how to get sum between two decimal values in android studio











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I am working with an app android studio - mrate is the rate for 1 km distance and replacetext is the distance between two points and replacing the (km) form the distance - when distance value has decimal value (10.5 )then the system is getting an error



String mykm =dbDistance.getText().toString();

String mrate = dbRate.getText().toString();
System.out.println(mrate);

String replacetext;
replacetext = mykm.replace(" km", "");
System.out.println(replacetext);


//convert value into int
int x=Integer.parseInt(mrate);
int y=Integer.parseInt(replacetext);

//sum these two numbers
int z=x+y;

System.out.println(z);









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  • the system is getting an error -> where is the stacktrace ?
    – 2Dee
    Nov 8 at 8:50










  • 2018-11-08 12:20:19.005 17543-17543/net.atsuae.vehiclebooking I/System.out: 5 2018-11-08 12:20:19.005 17543-17543/net.atsuae.vehiclebooking I/System.out: 2.5 D/AndroidRuntime: Shutting down VM 2018-11-08 12:20:19.007 17543-17543/net.atsuae.vehiclebooking E/AndroidRuntime: FATAL EXCEPTION: main Process: net.atsuae.vehiclebooking, PID: 17543 java.lang.NumberFormatException: For input string: "2.5" at java.lang.Integer.parseInt(Integer.java:608) at java.lang.Integer.parseInt(Integer.java:643) at
    – Solahin Sourjah
    Nov 8 at 8:53










  • you obviously can't store decimal values in int variable. As well as it is obvious that 10.5 can't be parsed into int.
    – Vladyslav Matviienko
    Nov 8 at 9:04










  • NumberFormatException: For input string: "2.5". What Vladyslav said. Please Google your exceptions.
    – 2Dee
    Nov 8 at 9:10















up vote
-2
down vote

favorite












I am working with an app android studio - mrate is the rate for 1 km distance and replacetext is the distance between two points and replacing the (km) form the distance - when distance value has decimal value (10.5 )then the system is getting an error



String mykm =dbDistance.getText().toString();

String mrate = dbRate.getText().toString();
System.out.println(mrate);

String replacetext;
replacetext = mykm.replace(" km", "");
System.out.println(replacetext);


//convert value into int
int x=Integer.parseInt(mrate);
int y=Integer.parseInt(replacetext);

//sum these two numbers
int z=x+y;

System.out.println(z);









share|improve this question
























  • the system is getting an error -> where is the stacktrace ?
    – 2Dee
    Nov 8 at 8:50










  • 2018-11-08 12:20:19.005 17543-17543/net.atsuae.vehiclebooking I/System.out: 5 2018-11-08 12:20:19.005 17543-17543/net.atsuae.vehiclebooking I/System.out: 2.5 D/AndroidRuntime: Shutting down VM 2018-11-08 12:20:19.007 17543-17543/net.atsuae.vehiclebooking E/AndroidRuntime: FATAL EXCEPTION: main Process: net.atsuae.vehiclebooking, PID: 17543 java.lang.NumberFormatException: For input string: "2.5" at java.lang.Integer.parseInt(Integer.java:608) at java.lang.Integer.parseInt(Integer.java:643) at
    – Solahin Sourjah
    Nov 8 at 8:53










  • you obviously can't store decimal values in int variable. As well as it is obvious that 10.5 can't be parsed into int.
    – Vladyslav Matviienko
    Nov 8 at 9:04










  • NumberFormatException: For input string: "2.5". What Vladyslav said. Please Google your exceptions.
    – 2Dee
    Nov 8 at 9:10













up vote
-2
down vote

favorite









up vote
-2
down vote

favorite











I am working with an app android studio - mrate is the rate for 1 km distance and replacetext is the distance between two points and replacing the (km) form the distance - when distance value has decimal value (10.5 )then the system is getting an error



String mykm =dbDistance.getText().toString();

String mrate = dbRate.getText().toString();
System.out.println(mrate);

String replacetext;
replacetext = mykm.replace(" km", "");
System.out.println(replacetext);


//convert value into int
int x=Integer.parseInt(mrate);
int y=Integer.parseInt(replacetext);

//sum these two numbers
int z=x+y;

System.out.println(z);









share|improve this question















I am working with an app android studio - mrate is the rate for 1 km distance and replacetext is the distance between two points and replacing the (km) form the distance - when distance value has decimal value (10.5 )then the system is getting an error



String mykm =dbDistance.getText().toString();

String mrate = dbRate.getText().toString();
System.out.println(mrate);

