C programming problem pointers and arrays 2d











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Q2: Implelment the follwoing function ArrPrintMatrix(char *(p)[7]) which prints the content of the matrix[m][7] ={"SHAHBAZ","AYAZ"} in to 3x3 Matrix



Sample Output




S H A
H B A
Z A Y ..


My question is : here is code only problem i am getting is a space after one name is completed..how to remove that space . I have this question in my assignments , that have to be submitted on sunday (11-11-18)..
My code is:



#include<stdio.h>
int main()
{
void ArrPrintMatrix(char *p);//function declaration
char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation
ArrPrintMatrix(&matrix[0][0]);//calling function with base address

}

void ArrPrintMatrix(char *p)
{
int i;
for(i=0;i<16;i++)
{
if(i>=9)//since 3 by 3 matrix is required
break;
if(i==3||i==6||i==9)//changing line since 3 by 3 matrix is needed
printf("n");
printf("%c ",*(p+i));//prininting chracters

}
}









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  • Nasty question. It tells you to write a function like this ArrPrintMatrix(char *(p)[7]) and gives you a string that's 8 characters long ("SHAHBAZ" plus a terminating zero).
    – Tim Randall
    Nov 9 at 16:42












  • thank you so much for quick reply . I donot understand hot to use ArrPrintMatrix(char *(p)[7]) and to pass it to function can you please please help me ....please
    – Âftãb Bãlôçh
    Nov 9 at 16:46















up vote
1
down vote

favorite
1












Q2: Implelment the follwoing function ArrPrintMatrix(char *(p)[7]) which prints the content of the matrix[m][7] ={"SHAHBAZ","AYAZ"} in to 3x3 Matrix



Sample Output




S H A
H B A
Z A Y ..


My question is : here is code only problem i am getting is a space after one name is completed..how to remove that space . I have this question in my assignments , that have to be submitted on sunday (11-11-18)..
My code is:



#include<stdio.h>
int main()
{
void ArrPrintMatrix(char *p);//function declaration
char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation
ArrPrintMatrix(&matrix[0][0]);//calling function with base address

}

void ArrPrintMatrix(char *p)
{
int i;
for(i=0;i<16;i++)
{
if(i>=9)//since 3 by 3 matrix is required
break;
if(i==3||i==6||i==9)//changing line since 3 by 3 matrix is needed
printf("n");
printf("%c ",*(p+i));//prininting chracters

}
}









share|improve this question
























  • Nasty question. It tells you to write a function like this ArrPrintMatrix(char *(p)[7]) and gives you a string that's 8 characters long ("SHAHBAZ" plus a terminating zero).
    – Tim Randall
    Nov 9 at 16:42












  • thank you so much for quick reply . I donot understand hot to use ArrPrintMatrix(char *(p)[7]) and to pass it to function can you please please help me ....please
    – Âftãb Bãlôçh
    Nov 9 at 16:46













up vote
1
down vote

favorite
1









up vote
1
down vote

favorite
1






1





Q2: Implelment the follwoing function ArrPrintMatrix(char *(p)[7]) which prints the content of the matrix[m][7] ={"SHAHBAZ","AYAZ"} in to 3x3 Matrix



Sample Output




S H A
H B A
Z A Y ..


My question is : here is code only problem i am getting is a space after one name is completed..how to remove that space . I have this question in my assignments , that have to be submitted on sunday (11-11-18)..
My code is:



#include<stdio.h>
int main()
{
void ArrPrintMatrix(char *p);//function declaration
char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation
ArrPrintMatrix(&matrix[0][0]);//calling function with base address

}

void ArrPrintMatrix(char *p)
{
int i;
for(i=0;i<16;i++)
{
if(i>=9)//since 3 by 3 matrix is required
break;
if(i==3||i==6||i==9)//changing line since 3 by 3 matrix is needed
printf("n");
printf("%c ",*(p+i));//prininting chracters

}
}









share|improve this question















Q2: Implelment the follwoing function ArrPrintMatrix(char *(p)[7]) which prints the content of the matrix[m][7] ={"SHAHBAZ","AYAZ"} in to 3x3 Matrix



Sample Output




S H A
H B A
Z A Y ..


