Can't access session variables in php
up vote
0
down vote
favorite
I'm trying to use session variable $_SESSION['name'] on the second page i.e review.php.
but it gives me nothing on the second page.How to use Session variable on the second page?
This is index.php
<?php
session_start();
$connect = mysqli_connect('localhost','root','root','review');
if(isset($_POST['submit']))
{
$id = $_POST['id'];
$_SESSION['name'] = $id;
}
?>
<!DOCTYPE html>
<html>
<head>
<title>
login
</title>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css">
</head>
<body>
<form action="review.php">
<input type="text" name="id" placeholder="id">
<input type="password" name="password" placeholder="password">
<input type="submit" name="submit" class="btn btn-success">
</form>
</body>
</html>
here is review.php
<?php
session_start();
$connect = mysqli_connect('localhost','root','root','review');
if(isset($_SESSION['name']))
{
echo $_SESSION['name'];
}
else{
echo "nothing";
}
?>
php session
asked Nov 10 at 10:27
Khan
136
add a comment |
up vote
0
down vote
favorite
I'm trying to use session variable $_SESSION['name'] on the second page i.e review.php.
but it gives me nothing on the second page.How to use Session variable on the second page?
This is index.php
<?php
session_start();
$connect = mysqli_connect('localhost','root','root','review');
if(isset($_POST['submit']))
{
$id = $_POST['id'];
$_SESSION['name'] = $id;
}
?>
<!DOCTYPE html>
<html>
<head>
<title>
login
</title>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css">
</head>
<body>
<form action="review.php">
<input type="text" name="id" placeholder="id">
<input type="password" name="password" placeholder="password">
<input type="submit" name="submit" class="btn btn-success">
</form>
</body>
</html>
here is review.php
<?php
session_start();
$connect = mysqli_connect('localhost','root','root','review');
if(isset($_SESSION['name']))
{
echo $_SESSION['name'];
}
else{
echo "nothing";
}
?>
php session
asked Nov 10 at 10:27
Khan
136
it is like: localhost/php/review/…
– Khan
Nov 10 at 10:36
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I'm trying to use session variable $_SESSION['name'] on the second page i.e review.php.
but it gives me nothing on the second page.How to use Session variable on the second page?
This is index.php
<?php
session_start();
$connect = mysqli_connect('localhost','root','root','review');
if(isset($_POST['submit']))
{
$id = $_POST['id'];
$_SESSION['name'] = $id;
}
?>
<!DOCTYPE html>
<html>
<head>
<title>
login
</title>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css">
</head>
<body>
<form action="review.php">
<input type="text" name="id" placeholder="id">
<input type="password" name="password" placeholder="password">
<input type="submit" name="submit" class="btn btn-success">
</form>
</body>
</html>
here is review.php
<?php
session_start();
$connect = mysqli_connect('localhost','root','root','review');
if(isset($_SESSION['name']))
{
echo $_SESSION['name'];
}
else{
echo "nothing";
}
?>
php session
asked Nov 10 at 10:27
Khan
136
I'm trying to use session variable $_SESSION['name'] on the second page i.e review.php.
but it gives me nothing on the second page.How to use Session variable on the second page?
This is index.php
<?php
session_start();
$connect = mysqli_connect('localhost','root','root','review');
if(isset($_POST['submit']))
{
$id = $_POST['id'];
$_SESSION['name'] = $id;
}
?>
<!DOCTYPE html>
<html>
<head>
<title>
login
</title>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css">
</head>
<body>
<form action="review.php">
<input type="text" name="id" placeholder="id">
<input type="password" name="password" placeholder="password">
<input type="submit" name="submit" class="btn btn-success">
</form>
</body>
</html>
here is review.php
<?php
session_start();
$connect = mysqli_connect('localhost','root','root','review');
if(isset($_SESSION['name']))
{
echo $_SESSION['name'];
}
else{
echo "nothing";
}
?>
php session
php session
asked Nov 10 at 10:27
Khan
136
asked Nov 10 at 10:27
Khan
136
asked Nov 10 at 10:27
Khan
136
asked Nov 10 at 10:27
Khan
136
asked Nov 10 at 10:27
Khan
136
136
it is like: localhost/php/review/…
– Khan
Nov 10 at 10:36
add a comment |
it is like: localhost/php/review/…
– Khan
Nov 10 at 10:36
it is like: localhost/php/review/…
– Khan
Nov 10 at 10:36
it is like: localhost/php/review/…
– Khan
Nov 10 at 10:36
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
accepted
You have 2 problem:
- You send submitted form to
review.php, so you should read form data inreview.php
- You did not set form
method. As defaultmethodisGET, but you read$_POSTvariable. (What is the default form HTTP method?)
