Iterate from col/row in matrix python
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I'm trying to take a column from sparse matrix(with scipy sparse library), and use for other operation in Python 3.
I tried to do this:
for l in range (0,10):
vec[l] =np.squeeze(np.asarray(sparse_matrix[:,l].A))
print(l,vec[l])
working but take often the same output, because l can't iterate in the range.
so my output is the same :
1 [4,5,4,5]
2 [4,5,4,5]
...
...
where was I wrong?
i m not sure if i do this np.squeeze(np.asarray(sparse_matrix[:,x].A))
where x is a number, I take an array from my columns of sparse matrix, I saw it in another StackOverflow question and seems work.
python arrays numpy matrix scipy
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up vote
0
down vote
favorite
I'm trying to take a column from sparse matrix(with scipy sparse library), and use for other operation in Python 3.
I tried to do this:
for l in range (0,10):
vec[l] =np.squeeze(np.asarray(sparse_matrix[:,l].A))
print(l,vec[l])
working but take often the same output, because l can't iterate in the range.
so my output is the same :
1 [4,5,4,5]
2 [4,5,4,5]
...
...
where was I wrong?
i m not sure if i do this np.squeeze(np.asarray(sparse_matrix[:,x].A))
where x is a number, I take an array from my columns of sparse matrix, I saw it in another StackOverflow question and seems work.
python arrays numpy matrix scipy
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I'm trying to take a column from sparse matrix(with scipy sparse library), and use for other operation in Python 3.
I tried to do this:
for l in range (0,10):
vec[l] =np.squeeze(np.asarray(sparse_matrix[:,l].A))
print(l,vec[l])
working but take often the same output, because l can't iterate in the range.
so my output is the same :
1 [4,5,4,5]
2 [4,5,4,5]
...
...
where was I wrong?
i m not sure if i do this np.squeeze(np.asarray(sparse_matrix[:,x].A))
where x is a number, I take an array from my columns of sparse matrix, I saw it in another StackOverflow question and seems work.
python arrays numpy matrix scipy
I'm trying to take a column from sparse matrix(with scipy sparse library), and use for other operation in Python 3.
I tried to do this:
for l in range (0,10):
vec[l] =np.squeeze(np.asarray(sparse_matrix[:,l].A))
print(l,vec[l])
working but take often the same output, because l can't iterate in the range.
so my output is the same :
1 [4,5,4,5]
2 [4,5,4,5]
...
...
where was I wrong?
i m not sure if i do this np.squeeze(np.asarray(sparse_matrix[:,x].A))
where x is a number, I take an array from my columns of sparse matrix, I saw it in another StackOverflow question and seems work.
python arrays numpy matrix scipy
python arrays numpy matrix scipy
edited Nov 10 at 10:44
lgwilliams
505317
505317
asked Nov 10 at 10:29
theantomc
417
417
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i tried more time, and i fixed with this
vec[l]=sparse_matrix.getcol(l).toarray()
in this way, at each iteration change the value of l.
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
i tried more time, and i fixed with this
vec[l]=sparse_matrix.getcol(l).toarray()
in this way, at each iteration change the value of l.
add a comment |
up vote
0
down vote
accepted
i tried more time, and i fixed with this
vec[l]=sparse_matrix.getcol(l).toarray()
in this way, at each iteration change the value of l.
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
i tried more time, and i fixed with this
vec[l]=sparse_matrix.getcol(l).toarray()
in this way, at each iteration change the value of l.
i tried more time, and i fixed with this
vec[l]=sparse_matrix.getcol(l).toarray()
in this way, at each iteration change the value of l.
answered Nov 10 at 10:45
theantomc
417
417
add a comment |
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