Type variables in a simple component











up vote
2
down vote

favorite












Say I have this simple component



type evt =
| NoOp;

type t('a) = 'a;

let component = ReasonReact.reducerComponent("TestComponent");

let make = _children => {
...component,
initialState: () => "hello",
reducer: (evt, state: t('a)) =>
switch (evt) {
| NoOp => ReasonReact.NoUpdate
},
render: self => <div> {str("hello")} </div>,
};


(try it here)



Why am I getting



The type of this module contains type variables that cannot be generalized



? (The type variable is useless here, but imagine it was needed in initialState. Tried to keep the sample as simple as possible.)










share|improve this question




























    up vote
    2
    down vote

    favorite












    Say I have this simple component



    type evt =
    | NoOp;

    type t('a) = 'a;

    let component = ReasonReact.reducerComponent("TestComponent");

    let make = _children => {
    ...component,
    initialState: () => "hello",
    reducer: (evt, state: t('a)) =>
    switch (evt) {
    | NoOp => ReasonReact.NoUpdate
    },
    render: self => <div> {str("hello")} </div>,
    };


    (try it here)



    Why am I getting



    The type of this module contains type variables that cannot be generalized



    ? (The type variable is useless here, but imagine it was needed in initialState. Tried to keep the sample as simple as possible.)










    share|improve this question


























      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      Say I have this simple component



      type evt =
      | NoOp;

      type t('a) = 'a;

      let component = ReasonReact.reducerComponent("TestComponent");

      let make = _children => {
      ...component,
      initialState: () => "hello",
      reducer: (evt, state: t('a)) =>
      switch (evt) {
      | NoOp => ReasonReact.NoUpdate
      },
      render: self => <div> {str("hello")} </div>,
      };


      (try it here)



      Why am I getting



      The type of this module contains type variables that cannot be generalized



      ? (The type variable is useless here, but imagine it was needed in initialState. Tried to keep the sample as simple as possible.)










      share|improve this question















      Say I have this simple component



      type evt =
      | NoOp;

      type t('a) = 'a;

      let component = ReasonReact.reducerComponent("TestComponent");

      let make = _children => {
      ...component,
      initialState: () => "hello",
      reducer: (evt, state: t('a)) =>
      switch (evt) {
      | NoOp => ReasonReact.NoUpdate
      },
      render: self => <div> {str("hello")} </div>,
      };


      (try it here)



      Why am I getting



      The type of this module contains type variables that cannot be generalized



      ? (The type variable is useless here, but imagine it was needed in initialState. Tried to keep the sample as simple as possible.)







      compiler-errors polymorphism ocaml reason reason-react






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 9 at 10:51









      glennsl

      8,918102645




      8,918102645










      asked Nov 9 at 7:51









      swelet

      3,16231930




      3,16231930
























          1 Answer
          1






          active

          oldest

          votes

















          up vote
          2
          down vote



          accepted










          The technical reason is that a ReasonReact component is record type which would look something like this:



          type fauxComponent = {
          reducer: (evt, t('a)) => t('a),
          render: t('a) => ReasonReact.reactElement
          };


          If you try to compile this you'll get an error about an "Unbound type parameter". The difference in error is because it is inferred to be of type ReasonReact.component which has a bunch of type variables, one of which is inferred to have a polymorphic type. The problem is essentially the same, but much easier to illustrate without all the indirection.



          Th technical reason why you can't do this I think is called the value restriction. But there are practical reasons as well. You actually can make this type compile if you explicitly specify 'a as being polymorphic:



          type fauxComponent = {
          reducer: 'a. (evt, t('a)) => t('a),
          render: 'a. t('a) => ReasonReact.reactElement
          };


          This says that 'a can be anything, but that's also the problem. Since it can be anything, you can't know what it is, and you therefore can't really do anything with it other than to have it pass through and returned. You also don't know that 'a is the same in reducer and render, which isn't usually a problem with records since they're not stateful objects. The problem arises because ReasonReact "abuses" them as if they were.