So you should change index.php as follow:
<?php
session_start();
$connect = mysqli_connect('localhost','root','root','review');
if(isset($_POST['submit']))
{
$id = $_POST['id'];
$_SESSION['name'] = $id;
}
?>
<!DOCTYPE html>
<html>
<head>
<title>
login
</title>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css">
</head>
<body>
<form method="post">
<input type="text" name="id" placeholder="id">
<input type="password" name="password" placeholder="password">
<input type="submit" name="submit" class="btn btn-success">
</form>
</body>
</html>
answered Nov 10 at 10:43
Mohammad Ali Taqvazadeh
947
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53238025%2fcant-access-session-variables-in-php%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
You have 2 problem:
- You send submitted form to
review.php, so you should read form data inreview.php
- You did not set form
method. As defaultmethodisGET, but you read$_POSTvariable. (What is the default form HTTP method?)
So you should change index.php as follow:
<?php
session_start();
$connect = mysqli_connect('localhost','root','root','review');
if(isset($_POST['submit']))
{
$id = $_POST['id'];
$_SESSION['name'] = $id;
}
?>
<!DOCTYPE html>
<html>
<head>
<title>
login
</title>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css">
</head>
<body>
<form method="post">
<input type="text" name="id" placeholder="id">
<input type="password" name="password" placeholder="password">
<input type="submit" name="submit" class="btn btn-success">
</form>
</body>
</html>
answered Nov 10 at 10:43
Mohammad Ali Taqvazadeh
947
add a comment |
up vote
0
down vote
accepted
You have 2 problem:
- You send submitted form to
review.php, so you should read form data inreview.php
- You did not set form
method. As defaultmethodisGET, but you read$_POSTvariable. (What is the default form HTTP method?)
So you should change index.php as follow:
<?php
session_start();
$connect = mysqli_connect('localhost','root','root','review');
if(isset($_POST['submit']))
{
$id = $_POST['id'];
$_SESSION['name'] = $id;
}
?>
<!DOCTYPE html>
<html>
<head>
<title>
login
</title>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css">
</head>
<body>
<form method="post">
<input type="text" name="id" placeholder="id">
<input type="password" name="password" placeholder="password">
<input type="submit" name="submit" class="btn btn-success">
</form>
</body>
</html>
answered Nov 10 at 10:43
Mohammad Ali Taqvazadeh
947
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
You have 2 problem:
- You send submitted form to
review.php, so you should read form data inreview.php
- You did not set form
method. As defaultmethodisGET, but you read$_POSTvariable. (What is the default form HTTP method?)
So you should change index.php as follow:
<?php
session_start();
$connect = mysqli_connect('localhost','root','root','review');
if(isset($_POST['submit']))
{
$id = $_POST['id'];
$_SESSION['name'] = $id;
}
?>
<!DOCTYPE html>
<html>
<head>
<title>
login
</title>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css">
</head>
<body>
<form method="post">
<input type="text" name="id" placeholder="id">
<input type="password" name="password" placeholder="password">
<input type="submit" name="submit" class="btn btn-success">
</form>
</body>
</html>
answered Nov 10 at 10:43
Mohammad Ali Taqvazadeh
947
You have 2 problem:
- You send submitted form to
review.php, so you should read form data inreview.php
- You did not set form
method. As defaultmethodisGET, but you read$_POSTvariable. (What is the default form HTTP method?)
So you should change index.php as follow:
<?php
session_start();
$connect = mysqli_connect('localhost','root','root','review');
if(isset($_POST['submit']))
{
$id = $_POST['id'];
$_SESSION['name'] = $id;
}
?>
<!DOCTYPE html>
<html>
<head>
<title>
login
</title>
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css">
</head>
<body>
<form method="post">
<input type="text" name="id" placeholder="id">
<input type="password" name="password" placeholder="password">
<input type="submit" name="submit" class="btn btn-success">
</form>
</body>
</html>
answered Nov 10 at 10:43
Mohammad Ali Taqvazadeh
947
answered Nov 10 at 10:43
Mohammad Ali Taqvazadeh
947
answered Nov 10 at 10:43
Mohammad Ali Taqvazadeh
947
answered Nov 10 at 10:43
Mohammad Ali Taqvazadeh
947
947
add a comment |
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53238025%2fcant-access-session-variables-in-php%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
it is like: localhost/php/review/…
– Khan
Nov 10 at 10:36