My question is : here is code only problem i am getting is a space after one name is completed..how to remove that space . I have this question in my assignments , that have to be submitted on sunday (11-11-18)..
My code is:



#include<stdio.h>
int main()
{
void ArrPrintMatrix(char *p);//function declaration
char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation
ArrPrintMatrix(&matrix[0][0]);//calling function with base address

}

void ArrPrintMatrix(char *p)
{
int i;
for(i=0;i<16;i++)
{
if(i>=9)//since 3 by 3 matrix is required
break;
if(i==3||i==6||i==9)//changing line since 3 by 3 matrix is needed
printf("n");
printf("%c ",*(p+i));//prininting chracters

}
}






c function pointers multidimensional-array






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edited Nov 9 at 16:30









Fiddling Bits

7,11021938




7,11021938










asked Nov 9 at 16:28









Âftãb Bãlôçh

47




47












  • Nasty question. It tells you to write a function like this ArrPrintMatrix(char *(p)[7]) and gives you a string that's 8 characters long ("SHAHBAZ" plus a terminating zero).
    – Tim Randall
    Nov 9 at 16:42












  • thank you so much for quick reply . I donot understand hot to use ArrPrintMatrix(char *(p)[7]) and to pass it to function can you please please help me ....please
    – Âftãb Bãlôçh
    Nov 9 at 16:46


















  • Nasty question. It tells you to write a function like this ArrPrintMatrix(char *(p)[7]) and gives you a string that's 8 characters long ("SHAHBAZ" plus a terminating zero).
    – Tim Randall
    Nov 9 at 16:42












  • thank you so much for quick reply . I donot understand hot to use ArrPrintMatrix(char *(p)[7]) and to pass it to function can you please please help me ....please
    – Âftãb Bãlôçh
    Nov 9 at 16:46
















Nasty question. It tells you to write a function like this ArrPrintMatrix(char *(p)[7]) and gives you a string that's 8 characters long ("SHAHBAZ" plus a terminating zero).
– Tim Randall
Nov 9 at 16:42






Nasty question. It tells you to write a function like this ArrPrintMatrix(char *(p)[7]) and gives you a string that's 8 characters long ("SHAHBAZ" plus a terminating zero).
– Tim Randall
Nov 9 at 16:42














thank you so much for quick reply . I donot understand hot to use ArrPrintMatrix(char *(p)[7]) and to pass it to function can you please please help me ....please
– Âftãb Bãlôçh
Nov 9 at 16:46




thank you so much for quick reply . I donot understand hot to use ArrPrintMatrix(char *(p)[7]) and to pass it to function can you please please help me ....please
– Âftãb Bãlôçh
Nov 9 at 16:46












3 Answers
3






active

oldest

votes

















up vote
0
down vote



accepted










As a follow-on to my other answer, if you do use my logic to skip over the '' that terminates the strings, you will need to use a different variable to keep track of how many characters you've actually printed, and just let i keep track of where you are in the input string(s). Like so:



#include<stdio.h>
int main()
{
void ArrPrintMatrix(char *p);//function declaration
char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation
ArrPrintMatrix(&matrix[0][0]);//calling function with base address

}

void ArrPrintMatrix(char *p)
{
int i, j;
for(i=0, j=0;i<16;i++)
{
if(j>=9)//since 3 by 3 matrix is required
break;
if(j==3||j==6||j==9)//changing line since 3 by 3 matrix is needed
printf("n");
if (*(p+i)==0) continue; //don't try to print the trailing ''
printf("%c ",*(p+i));//prininting chracters
j++; //increment counter of characters actually printed

}
}


Output:



S H A 
H B A
Z A Y


Note the use of the j variable, and how it is incremented with j++ only after actually printing a character.