String replacetext;
replacetext = mykm.replace(" km", "");
System.out.println(replacetext);


//convert value into int
int x=Integer.parseInt(mrate);
int y=Integer.parseInt(replacetext);

//sum these two numbers
int z=x+y;

System.out.println(z);






android android-studio






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share|improve this question













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edited Nov 8 at 9:12









AS Mackay

1,6213816




1,6213816










asked Nov 8 at 8:48









Solahin Sourjah

32




32












  • the system is getting an error -> where is the stacktrace ?
    – 2Dee
    Nov 8 at 8:50










  • 2018-11-08 12:20:19.005 17543-17543/net.atsuae.vehiclebooking I/System.out: 5 2018-11-08 12:20:19.005 17543-17543/net.atsuae.vehiclebooking I/System.out: 2.5 D/AndroidRuntime: Shutting down VM 2018-11-08 12:20:19.007 17543-17543/net.atsuae.vehiclebooking E/AndroidRuntime: FATAL EXCEPTION: main Process: net.atsuae.vehiclebooking, PID: 17543 java.lang.NumberFormatException: For input string: "2.5" at java.lang.Integer.parseInt(Integer.java:608) at java.lang.Integer.parseInt(Integer.java:643) at
    – Solahin Sourjah
    Nov 8 at 8:53










  • you obviously can't store decimal values in int variable. As well as it is obvious that 10.5 can't be parsed into int.
    – Vladyslav Matviienko
    Nov 8 at 9:04










  • NumberFormatException: For input string: "2.5". What Vladyslav said. Please Google your exceptions.
    – 2Dee
    Nov 8 at 9:10


















  • the system is getting an error -> where is the stacktrace ?
    – 2Dee
    Nov 8 at 8:50










  • 2018-11-08 12:20:19.005 17543-17543/net.atsuae.vehiclebooking I/System.out: 5 2018-11-08 12:20:19.005 17543-17543/net.atsuae.vehiclebooking I/System.out: 2.5 D/AndroidRuntime: Shutting down VM 2018-11-08 12:20:19.007 17543-17543/net.atsuae.vehiclebooking E/AndroidRuntime: FATAL EXCEPTION: main Process: net.atsuae.vehiclebooking, PID: 17543 java.lang.NumberFormatException: For input string: "2.5" at java.lang.Integer.parseInt(Integer.java:608) at java.lang.Integer.parseInt(Integer.java:643) at
    – Solahin Sourjah
    Nov 8 at 8:53










  • you obviously can't store decimal values in int variable. As well as it is obvious that 10.5 can't be parsed into int.
    – Vladyslav Matviienko
    Nov 8 at 9:04










  • NumberFormatException: For input string: "2.5". What Vladyslav said. Please Google your exceptions.
    – 2Dee
    Nov 8 at 9:10
















the system is getting an error -> where is the stacktrace ?
– 2Dee
Nov 8 at 8:50




the system is getting an error -> where is the stacktrace ?
– 2Dee
Nov 8 at 8:50












2018-11-08 12:20:19.005 17543-17543/net.atsuae.vehiclebooking I/System.out: 5 2018-11-08 12:20:19.005 17543-17543/net.atsuae.vehiclebooking I/System.out: 2.5 D/AndroidRuntime: Shutting down VM 2018-11-08 12:20:19.007 17543-17543/net.atsuae.vehiclebooking E/AndroidRuntime: FATAL EXCEPTION: main Process: net.atsuae.vehiclebooking, PID: 17543 java.lang.NumberFormatException: For input string: "2.5" at java.lang.Integer.parseInt(Integer.java:608) at java.lang.Integer.parseInt(Integer.java:643) at
– Solahin Sourjah
Nov 8 at 8:53




2018-11-08 12:20:19.005 17543-17543/net.atsuae.vehiclebooking I/System.out: 5 2018-11-08 12:20:19.005 17543-17543/net.atsuae.vehiclebooking I/System.out: 2.5 D/AndroidRuntime: Shutting down VM 2018-11-08 12:20:19.007 17543-17543/net.atsuae.vehiclebooking E/AndroidRuntime: FATAL EXCEPTION: main Process: net.atsuae.vehiclebooking, PID: 17543 java.lang.NumberFormatException: For input string: "2.5" at java.lang.Integer.parseInt(Integer.java:608) at java.lang.Integer.parseInt(Integer.java:643) at
– Solahin Sourjah
Nov 8 at 8:53












you obviously can't store decimal values in int variable. As well as it is obvious that 10.5 can't be parsed into int.
– Vladyslav Matviienko
Nov 8 at 9:04




you obviously can't store decimal values in int variable. As well as it is obvious that 10.5 can't be parsed into int.
– Vladyslav Matviienko
Nov 8 at 9:04












