Input line from Scanner object gets printed before official print command
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I have a the following method below that receives a Scanner object with N number of lines, each with a a one word string.
public static void longestName(Scanner console, int n) {
for (int i = 1; i <= n; i++) {
System.out.println("name #" + i + "?" + " " + console.nextLine());
}
}
Instead of this (expected output)...
name #1? roy
name #2? DANE
name #3? Erik
name #4? sTeFaNiE
name #5? LaurA
...I'm getting this
roy
name #1? roy
DANE
name #2? DANE
Erik
name #3? Erik
sTeFaNiE
name #4? sTeFaNiE
LaurA
name #5? LaurA
Why is the "nextLine()" from the Scanner object being printed once prior to the actual print command output?
****** This is a practice problem I'm using and they only ask me to define a method "longestName" that takes a Scanner object and an integer "n" denoting the number of names in the Scanner object.
The output above is a result of the method being used with a Scanner object with "n" number of names.
java java.util.scanner user-input system.out console-input
asked Nov 8 at 19:37
Edson
123111
add a comment |
up vote
0
down vote
favorite
I have a the following method below that receives a Scanner object with N number of lines, each with a a one word string.
public static void longestName(Scanner console, int n) {
for (int i = 1; i <= n; i++) {
System.out.println("name #" + i + "?" + " " + console.nextLine());
}
}
Instead of this (expected output)...
name #1? roy
name #2? DANE
name #3? Erik
name #4? sTeFaNiE
name #5? LaurA
...I'm getting this
roy
name #1? roy
DANE
name #2? DANE
Erik
name #3? Erik
sTeFaNiE
name #4? sTeFaNiE
LaurA
name #5? LaurA
Why is the "nextLine()" from the Scanner object being printed once prior to the actual print command output?
****** This is a practice problem I'm using and they only ask me to define a method "longestName" that takes a Scanner object and an integer "n" denoting the number of names in the Scanner object.
The output above is a result of the method being used with a Scanner object with "n" number of names.
java java.util.scanner user-input system.out console-input
asked Nov 8 at 19:37
Edson
123111
Please post full code.
– Sasikumar Murugesan
Nov 8 at 19:42
2
Er isn't that just the text you typed yourself, followed by the output of the code?
– OpenSauce
Nov 8 at 19:43
@OpenSauce - huh? I manually posted the output. The code i'm using for a practice problem on a website that runs the code I input. It shows me the output I posted above.
– Edson
Nov 8 at 21:05
@Edson the Scanner gets its input from somewhere, presumably from you typing it into the console. Since you type into the console, what you type appears in the console. The confusion probably comes from you putting the code into a website which makes it look like your input is separate from the console content. If you just ran the code as a standalone Java application it would be more clear.
– OpenSauce
Nov 8 at 21:14
@OpenSauce - Yup, I understand what you asked now, I edited my post with an explanation.
– Edson
Nov 8 at 21:17
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have a the following method below that receives a Scanner object with N number of lines, each with a a one word string.
public static void longestName(Scanner console, int n) {
for (int i = 1; i <= n; i++) {
System.out.println("name #" + i + "?" + " " + console.nextLine());
}
}
Instead of this (expected output)...
name #1? roy
name #2? DANE
name #3? Erik
name #4? sTeFaNiE
name #5? LaurA
...I'm getting this
roy
name #1? roy
DANE
name #2? DANE
Erik
name #3? Erik
sTeFaNiE
name #4? sTeFaNiE
LaurA
name #5? LaurA
Why is the "nextLine()" from the Scanner object being printed once prior to the actual print command output?
****** This is a practice problem I'm using and they only ask me to define a method "longestName" that takes a Scanner object and an integer "n" denoting the number of names in the Scanner object.
The output above is a result of the method being used with a Scanner object with "n" number of names.
java java.util.scanner user-input system.out console-input
asked Nov 8 at 19:37
Edson
123111
I have a the following method below that receives a Scanner object with N number of lines, each with a a one word string.
public static void longestName(Scanner console, int n) {
for (int i = 1; i <= n; i++) {
System.out.println("name #" + i + "?" + " " + console.nextLine());
}
}
Instead of this (expected output)...
name #1? roy
name #2? DANE
name #3? Erik
name #4? sTeFaNiE
name #5? LaurA
...I'm getting this
roy
name #1? roy
DANE
name #2? DANE
Erik
name #3? Erik
sTeFaNiE
name #4? sTeFaNiE
LaurA
name #5? LaurA
Why is the "nextLine()" from the Scanner object being printed once prior to the actual print command output?
****** This is a practice problem I'm using and they only ask me to define a method "longestName" that takes a Scanner object and an integer "n" denoting the number of names in the Scanner object.