share|improve this answer





















  • if (*(p+i)==0) continue; //don't try to print the trailing '' I donot understand this point , i mean why donot i say thay if *(p+j)=='0'??
    – Âftãb Bãlôçh
    Nov 9 at 17:06












  • '0' is very different from 0; '' on the other hand equates to 0
    – landru27
    Nov 9 at 17:13










  • you could use either if (*(p+i)==0) or if (*(p+i)==''), but not if *(p+j)=='0', which is what you have in your comment
    – landru27
    Nov 9 at 17:15










  • ok got it thank you
    – Âftãb Bãlôçh
    Nov 9 at 17:20










  • can you help me understand this code please your explanation is tremendous #include<stdio.h> int main() { void ArrPrintMatrix(char (*p)[8]);//function declaration char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation ArrPrintMatrix(matrix);//calling function with base address } void ArrPrintMatrix(char (*p)[8]) { int i = 0, j = 0, k = 0; while (k != 9) { if (p[i][j] == '') { ++i; j = 0; } printf("%c ", p[i][j++]); ++k; if(k%3 == 0) printf("n"); } }
    – Âftãb Bãlôçh
    Nov 9 at 17:21




















up vote
1
down vote













You should use char (*p)[8] not char* p



The following code could wrok:



#include<stdio.h>
int main()
{
void ArrPrintMatrix(char (*p)[8]);//function declaration
char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation
ArrPrintMatrix(matrix);//calling function with base address

}
void ArrPrintMatrix(char (*p)[8])
{
// i will point to one of the strings in the set of strings
// j will point into the string we are inspecting
// k will count how many characters we have printed
int i = 0, j = 0, k = 0;

// we only need to print the first 9 printable characters we find
while (k != 9)
{
// if we have reached the end of an input string (the null-terminator),
// then move on to the next element in the array, and reset
// the string pointer to the beginning of the new string
if (p[i][j] == '') {
++i;
j = 0;
}

// print the character we are now pointing at,
// and increment the string pointer
printf("%c ", p[i][j++]);

// keep count of how many characters we have printed
++k;

// if k is divisible by 3, start a new row
if(k%3 == 0)
printf("n");
}
}





share|improve this answer























  • perfectly done i must appreciate bou unfortunately i don't understand how this code is working ..I also have exams on monday :(
    – Âftãb Bãlôçh
    Nov 9 at 16:59










  • can you please tech me your code by commenting or something like dry run..I would be thankfull
    – Âftãb Bãlôçh
    Nov 9 at 17:39


















up vote
0
down vote













What you are missing is that there is a trailing '' at the end of SHAHBAZ, which you are also "printing", but because '' does not have a character representation, you are seeing what looks like an 'extra' space.



Here is the smallest change I can think of to address this exact problem; add:



if (*(p+i)==0) continue; //don't try to print the trailing ''


just above your existing line:



printf("%c ",*(p+i));//prininting chracters


Output:



S H A 
H B A
Z A


There are other things I would do differently than how you are doing them, but this addresses your exact question, using your coding style.






share|improve this answer





















  • oh man !!! Thank you so much ..... THANKS DUDE LOVE YOU
    – Âftãb Bãlôçh
    Nov 9 at 16:53











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3 Answers
3






active

oldest

votes








3 Answers
3






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
0
down vote



accepted










As a follow-on to my other answer, if you do use my logic to skip over the '' that terminates the strings, you will need to use a different variable to keep track of how many characters you've actually printed, and just let i keep track of where you are in the input string(s). Like so:



#include<stdio.h>
int main()
{
void ArrPrintMatrix(char *p);//function declaration
char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation
ArrPrintMatrix(&matrix[0][0]);//calling function with base address