          So how would you then accomplish what you're trying to do? Easy, use a functor! ;) In Reason you can parameterize modules, which are then called functors, and use that to specify the type to use across the entire module. Here's your example functorized:



          module type Config = {
          type t;
          let initialState : t;
          };

          module FunctorComponent(T : Config) {
          type evt =
          | NoOp;

          type t = T.t;

          let component = ReasonReact.reducerComponent("TestComponent");

          let make = _children => {
          ...component,
          initialState: () => T.initialState,
          reducer: (evt, state: t) =>
          switch (evt) {
          | NoOp => ReasonReact.NoUpdate
          },
          render: self => <div> {ReasonReact.string("hello")} </div>,
          };
          };

          module MyComponent = FunctorComponent({
          type t = string;
          let initialState = "hello";
          });

          ReactDOMRe.renderToElementWithId(<MyComponent />, "preview");


          The parameters a functor takes actually need to be modules, so we first define a module type Config, specify that as the parameter type, and then when we create our MyComponent module using the functor we create and pass it an anonymous module that implement the Config module type.



          Now you know why a lot of people think OCaml and Reason's module system is so awesome :) (There's actually a lot more to it, but this is a good start)






          share|improve this answer





















          • Whoa! You just blew my mind. Can't try it until tonight, but the upvote is yours.
            – swelet
            Nov 9 at 11:50










          • Thanks once again. Been dabbling with Reason and functional programming in general for a while now but I never had a practical use case for functors until now (atleast not that I know of), so I never got to learning them. Great answer!
            – swelet
            Nov 9 at 22:19











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          active

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          up vote
          2
          down vote



          accepted










          The technical reason is that a ReasonReact component is record type which would look something like this:



          type fauxComponent = {
          reducer: (evt, t('a)) => t('a),
          render: t('a) => ReasonReact.reactElement
          };


          If you try to compile this you'll get an error about an "Unbound type parameter". The difference in error is because it is inferred to be of type ReasonReact.component which has a bunch of type variables, one of which is inferred to have a polymorphic type. The problem is essentially the same, but much easier to illustrate without all the indirection.



          Th technical reason why you can't do this I think is called the value restriction. But there are practical reasons as well. You actually can make this type compile if you explicitly specify 'a as being polymorphic:



          type fauxComponent = {
          reducer: 'a. (evt, t('a)) => t('a),
          render: 'a. t('a) => ReasonReact.reactElement
          };


          This says that 'a can be anything, but that's also the problem. Since it can be anything, you can't know what it is, and you therefore can't really do anything with it other than to have it pass through and returned. You also don't know that 'a is the same in reducer and render, which isn't usually a problem with records since they're not stateful objects. The problem arises because ReasonReact "abuses" them as if they were.



          So how would you then accomplish what you're trying to do? Easy, use a functor! ;) In Reason you can parameterize modules, which are then called functors, and use that to specify the type to use across the entire module. Here's your example functorized:



          module type Config = {
          type t;
          let initialState : t;
          };

          module FunctorComponent(T : Config) {
          type evt =
          | NoOp;

          type t = T.t;

          let component = ReasonReact.reducerComponent("TestComponent");

          let make = _children => {
          ...component,
          initialState: () => T.initialState,
          reducer: (evt, state: t) =>
          switch (evt) {
          | NoOp => ReasonReact.NoUpdate
          },
          render: self => <div> {ReasonReact.string("hello")} </div>,
          };
          };

          module MyComponent = FunctorComponent({
          type t = string;
          let initialState = "hello";
          });

          ReactDOMRe.renderToElementWithId(<MyComponent />, "preview");


          The parameters a functor takes actually need to be modules, so we first define a module type Config, specify that as the parameter type, and then when we create our MyComponent module using the functor we create and pass it an anonymous module that implement the Config module type.



          Now you know why a lot of people think OCaml and Reason's module system is so awesome :) (There's actually a lot more to it, but this is a good start)






          share|improve this answer





















          • Whoa! You just blew my mind. Can't try it until tonight, but the upvote is yours.
            – swelet
            Nov 9 at 11:50










          • Thanks once again. Been dabbling with Reason and functional programming in general for a while now but I never had a practical use case for functors until now (atleast not that I know of), so I never got to learning them. Great answer!
            – swelet
            Nov 9 at 22:19















          up vote
          2
          down vote



          accepted










          The technical reason is that a ReasonReact component is record type which would look something like this:



          type fauxComponent = {
          reducer: (evt, t('a)) => t('a),
          render: t('a) => ReasonReact.reactElement
          };


          If you try to compile this you'll get an error about an "Unbound type parameter". The difference in error is because it is inferred to be of type ReasonReact.component which has a bunch of type variables, one of which is inferred to have a polymorphic type. The problem is essentially the same, but much easier to illustrate without all the indirection.