The output above is a result of the method being used with a Scanner object with "n" number of names.
java java.util.scanner user-input system.out console-input
java java.util.scanner user-input system.out console-input
asked Nov 8 at 19:37
Edson
123111
asked Nov 8 at 19:37
Edson
123111
edited Nov 8 at 21:16
asked Nov 8 at 19:37
Edson
123111
asked Nov 8 at 19:37
Edson
123111
asked Nov 8 at 19:37
Edson
123111
123111
Please post full code.
– Sasikumar Murugesan
Nov 8 at 19:42
2
Er isn't that just the text you typed yourself, followed by the output of the code?
– OpenSauce
Nov 8 at 19:43
@OpenSauce - huh? I manually posted the output. The code i'm using for a practice problem on a website that runs the code I input. It shows me the output I posted above.
– Edson
Nov 8 at 21:05
@Edson the Scanner gets its input from somewhere, presumably from you typing it into the console. Since you type into the console, what you type appears in the console. The confusion probably comes from you putting the code into a website which makes it look like your input is separate from the console content. If you just ran the code as a standalone Java application it would be more clear.
– OpenSauce
Nov 8 at 21:14
@OpenSauce - Yup, I understand what you asked now, I edited my post with an explanation.
– Edson
Nov 8 at 21:17
add a comment |
Please post full code.
– Sasikumar Murugesan
Nov 8 at 19:42
2
Er isn't that just the text you typed yourself, followed by the output of the code?
– OpenSauce
Nov 8 at 19:43
@OpenSauce - huh? I manually posted the output. The code i'm using for a practice problem on a website that runs the code I input. It shows me the output I posted above.
– Edson
Nov 8 at 21:05
@Edson the Scanner gets its input from somewhere, presumably from you typing it into the console. Since you type into the console, what you type appears in the console. The confusion probably comes from you putting the code into a website which makes it look like your input is separate from the console content. If you just ran the code as a standalone Java application it would be more clear.
– OpenSauce
Nov 8 at 21:14
@OpenSauce - Yup, I understand what you asked now, I edited my post with an explanation.
– Edson
Nov 8 at 21:17
Please post full code.
– Sasikumar Murugesan
Nov 8 at 19:42
Please post full code.
– Sasikumar Murugesan
Nov 8 at 19:42
2
2
Er isn't that just the text you typed yourself, followed by the output of the code?
– OpenSauce
Nov 8 at 19:43
Er isn't that just the text you typed yourself, followed by the output of the code?
– OpenSauce
Nov 8 at 19:43
@OpenSauce - huh? I manually posted the output. The code i'm using for a practice problem on a website that runs the code I input. It shows me the output I posted above.
– Edson
Nov 8 at 21:05
@OpenSauce - huh? I manually posted the output. The code i'm using for a practice problem on a website that runs the code I input. It shows me the output I posted above.
– Edson
Nov 8 at 21:05
@Edson the Scanner gets its input from somewhere, presumably from you typing it into the console. Since you type into the console, what you type appears in the console. The confusion probably comes from you putting the code into a website which makes it look like your input is separate from the console content. If you just ran the code as a standalone Java application it would be more clear.
– OpenSauce
Nov 8 at 21:14
@Edson the Scanner gets its input from somewhere, presumably from you typing it into the console. Since you type into the console, what you type appears in the console. The confusion probably comes from you putting the code into a website which makes it look like your input is separate from the console content. If you just ran the code as a standalone Java application it would be more clear.
– OpenSauce
Nov 8 at 21:14
@OpenSauce - Yup, I understand what you asked now, I edited my post with an explanation.
– Edson
Nov 8 at 21:17
@OpenSauce - Yup, I understand what you asked now, I edited my post with an explanation.
– Edson
Nov 8 at 21:17
add a comment |
2 Answers
2
active
oldest
votes
up vote
1
down vote
accepted
This will give you the expected output:
System.out.println("name #" + i + "?" + " ");
console.nextLine();
answered Nov 8 at 19:50
Justin
37618
Thanks, it worked after I used "print" instead of "println". Any ideas as to why the original code wasn't working correctly?
– Edson
Nov 8 at 21:11
When constructing the string to print out, java attempts to get the input before printing out to console. The function must finish before the line prints out
– Justin
Nov 8 at 22:16
add a comment |
up vote
1
down vote
It is not printing it multiple times, it is the text you have typed into the console yourself. You type Erik as you can see, only after that it will process your print statement and print name #3? Erik where Erik is the text you've typed in.
answered Nov 8 at 19:41
Mark
2,4551620
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
This will give you the expected output:
System.out.println("name #" + i + "?" + " ");
console.nextLine();
answered Nov 8 at 19:50
Justin
37618
Thanks, it worked after I used "print" instead of "println". Any ideas as to why the original code wasn't working correctly?