}

void ArrPrintMatrix(char *p)
{
int i, j;
for(i=0, j=0;i<16;i++)
{
if(j>=9)//since 3 by 3 matrix is required
break;
if(j==3||j==6||j==9)//changing line since 3 by 3 matrix is needed
printf("n");
if (*(p+i)==0) continue; //don't try to print the trailing ''
printf("%c ",*(p+i));//prininting chracters
j++; //increment counter of characters actually printed

}
}


Output:



S H A 
H B A
Z A Y


Note the use of the j variable, and how it is incremented with j++ only after actually printing a character.






share|improve this answer





















  • if (*(p+i)==0) continue; //don't try to print the trailing '' I donot understand this point , i mean why donot i say thay if *(p+j)=='0'??
    – Âftãb Bãlôçh
    Nov 9 at 17:06












  • '0' is very different from 0; '' on the other hand equates to 0
    – landru27
    Nov 9 at 17:13










  • you could use either if (*(p+i)==0) or if (*(p+i)==''), but not if *(p+j)=='0', which is what you have in your comment
    – landru27
    Nov 9 at 17:15










  • ok got it thank you
    – Âftãb Bãlôçh
    Nov 9 at 17:20










  • can you help me understand this code please your explanation is tremendous #include<stdio.h> int main() { void ArrPrintMatrix(char (*p)[8]);//function declaration char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation ArrPrintMatrix(matrix);//calling function with base address } void ArrPrintMatrix(char (*p)[8]) { int i = 0, j = 0, k = 0; while (k != 9) { if (p[i][j] == '') { ++i; j = 0; } printf("%c ", p[i][j++]); ++k; if(k%3 == 0) printf("n"); } }
    – Âftãb Bãlôçh
    Nov 9 at 17:21

















up vote
0
down vote



accepted










As a follow-on to my other answer, if you do use my logic to skip over the '' that terminates the strings, you will need to use a different variable to keep track of how many characters you've actually printed, and just let i keep track of where you are in the input string(s). Like so:



#include<stdio.h>
int main()
{
void ArrPrintMatrix(char *p);//function declaration
char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation
ArrPrintMatrix(&matrix[0][0]);//calling function with base address

}

void ArrPrintMatrix(char *p)
{
int i, j;
for(i=0, j=0;i<16;i++)
{
if(j>=9)//since 3 by 3 matrix is required
break;
if(j==3||j==6||j==9)//changing line since 3 by 3 matrix is needed
printf("n");
if (*(p+i)==0) continue; //don't try to print the trailing ''
printf("%c ",*(p+i));//prininting chracters
j++; //increment counter of characters actually printed

}
}


Output:



S H A 
H B A
Z A Y


Note the use of the j variable, and how it is incremented with j++ only after actually printing a character.






share|improve this answer





















  • if (*(p+i)==0) continue; //don't try to print the trailing '' I donot understand this point , i mean why donot i say thay if *(p+j)=='0'??
    – Âftãb Bãlôçh
    Nov 9 at 17:06












  • '0' is very different from 0; '' on the other hand equates to 0
    – landru27
    Nov 9 at 17:13










  • you could use either if (*(p+i)==0) or if (*(p+i)==''), but not if *(p+j)=='0', which is what you have in your comment
    – landru27
    Nov 9 at 17:15










  • ok got it thank you
    – Âftãb Bãlôçh
    Nov 9 at 17:20










  • can you help me understand this code please your explanation is tremendous #include<stdio.h> int main() { void ArrPrintMatrix(char (*p)[8]);//function declaration char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation ArrPrintMatrix(matrix);//calling function with base address } void ArrPrintMatrix(char (*p)[8]) { int i = 0, j = 0, k = 0; while (k != 9) { if (p[i][j] == '') { ++i; j = 0; } printf("%c ", p[i][j++]); ++k; if(k%3 == 0) printf("n"); } }
    – Âftãb Bãlôçh
    Nov 9 at 17:21















up vote
0
down vote



accepted







up vote
0
down vote



accepted






As a follow-on to my other answer, if you do use my logic to skip over the '' that terminates the strings, you will need to use a different variable to keep track of how many characters you've actually printed, and just let i keep track of where you are in the input string(s). Like so:



#include<stdio.h>
int main()
{
void ArrPrintMatrix(char *p);//function declaration
char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation
ArrPrintMatrix(&matrix[0][0]);//calling function with base address

}

void ArrPrintMatrix(char *p)
{
int i, j;
for(i=0, j=0;i<16;i++)
{
if(j>=9)//since 3 by 3 matrix is required
break;
if(j==3||j==6||j==9)//changing line since 3 by 3 matrix is needed
printf("n");
if (*(p+i)==0) continue; //don't try to print the trailing ''
printf("%c ",*(p+i));//prininting chracters
j++; //increment counter of characters actually printed

}
}


Output:



S H A 
H B A
Z A Y


Note the use of the j variable, and how it is incremented with j++ only after actually printing a character.






share|improve this answer












As a follow-on to my other answer, if you do use my logic to skip over the '' that terminates the strings, you will need to use a different variable to keep track of how many characters you've actually printed, and just let i keep track of where you are in the input string(s). Like so:



#include<stdio.h>
int main()
{
void ArrPrintMatrix(char *p);//function declaration
char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation
ArrPrintMatrix(&matrix[0][0]);//calling function with base address

}

void ArrPrintMatrix(char *p)
{
int i, j;
for(i=0, j=0;i<16;i++)
{
if(j>=9)//since 3 by 3 matrix is required
break;
if(j==3||j==6||j==9)//changing line since 3 by 3 matrix is needed
printf("n");
if (*(p+i)==0) continue; //don't try to print the trailing ''
printf("%c ",*(p+i));//prininting chracters
j++; //increment counter of characters actually printed

}
}


Output:



S H A 
H B A
Z A Y


Note the use of the j variable, and how it is incremented with j++ only after actually printing a character.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 9 at 16:55









landru27

752213




752213












  • if (*(p+i)==0) continue; //don't try to print the trailing '' I donot understand this point , i mean why donot i say thay if *(p+j)=='0'??
    – Âftãb Bãlôçh
    Nov 9 at 17:06












  • '0' is very different from 0; '' on the other hand equates to 0
    – landru27
    Nov 9 at 17:13










  • you could use either if (*(p+i)==0) or if (*(p+i)==''), but not if *(p+j)=='0', which is what you have in your comment
    – landru27
    Nov 9 at 17:15










  • ok got it thank you
    – Âftãb Bãlôçh
    Nov 9 at 17:20










  • can you help me understand this code please your explanation is tremendous #include<stdio.h> int main() { void ArrPrintMatrix(char (*p)[8]);//function declaration char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation ArrPrintMatrix(matrix);//calling function with base address } void ArrPrintMatrix(char (*p)[8]) { int i = 0, j = 0, k = 0; while (k != 9) { if (p[i][j] == '') { ++i; j = 0; } printf("%c ", p[i][j++]); ++k; if(k%3 == 0) printf("n"); } }
    – Âftãb Bãlôçh
    Nov 9 at 17:21




















  • if (*(p+i)==0) continue; //don't try to print the trailing '' I donot understand this point , i mean why donot i say thay if *(p+j)=='0'??
    – Âftãb Bãlôçh
    Nov 9 at 17:06












  • '0' is very different from 0; '' on the other hand equates to 0
    – landru27
    Nov 9 at 17:13










  • you could use either if (*(p+i)==0) or if (*(p+i)==''), but not if *(p+j)=='0', which is what you have in your comment
    – landru27
    Nov 9 at 17:15










