python 3 regex string matching ignore whitespace and string.punctuation
I am new to regex and would like to know how to pattern match two strings. The use case would be something like finding a certain phrase in some text. I'm using python 3.7 if that makes a difference.
phrase = "some phrase" #the phrase I'm searching for
Possible matches:
text = "some#@$#phrase"
^^^^ #non-alphanumeric can be treated like a single space
text = "some phrase"
text = "!!!some!!! phrase!!!"
These are not matches:
text = "some phrases"
^ #the 's' on the end makes it false
text = "ssome phrase"
text = "some other phrase"
I have tried using something like:
re.search(r'b'+phrase+'b', text)
I would very much appreciate an explanation of why the regex works if you provide a valid solution.
regex string python-3.x pattern-matching non-alphanumeric
asked Nov 10 at 14:17
quixote
154
add a comment |
I am new to regex and would like to know how to pattern match two strings. The use case would be something like finding a certain phrase in some text. I'm using python 3.7 if that makes a difference.
phrase = "some phrase" #the phrase I'm searching for
Possible matches:
text = "some#@$#phrase"
^^^^ #non-alphanumeric can be treated like a single space
text = "some phrase"
text = "!!!some!!! phrase!!!"
These are not matches:
text = "some phrases"
^ #the 's' on the end makes it false
text = "ssome phrase"
text = "some other phrase"
I have tried using something like:
re.search(r'b'+phrase+'b', text)
I would very much appreciate an explanation of why the regex works if you provide a valid solution.
regex string python-3.x pattern-matching non-alphanumeric
asked Nov 10 at 14:17
quixote
154
Please edit your question because its not clear what do you want.
– Juan Ignacio Sánchez
Nov 10 at 14:24
add a comment |
I am new to regex and would like to know how to pattern match two strings. The use case would be something like finding a certain phrase in some text. I'm using python 3.7 if that makes a difference.
phrase = "some phrase" #the phrase I'm searching for
Possible matches:
text = "some#@$#phrase"
^^^^ #non-alphanumeric can be treated like a single space
text = "some phrase"
text = "!!!some!!! phrase!!!"
These are not matches:
text = "some phrases"
^ #the 's' on the end makes it false
text = "ssome phrase"
text = "some other phrase"
I have tried using something like:
re.search(r'b'+phrase+'b', text)
I would very much appreciate an explanation of why the regex works if you provide a valid solution.
regex string python-3.x pattern-matching non-alphanumeric
asked Nov 10 at 14:17
quixote
154
I am new to regex and would like to know how to pattern match two strings. The use case would be something like finding a certain phrase in some text. I'm using python 3.7 if that makes a difference.
phrase = "some phrase" #the phrase I'm searching for
Possible matches:
text = "some#@$#phrase"
^^^^ #non-alphanumeric can be treated like a single space
text = "some phrase"
text = "!!!some!!! phrase!!!"
These are not matches:
text = "some phrases"
^ #the 's' on the end makes it false
text = "ssome phrase"
text = "some other phrase"
I have tried using something like:
re.search(r'b'+phrase+'b', text)
I would very much appreciate an explanation of why the regex works if you provide a valid solution.
regex string python-3.x pattern-matching non-alphanumeric
regex string python-3.x pattern-matching non-alphanumeric
asked Nov 10 at 14:17
quixote
154
asked Nov 10 at 14:17
quixote
154
edited Nov 10 at 14:30
asked Nov 10 at 14:17
quixote
154
asked Nov 10 at 14:17
quixote
154
asked Nov 10 at 14:17
quixote
154
154
Please edit your question because its not clear what do you want.
– Juan Ignacio Sánchez
Nov 10 at 14:24
add a comment |
Please edit your question because its not clear what do you want.
– Juan Ignacio Sánchez
Nov 10 at 14:24
Please edit your question because its not clear what do you want.
– Juan Ignacio Sánchez
Nov 10 at 14:24
Please edit your question because its not clear what do you want.
– Juan Ignacio Sánchez
Nov 10 at 14:24
add a comment |
1 Answer
1
active
oldest
votes
You should use something like this:
re.search(r'bsomeW+phraseb', text)
'W' means non-word character
'+' means one or more times
In case you have a given phrase in a variable, you could try this before:
some_phrase = some_phrase.replace(r' ', r'W+')
answered Nov 10 at 14:39
Juan Ignacio Sánchez
316111
some_phrase = some_phrase.replace(r' ', r'W+') prints 'someW+phrase'.
– quixote
Nov 10 at 15:10
finally you put b at the begining and the end.
– Juan Ignacio Sánchez
Nov 10 at 15:16
does not this solve your problem? please explain to me on what you are stuck
– Juan Ignacio Sánchez
Nov 10 at 15:20
Oh I see what you mean. Perform the replace and then search using that string. Yes that is what I needed. Thank you.