          Th technical reason why you can't do this I think is called the value restriction. But there are practical reasons as well. You actually can make this type compile if you explicitly specify 'a as being polymorphic:



          type fauxComponent = {
          reducer: 'a. (evt, t('a)) => t('a),
          render: 'a. t('a) => ReasonReact.reactElement
          };


          This says that 'a can be anything, but that's also the problem. Since it can be anything, you can't know what it is, and you therefore can't really do anything with it other than to have it pass through and returned. You also don't know that 'a is the same in reducer and render, which isn't usually a problem with records since they're not stateful objects. The problem arises because ReasonReact "abuses" them as if they were.



          So how would you then accomplish what you're trying to do? Easy, use a functor! ;) In Reason you can parameterize modules, which are then called functors, and use that to specify the type to use across the entire module. Here's your example functorized:



          module type Config = {
          type t;
          let initialState : t;
          };

          module FunctorComponent(T : Config) {
          type evt =
          | NoOp;

          type t = T.t;

          let component = ReasonReact.reducerComponent("TestComponent");

          let make = _children => {
          ...component,
          initialState: () => T.initialState,
          reducer: (evt, state: t) =>
          switch (evt) {
          | NoOp => ReasonReact.NoUpdate
          },
          render: self => <div> {ReasonReact.string("hello")} </div>,
          };
          };

          module MyComponent = FunctorComponent({
          type t = string;
          let initialState = "hello";
          });

          ReactDOMRe.renderToElementWithId(<MyComponent />, "preview");


          The parameters a functor takes actually need to be modules, so we first define a module type Config, specify that as the parameter type, and then when we create our MyComponent module using the functor we create and pass it an anonymous module that implement the Config module type.



          Now you know why a lot of people think OCaml and Reason's module system is so awesome :) (There's actually a lot more to it, but this is a good start)






          share|improve this answer





















          • Whoa! You just blew my mind. Can't try it until tonight, but the upvote is yours.
            – swelet
            Nov 9 at 11:50










          • Thanks once again. Been dabbling with Reason and functional programming in general for a while now but I never had a practical use case for functors until now (atleast not that I know of), so I never got to learning them. Great answer!
            – swelet
            Nov 9 at 22:19













          up vote
          2
          down vote



          accepted







          up vote
          2
          down vote



          accepted






          The technical reason is that a ReasonReact component is record type which would look something like this:



          type fauxComponent = {
          reducer: (evt, t('a)) => t('a),
          render: t('a) => ReasonReact.reactElement
          };


          If you try to compile this you'll get an error about an "Unbound type parameter". The difference in error is because it is inferred to be of type ReasonReact.component which has a bunch of type variables, one of which is inferred to have a polymorphic type. The problem is essentially the same, but much easier to illustrate without all the indirection.



          Th technical reason why you can't do this I think is called the value restriction. But there are practical reasons as well. You actually can make this type compile if you explicitly specify 'a as being polymorphic:



          type fauxComponent = {
          reducer: 'a. (evt, t('a)) => t('a),
          render: 'a. t('a) => ReasonReact.reactElement
          };


          This says that 'a can be anything, but that's also the problem. Since it can be anything, you can't know what it is, and you therefore can't really do anything with it other than to have it pass through and returned. You also don't know that 'a is the same in reducer and render, which isn't usually a problem with records since they're not stateful objects. The problem arises because ReasonReact "abuses" them as if they were.



          So how would you then accomplish what you're trying to do? Easy, use a functor! ;) In Reason you can parameterize modules, which are then called functors, and use that to specify the type to use across the entire module. Here's your example functorized:



          module type Config = {
          type t;
          let initialState : t;
          };

          module FunctorComponent(T : Config) {
          type evt =
          | NoOp;

          type t = T.t;

          let component = ReasonReact.reducerComponent("TestComponent");

          let make = _children => {
          ...component,
          initialState: () => T.initialState,
          reducer: (evt, state: t) =>
          switch (evt) {
          | NoOp => ReasonReact.NoUpdate
          },
          render: self => <div> {ReasonReact.string("hello")} </div>,
          };
          };

          module MyComponent = FunctorComponent({
          type t = string;
          let initialState = "hello";
          });

          ReactDOMRe.renderToElementWithId(<MyComponent />, "preview");


          The parameters a functor takes actually need to be modules, so we first define a module type Config, specify that as the parameter type, and then when we create our MyComponent module using the functor we create and pass it an anonymous module that implement the Config module type.