  • ok got it thank you
    – Âftãb Bãlôçh
    Nov 9 at 17:20










  • can you help me understand this code please your explanation is tremendous #include<stdio.h> int main() { void ArrPrintMatrix(char (*p)[8]);//function declaration char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation ArrPrintMatrix(matrix);//calling function with base address } void ArrPrintMatrix(char (*p)[8]) { int i = 0, j = 0, k = 0; while (k != 9) { if (p[i][j] == '') { ++i; j = 0; } printf("%c ", p[i][j++]); ++k; if(k%3 == 0) printf("n"); } }
    – Âftãb Bãlôçh
    Nov 9 at 17:21


















if (*(p+i)==0) continue; //don't try to print the trailing '' I donot understand this point , i mean why donot i say thay if *(p+j)=='0'??
– Âftãb Bãlôçh
Nov 9 at 17:06






if (*(p+i)==0) continue; //don't try to print the trailing '' I donot understand this point , i mean why donot i say thay if *(p+j)=='0'??
– Âftãb Bãlôçh
Nov 9 at 17:06














'0' is very different from 0; '' on the other hand equates to 0
– landru27
Nov 9 at 17:13




'0' is very different from 0; '' on the other hand equates to 0
– landru27
Nov 9 at 17:13












you could use either if (*(p+i)==0) or if (*(p+i)==''), but not if *(p+j)=='0', which is what you have in your comment
– landru27
Nov 9 at 17:15




you could use either if (*(p+i)==0) or if (*(p+i)==''), but not if *(p+j)=='0', which is what you have in your comment
– landru27
Nov 9 at 17:15












ok got it thank you
– Âftãb Bãlôçh
Nov 9 at 17:20




ok got it thank you
– Âftãb Bãlôçh
Nov 9 at 17:20












can you help me understand this code please your explanation is tremendous #include<stdio.h> int main() { void ArrPrintMatrix(char (*p)[8]);//function declaration char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation ArrPrintMatrix(matrix);//calling function with base address } void ArrPrintMatrix(char (*p)[8]) { int i = 0, j = 0, k = 0; while (k != 9) { if (p[i][j] == '') { ++i; j = 0; } printf("%c ", p[i][j++]); ++k; if(k%3 == 0) printf("n"); } }
– Âftãb Bãlôçh
Nov 9 at 17:21






can you help me understand this code please your explanation is tremendous #include<stdio.h> int main() { void ArrPrintMatrix(char (*p)[8]);//function declaration char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation ArrPrintMatrix(matrix);//calling function with base address } void ArrPrintMatrix(char (*p)[8]) { int i = 0, j = 0, k = 0; while (k != 9) { if (p[i][j] == '') { ++i; j = 0; } printf("%c ", p[i][j++]); ++k; if(k%3 == 0) printf("n"); } }
– Âftãb Bãlôçh
Nov 9 at 17:21














up vote
1
down vote













You should use char (*p)[8] not char* p



The following code could wrok:



#include<stdio.h>
int main()
{
void ArrPrintMatrix(char (*p)[8]);//function declaration
char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation
ArrPrintMatrix(matrix);//calling function with base address

}
void ArrPrintMatrix(char (*p)[8])
{
// i will point to one of the strings in the set of strings
// j will point into the string we are inspecting
// k will count how many characters we have printed
int i = 0, j = 0, k = 0;

// we only need to print the first 9 printable characters we find
while (k != 9)
{
// if we have reached the end of an input string (the null-terminator),
// then move on to the next element in the array, and reset
// the string pointer to the beginning of the new string
if (p[i][j] == '') {
++i;
j = 0;
}

// print the character we are now pointing at,
// and increment the string pointer
printf("%c ", p[i][j++]);

// keep count of how many characters we have printed
++k;

// if k is divisible by 3, start a new row
if(k%3 == 0)
printf("n");
}
}





share|improve this answer























  • perfectly done i must appreciate bou unfortunately i don't understand how this code is working ..I also have exams on monday :(
    – Âftãb Bãlôçh
    Nov 9 at 16:59










  • can you please tech me your code by commenting or something like dry run..I would be thankfull
    – Âftãb Bãlôçh
    Nov 9 at 17:39















up vote
1
down vote













You should use char (*p)[8] not char* p



The following code could wrok:



#include<stdio.h>
int main()
{
void ArrPrintMatrix(char (*p)[8]);//function declaration
char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation
ArrPrintMatrix(matrix);//calling function with base address

}
void ArrPrintMatrix(char (*p)[8])
{
// i will point to one of the strings in the set of strings
// j will point into the string we are inspecting
// k will count how many characters we have printed
int i = 0, j = 0, k = 0;

// we only need to print the first 9 printable characters we find
while (k != 9)
{
// if we have reached the end of an input string (the null-terminator),
// then move on to the next element in the array, and reset
// the string pointer to the beginning of the new string
if (p[i][j] == '') {
++i;
j = 0;
}

// print the character we are now pointing at,
// and increment the string pointer
printf("%c ", p[i][j++]);

// keep count of how many characters we have printed
++k;

// if k is divisible by 3, start a new row
if(k%3 == 0)
printf("n");
}
}





share|improve this answer























  • perfectly done i must appreciate bou unfortunately i don't understand how this code is working ..I also have exams on monday :(
    – Âftãb Bãlôçh
    Nov 9 at 16:59










  • can you please tech me your code by commenting or something like dry run..I would be thankfull
    – Âftãb Bãlôçh
    Nov 9 at 17:39













up vote
1
down vote










up vote
1
down vote









You should use char (*p)[8] not char* p



The following code could wrok:



#include<stdio.h>
int main()
{
void ArrPrintMatrix(char (*p)[8]);//function declaration
char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation
ArrPrintMatrix(matrix);//calling function with base address

}
void ArrPrintMatrix(char (*p)[8])
{
// i will point to one of the strings in the set of strings
// j will point into the string we are inspecting
// k will count how many characters we have printed
int i = 0, j = 0, k = 0;

// we only need to print the first 9 printable characters we find
while (k != 9)
{
// if we have reached the end of an input string (the null-terminator),
// then move on to the next element in the array, and reset
// the string pointer to the beginning of the new string
if (p[i][j] == '') {
++i;
j = 0;
}

// print the character we are now pointing at,
// and increment the string pointer
printf("%c ", p[i][j++]);

// keep count of how many characters we have printed
++k;

// if k is divisible by 3, start a new row
if(k%3 == 0)
printf("n");
}
}





share|improve this answer














You should use char (*p)[8] not char* p



The following code could wrok:



#include<stdio.h>
int main()
{
void ArrPrintMatrix(char (*p)[8]);//function declaration
char matrix[2][8] ={"SHAHBAZ","AYAZ"};//2d array initiliation
ArrPrintMatrix(matrix);//calling function with base address

}
void ArrPrintMatrix(char (*p)[8])
{
// i will point to one of the strings in the set of strings
// j will point into the string we are inspecting
// k will count how many characters we have printed
int i = 0, j = 0, k = 0;

// we only need to print the first 9 printable characters we find
while (k != 9)
{
// if we have reached the end of an input string (the null-terminator),
// then move on to the next element in the array, and reset
// the string pointer to the beginning of the new string
if (p[i][j] == '') {
++i;
j = 0;
}

// print the character we are now pointing at,
// and increment the string pointer
printf("%c ", p[i][j++]);

// keep count of how many characters we have printed
++k;

// if k is divisible by 3, start a new row
if(k%3 == 0)
printf("n");
}
}






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 9 at 19:40









landru27

752213




752213










answered Nov 9 at 16:38









Yunbin Liu

1,006313




1,006313












  • perfectly done i must appreciate bou unfortunately i don't understand how this code is working ..I also have exams on monday :(
    – Âftãb Bãlôçh
    Nov 9 at 16:59










  • can you please tech me your code by commenting or something like dry run..I would be thankfull
    – Âftãb Bãlôçh
    Nov 9 at 17:39


















  • perfectly done i must appreciate bou unfortunately i don't understand how this code is working ..I also have exams on monday :(
    – Âftãb Bãlôçh
    Nov 9 at 16:59