– Edson
Nov 8 at 21:11
When constructing the string to print out, java attempts to get the input before printing out to console. The function must finish before the line prints out
– Justin
Nov 8 at 22:16
add a comment |
up vote
1
down vote
accepted
This will give you the expected output:
System.out.println("name #" + i + "?" + " ");
console.nextLine();
answered Nov 8 at 19:50
Justin
37618
Thanks, it worked after I used "print" instead of "println". Any ideas as to why the original code wasn't working correctly?
– Edson
Nov 8 at 21:11
When constructing the string to print out, java attempts to get the input before printing out to console. The function must finish before the line prints out
– Justin
Nov 8 at 22:16
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
This will give you the expected output:
System.out.println("name #" + i + "?" + " ");
console.nextLine();
answered Nov 8 at 19:50
Justin
37618
This will give you the expected output:
System.out.println("name #" + i + "?" + " ");
console.nextLine();
answered Nov 8 at 19:50
Justin
37618
answered Nov 8 at 19:50
Justin
37618
answered Nov 8 at 19:50
Justin
37618
answered Nov 8 at 19:50
Justin
37618
37618
Thanks, it worked after I used "print" instead of "println". Any ideas as to why the original code wasn't working correctly?
– Edson
Nov 8 at 21:11
When constructing the string to print out, java attempts to get the input before printing out to console. The function must finish before the line prints out
– Justin
Nov 8 at 22:16
add a comment |
Thanks, it worked after I used "print" instead of "println". Any ideas as to why the original code wasn't working correctly?
– Edson
Nov 8 at 21:11
When constructing the string to print out, java attempts to get the input before printing out to console. The function must finish before the line prints out
– Justin
Nov 8 at 22:16
Thanks, it worked after I used "print" instead of "println". Any ideas as to why the original code wasn't working correctly?
– Edson
Nov 8 at 21:11
Thanks, it worked after I used "print" instead of "println". Any ideas as to why the original code wasn't working correctly?
– Edson
Nov 8 at 21:11
When constructing the string to print out, java attempts to get the input before printing out to console. The function must finish before the line prints out
– Justin
Nov 8 at 22:16
When constructing the string to print out, java attempts to get the input before printing out to console. The function must finish before the line prints out
– Justin
Nov 8 at 22:16
add a comment |
up vote
1
down vote
It is not printing it multiple times, it is the text you have typed into the console yourself. You type Erik as you can see, only after that it will process your print statement and print name #3? Erik where Erik is the text you've typed in.
answered Nov 8 at 19:41
Mark
2,4551620
add a comment |
up vote
1
down vote
It is not printing it multiple times, it is the text you have typed into the console yourself. You type Erik as you can see, only after that it will process your print statement and print name #3? Erik where Erik is the text you've typed in.
answered Nov 8 at 19:41
Mark
2,4551620
add a comment |
up vote
1
down vote
up vote
1
down vote
It is not printing it multiple times, it is the text you have typed into the console yourself. You type Erik as you can see, only after that it will process your print statement and print name #3? Erik where Erik is the text you've typed in.
answered Nov 8 at 19:41
Mark
2,4551620
It is not printing it multiple times, it is the text you have typed into the console yourself. You type Erik as you can see, only after that it will process your print statement and print name #3? Erik where Erik is the text you've typed in.
answered Nov 8 at 19:41
Mark
2,4551620
answered Nov 8 at 19:41
Mark
2,4551620
answered Nov 8 at 19:41
Mark
2,4551620
answered Nov 8 at 19:41
Mark
2,4551620
2,4551620
add a comment |
add a comment |
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Please post full code.
– Sasikumar Murugesan
Nov 8 at 19:42
2
Er isn't that just the text you typed yourself, followed by the output of the code?
– OpenSauce
Nov 8 at 19:43
@OpenSauce - huh? I manually posted the output. The code i'm using for a practice problem on a website that runs the code I input. It shows me the output I posted above.
– Edson
Nov 8 at 21:05
@Edson the Scanner gets its input from somewhere, presumably from you typing it into the console. Since you type into the console, what you type appears in the console. The confusion probably comes from you putting the code into a website which makes it look like your input is separate from the console content. If you just ran the code as a standalone Java application it would be more clear.
– OpenSauce
Nov 8 at 21:14
@OpenSauce - Yup, I understand what you asked now, I edited my post with an explanation.
– Edson
Nov 8 at 21:17