          Now you know why a lot of people think OCaml and Reason's module system is so awesome :) (There's actually a lot more to it, but this is a good start)






          share|improve this answer












          The technical reason is that a ReasonReact component is record type which would look something like this:



          type fauxComponent = {
          reducer: (evt, t('a)) => t('a),
          render: t('a) => ReasonReact.reactElement
          };


          If you try to compile this you'll get an error about an "Unbound type parameter". The difference in error is because it is inferred to be of type ReasonReact.component which has a bunch of type variables, one of which is inferred to have a polymorphic type. The problem is essentially the same, but much easier to illustrate without all the indirection.



          Th technical reason why you can't do this I think is called the value restriction. But there are practical reasons as well. You actually can make this type compile if you explicitly specify 'a as being polymorphic:



          type fauxComponent = {
          reducer: 'a. (evt, t('a)) => t('a),
          render: 'a. t('a) => ReasonReact.reactElement
          };


          This says that 'a can be anything, but that's also the problem. Since it can be anything, you can't know what it is, and you therefore can't really do anything with it other than to have it pass through and returned. You also don't know that 'a is the same in reducer and render, which isn't usually a problem with records since they're not stateful objects. The problem arises because ReasonReact "abuses" them as if they were.



          So how would you then accomplish what you're trying to do? Easy, use a functor! ;) In Reason you can parameterize modules, which are then called functors, and use that to specify the type to use across the entire module. Here's your example functorized:



          module type Config = {
          type t;
          let initialState : t;
          };

          module FunctorComponent(T : Config) {
          type evt =
          | NoOp;

          type t = T.t;

          let component = ReasonReact.reducerComponent("TestComponent");

          let make = _children => {
          ...component,
          initialState: () => T.initialState,
          reducer: (evt, state: t) =>
          switch (evt) {
          | NoOp => ReasonReact.NoUpdate
          },
          render: self => <div> {ReasonReact.string("hello")} </div>,
          };
          };

          module MyComponent = FunctorComponent({
          type t = string;
          let initialState = "hello";
          });

          ReactDOMRe.renderToElementWithId(<MyComponent />, "preview");


          The parameters a functor takes actually need to be modules, so we first define a module type Config, specify that as the parameter type, and then when we create our MyComponent module using the functor we create and pass it an anonymous module that implement the Config module type.



          Now you know why a lot of people think OCaml and Reason's module system is so awesome :) (There's actually a lot more to it, but this is a good start)







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 9 at 10:50









          glennsl

          8,918102645




          8,918102645












          • Whoa! You just blew my mind. Can't try it until tonight, but the upvote is yours.
            – swelet
            Nov 9 at 11:50










          • Thanks once again. Been dabbling with Reason and functional programming in general for a while now but I never had a practical use case for functors until now (atleast not that I know of), so I never got to learning them. Great answer!
            – swelet
            Nov 9 at 22:19


















          • Whoa! You just blew my mind. Can't try it until tonight, but the upvote is yours.
            – swelet
            Nov 9 at 11:50










          • Thanks once again. Been dabbling with Reason and functional programming in general for a while now but I never had a practical use case for functors until now (atleast not that I know of), so I never got to learning them. Great answer!
            – swelet
            Nov 9 at 22:19
















          Whoa! You just blew my mind. Can't try it until tonight, but the upvote is yours.
          – swelet
          Nov 9 at 11:50




          Whoa! You just blew my mind. Can't try it until tonight, but the upvote is yours.
          – swelet
          Nov 9 at 11:50












          Thanks once again. Been dabbling with Reason and functional programming in general for a while now but I never had a practical use case for functors until now (atleast not that I know of), so I never got to learning them. Great answer!
          – swelet
          Nov 9 at 22:19




          Thanks once again. Been dabbling with Reason and functional programming in general for a while now but I never had a practical use case for functors until now (atleast not that I know of), so I never got to learning them. Great answer!
          – swelet
          Nov 9 at 22:19


















           

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