  • can you please tech me your code by commenting or something like dry run..I would be thankfull
    – Âftãb Bãlôçh
    Nov 9 at 17:39
















perfectly done i must appreciate bou unfortunately i don't understand how this code is working ..I also have exams on monday :(
– Âftãb Bãlôçh
Nov 9 at 16:59




perfectly done i must appreciate bou unfortunately i don't understand how this code is working ..I also have exams on monday :(
– Âftãb Bãlôçh
Nov 9 at 16:59












can you please tech me your code by commenting or something like dry run..I would be thankfull
– Âftãb Bãlôçh
Nov 9 at 17:39




can you please tech me your code by commenting or something like dry run..I would be thankfull
– Âftãb Bãlôçh
Nov 9 at 17:39










up vote
0
down vote













What you are missing is that there is a trailing '' at the end of SHAHBAZ, which you are also "printing", but because '' does not have a character representation, you are seeing what looks like an 'extra' space.



Here is the smallest change I can think of to address this exact problem; add:



if (*(p+i)==0) continue; //don't try to print the trailing ''


just above your existing line:



printf("%c ",*(p+i));//prininting chracters


Output:



S H A 
H B A
Z A


There are other things I would do differently than how you are doing them, but this addresses your exact question, using your coding style.






share|improve this answer





















  • oh man !!! Thank you so much ..... THANKS DUDE LOVE YOU
    – Âftãb Bãlôçh
    Nov 9 at 16:53















up vote
0
down vote













What you are missing is that there is a trailing '' at the end of SHAHBAZ, which you are also "printing", but because '' does not have a character representation, you are seeing what looks like an 'extra' space.



Here is the smallest change I can think of to address this exact problem; add:



if (*(p+i)==0) continue; //don't try to print the trailing ''


just above your existing line:



printf("%c ",*(p+i));//prininting chracters


Output:



S H A 
H B A
Z A


There are other things I would do differently than how you are doing them, but this addresses your exact question, using your coding style.






share|improve this answer





















  • oh man !!! Thank you so much ..... THANKS DUDE LOVE YOU
    – Âftãb Bãlôçh
    Nov 9 at 16:53













up vote
0
down vote










up vote
0
down vote









What you are missing is that there is a trailing '' at the end of SHAHBAZ, which you are also "printing", but because '' does not have a character representation, you are seeing what looks like an 'extra' space.



Here is the smallest change I can think of to address this exact problem; add:



if (*(p+i)==0) continue; //don't try to print the trailing ''


just above your existing line:



printf("%c ",*(p+i));//prininting chracters


Output:



S H A 
H B A
Z A


There are other things I would do differently than how you are doing them, but this addresses your exact question, using your coding style.






share|improve this answer












What you are missing is that there is a trailing '' at the end of SHAHBAZ, which you are also "printing", but because '' does not have a character representation, you are seeing what looks like an 'extra' space.



Here is the smallest change I can think of to address this exact problem; add:



if (*(p+i)==0) continue; //don't try to print the trailing ''


just above your existing line:



printf("%c ",*(p+i));//prininting chracters


Output:



S H A 
H B A
Z A


There are other things I would do differently than how you are doing them, but this addresses your exact question, using your coding style.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 9 at 16:45









landru27

752213




752213












  • oh man !!! Thank you so much ..... THANKS DUDE LOVE YOU
    – Âftãb Bãlôçh
    Nov 9 at 16:53


















  • oh man !!! Thank you so much ..... THANKS DUDE LOVE YOU
    – Âftãb Bãlôçh
    Nov 9 at 16:53
















oh man !!! Thank you so much ..... THANKS DUDE LOVE YOU
– Âftãb Bãlôçh
Nov 9 at 16:53




oh man !!! Thank you so much ..... THANKS DUDE LOVE YOU
– Âftãb Bãlôçh
Nov 9 at 16:53


















 

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