :: tl -> (match hd with
| (x, a) -> if x = l then a else (memory_lookup (tl, l))
)
;;
The code that I wrote is basically my rudimentary attempt at implementing/emulating looking up memory and returning corresponding values.
Here's an example input:
memory1 = [ (1, Num 1) ; (2, Bool true) ; (3, Unit) ];;
Here's the expected output:
memory_lookup (memory1, 2);;
- : value = Bool true
However, here's the actual output:
Characters: 179-180:
| (x, a) -> if x = l then "a" else (memory_lookup (tl, l)))
Error: This expression has type value/1076
but an expression was expected of type value/1104
(Just for clarification: the error is regarding character a
)
Does anybody know what type value/1076
and type value/1104
mean? Also, if there is anything wrong with the code that I wrote, would anybody be kind enough to point it out?
Thank you.
error-handling ocaml valueerror
error-handling ocaml valueerror
asked Nov 8 at 10:39
Sean
306212
306212
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add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
This kind of error happens in the toplevel when a type is defined multiple times, and some values of the old type are left in scope. A simple example is
type t = A
let x = A;;
type t = A
let y = A;;
x = y;;
Error: This expression has type t/1012 but an expression was expected of type
t/1009
The numerical part after the type name in value/1076
is a binding time for the type value
. This binding time is used as a last resort to differentiate between two different types that happens to have the same name. Thus
Error: This expression has type value/1076
but an expression was expected of type value/1104
means that the value memory1
was defined with a type value
defined at time 1076
, whereas the function memory_lookup
expected values of the type value
defined at a later date (aka at time 1104
). The binding times are a bit arbitrary , so they may be replaced by simply value/1
and value/2
in OCaml 4.08 .
Oh wow thank you! I didn't know about this before.
– Sean
Nov 8 at 12:59
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
This kind of error happens in the toplevel when a type is defined multiple times, and some values of the old type are left in scope. A simple example is
type t = A
let x = A;;
type t = A
let y = A;;
x = y;;
Error: This expression has type t/1012 but an expression was expected of type
t/1009
The numerical part after the type name in value/1076
is a binding time for the type value
. This binding time is used as a last resort to differentiate between two different types that happens to have the same name. Thus
Error: This expression has type value/1076
but an expression was expected of type value/1104
means that the value memory1
was defined with a type value
defined at time 1076
, whereas the function memory_lookup
expected values of the type value
defined at a later date (aka at time 1104
). The binding times are a bit arbitrary , so they may be replaced by simply value/1
and value/2
in OCaml 4.08 .
Oh wow thank you! I didn't know about this before.
– Sean
Nov 8 at 12:59
add a comment |
up vote
1
down vote
accepted
This kind of error happens in the toplevel when a type is defined multiple times, and some values of the old type are left in scope. A simple example is
type t = A
let x = A;;
type t = A
let y = A;;
x = y;;
Error: This expression has type t/1012 but an expression was expected of type
t/1009
The numerical part after the type name in value/1076
is a binding time for the type value
. This binding time is used as a last resort to differentiate between two different types that happens to have the same name. Thus
Error: This expression has type value/1076
but an expression was expected of type value/1104
means that the value memory1
was defined with a type value
defined at time 1076
, whereas the function memory_lookup
expected values of the type value
defined at a later date (aka at time 1104
). The binding times are a bit arbitrary , so they may be replaced by simply value/1
and value/2
in OCaml 4.08 .
Oh wow thank you! I didn't know about this before.
– Sean
Nov 8 at 12:59
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
This kind of error happens in the toplevel when a type is defined multiple times, and some values of the old type are left in scope. A simple example is
type t = A
let x = A;;
type t = A
let y = A;;
x = y;;
Error: This expression has type t/1012 but an expression was expected of type
t/1009
The numerical part after the type name in value/1076
is a binding time for the type value
. This binding time is used as a last resort to differentiate between two different types that happens to have the same name. Thus
Error: This expression has type value/1076
but an expression was expected of type value/1104
means that the value memory1
was defined with a type value
defined at time 1076
, whereas the function memory_lookup
expected values of the type value
defined at a later date (aka at time 1104
). The binding times are a bit arbitrary , so they may be replaced by simply value/1
and value/2
in OCaml 4.08 .
This kind of error happens in the toplevel when a type is defined multiple times, and some values of the old type are left in scope. A simple example is
type t = A
let x = A;;
type t = A
let y = A;;
x = y;;
Error: This expression has type t/1012 but an expression was expected of type
t/1009
The numerical part after the type name in value/1076
is a binding time for the type value
. This binding time is used as a last resort to differentiate between two different types that happens to have the same name. Thus
Error: This expression has type value/1076
but an expression was expected of type value/1104
means that the value memory1
was defined with a type value
defined at time 1076
, whereas the function memory_lookup
expected values of the type value
defined at a later date (aka at time 1104
). The binding times are a bit arbitrary , so they may be replaced by simply value/1
and value/2
in OCaml 4.08 .
answered Nov 8 at 11:16
octachron
3,8381312
3,8381312
Oh wow thank you! I didn't know about this before.
– Sean
Nov 8 at 12:59
add a comment |
Oh wow thank you! I didn't know about this before.
– Sean
Nov 8 at 12:59
Oh wow thank you! I didn't know about this before.
– Sean
Nov 8 at 12:59
Oh wow thank you! I didn't know about this before.
– Sean
Nov 8 at 12:59
add a comment |
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