– quixote
Nov 10 at 15:42
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You should use something like this:
re.search(r'bsomeW+phraseb', text)
'W' means non-word character
'+' means one or more times
In case you have a given phrase in a variable, you could try this before:
some_phrase = some_phrase.replace(r' ', r'W+')
answered Nov 10 at 14:39
Juan Ignacio Sánchez
316111
some_phrase = some_phrase.replace(r' ', r'W+') prints 'someW+phrase'.
– quixote
Nov 10 at 15:10
finally you put b at the begining and the end.
– Juan Ignacio Sánchez
Nov 10 at 15:16
does not this solve your problem? please explain to me on what you are stuck
– Juan Ignacio Sánchez
Nov 10 at 15:20
Oh I see what you mean. Perform the replace and then search using that string. Yes that is what I needed. Thank you.
– quixote
Nov 10 at 15:42
add a comment |
You should use something like this:
re.search(r'bsomeW+phraseb', text)
'W' means non-word character
'+' means one or more times
In case you have a given phrase in a variable, you could try this before:
some_phrase = some_phrase.replace(r' ', r'W+')
answered Nov 10 at 14:39
Juan Ignacio Sánchez
316111
some_phrase = some_phrase.replace(r' ', r'W+') prints 'someW+phrase'.
– quixote
Nov 10 at 15:10
finally you put b at the begining and the end.
– Juan Ignacio Sánchez
Nov 10 at 15:16
does not this solve your problem? please explain to me on what you are stuck
– Juan Ignacio Sánchez
Nov 10 at 15:20
Oh I see what you mean. Perform the replace and then search using that string. Yes that is what I needed. Thank you.
– quixote
Nov 10 at 15:42
add a comment |
You should use something like this:
re.search(r'bsomeW+phraseb', text)
'W' means non-word character
'+' means one or more times
In case you have a given phrase in a variable, you could try this before:
some_phrase = some_phrase.replace(r' ', r'W+')
answered Nov 10 at 14:39
Juan Ignacio Sánchez
316111
You should use something like this:
re.search(r'bsomeW+phraseb', text)
'W' means non-word character
'+' means one or more times
In case you have a given phrase in a variable, you could try this before:
some_phrase = some_phrase.replace(r' ', r'W+')
answered Nov 10 at 14:39
Juan Ignacio Sánchez
316111
edited Nov 10 at 14:46
answered Nov 10 at 14:39
Juan Ignacio Sánchez
316111
answered Nov 10 at 14:39
Juan Ignacio Sánchez
316111
answered Nov 10 at 14:39
Juan Ignacio Sánchez
316111
316111
some_phrase = some_phrase.replace(r' ', r'W+') prints 'someW+phrase'.
– quixote
Nov 10 at 15:10
finally you put b at the begining and the end.
– Juan Ignacio Sánchez
Nov 10 at 15:16
does not this solve your problem? please explain to me on what you are stuck
– Juan Ignacio Sánchez
Nov 10 at 15:20
Oh I see what you mean. Perform the replace and then search using that string. Yes that is what I needed. Thank you.
– quixote
Nov 10 at 15:42
add a comment |
some_phrase = some_phrase.replace(r' ', r'W+') prints 'someW+phrase'.
– quixote
Nov 10 at 15:10
finally you put b at the begining and the end.
– Juan Ignacio Sánchez
Nov 10 at 15:16
does not this solve your problem? please explain to me on what you are stuck
– Juan Ignacio Sánchez
Nov 10 at 15:20
Oh I see what you mean. Perform the replace and then search using that string. Yes that is what I needed. Thank you.
– quixote
Nov 10 at 15:42
some_phrase = some_phrase.replace(r' ', r'W+') prints 'someW+phrase'.
– quixote
Nov 10 at 15:10
some_phrase = some_phrase.replace(r' ', r'W+') prints 'someW+phrase'.
– quixote
Nov 10 at 15:10
finally you put b at the begining and the end.
– Juan Ignacio Sánchez
Nov 10 at 15:16
finally you put b at the begining and the end.
– Juan Ignacio Sánchez
Nov 10 at 15:16
does not this solve your problem? please explain to me on what you are stuck
– Juan Ignacio Sánchez
Nov 10 at 15:20
does not this solve your problem? please explain to me on what you are stuck
– Juan Ignacio Sánchez
Nov 10 at 15:20
Oh I see what you mean. Perform the replace and then search using that string. Yes that is what I needed. Thank you.
– quixote
Nov 10 at 15:42
Oh I see what you mean. Perform the replace and then search using that string. Yes that is what I needed. Thank you.
– quixote
Nov 10 at 15:42
add a comment |
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Please edit your question because its not clear what do you want.
– Juan Ignacio Sánchez
Nov 10 at 14:24