NumberFormatException: For input string: "2.5". What Vladyslav said. Please Google your exceptions.
– 2Dee
Nov 8 at 9:10




NumberFormatException: For input string: "2.5". What Vladyslav said. Please Google your exceptions.
– 2Dee
Nov 8 at 9:10












2 Answers
2






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oldest

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up vote
0
down vote



accepted










You can also use BigDecimal objects for easy conversion and arithmetics



    BigDecimal decimal1 = new BigDecimal("1.024");
BigDecimal decimal2 = new BigDecimal("52.232");
BigDecimal decimal3 = decimal1.add(decimal2);
BigDecimal decimal4 = decimal3.multiply(decimal1);
String newValue = decimal4.toString();


BigDecimal is very powerful especially if you want precision with large decimal places or large numbers in general






share|improve this answer




























    up vote
    1
    down vote













    //convert value into int
    int x=Integer.parseInt(mrate);
    int y=Integer.parseInt(replacetext);


    If you've got decimal values, use Double or Float instead of Integer






    share|improve this answer





















    • yes he have decimals java.lang.NumberFormatException: For input string: "2.5" at java.lang.Integer.parseInt(Integer.java:608)
      – Milos Lulic
      Nov 8 at 9:01










    • Thank you very much. you save my day!
      – Solahin Sourjah
      Nov 8 at 9:08











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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote



    accepted










    You can also use BigDecimal objects for easy conversion and arithmetics



        BigDecimal decimal1 = new BigDecimal("1.024");
    BigDecimal decimal2 = new BigDecimal("52.232");
    BigDecimal decimal3 = decimal1.add(decimal2);
    BigDecimal decimal4 = decimal3.multiply(decimal1);
    String newValue = decimal4.toString();


    BigDecimal is very powerful especially if you want precision with large decimal places or large numbers in general






    share|improve this answer

























      up vote
      0
      down vote



      accepted










      You can also use BigDecimal objects for easy conversion and arithmetics



          BigDecimal decimal1 = new BigDecimal("1.024");
      BigDecimal decimal2 = new BigDecimal("52.232");
      BigDecimal decimal3 = decimal1.add(decimal2);
      BigDecimal decimal4 = decimal3.multiply(decimal1);
      String newValue = decimal4.toString();


      BigDecimal is very powerful especially if you want precision with large decimal places or large numbers in general






      share|improve this answer























        up vote
        0
        down vote



        accepted







        up vote
        0
        down vote



        accepted






        You can also use BigDecimal objects for easy conversion and arithmetics



            BigDecimal decimal1 = new BigDecimal("1.024");
        BigDecimal decimal2 = new BigDecimal("52.232");
        BigDecimal decimal3 = decimal1.add(decimal2);
        BigDecimal decimal4 = decimal3.multiply(decimal1);
        String newValue = decimal4.toString();


        BigDecimal is very powerful especially if you want precision with large decimal places or large numbers in general






        share|improve this answer












        You can also use BigDecimal objects for easy conversion and arithmetics



            BigDecimal decimal1 = new BigDecimal("1.024");
        BigDecimal decimal2 = new BigDecimal("52.232");
        BigDecimal decimal3 = decimal1.add(decimal2);
        BigDecimal decimal4 = decimal3.multiply(decimal1);
        String newValue = decimal4.toString();


        BigDecimal is very powerful especially if you want precision with large decimal places or large numbers in general







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 8 at 9:15









        Brandon

        11018




        11018
























            up vote
            1
            down vote













            //convert value into int
            int x=Integer.parseInt(mrate);
            int y=Integer.parseInt(replacetext);


            If you've got decimal values, use Double or Float instead of Integer






            share|improve this answer





















            • yes he have decimals java.lang.NumberFormatException: For input string: "2.5" at java.lang.Integer.parseInt(Integer.java:608)
              – Milos Lulic
              Nov 8 at 9:01










            • Thank you very much. you save my day!
              – Solahin Sourjah
              Nov 8 at 9:08















            up vote
            1
            down vote













            //convert value into int
            int x=Integer.parseInt(mrate);
            int y=Integer.parseInt(replacetext);


            If you've got decimal values, use Double or Float instead of Integer






            share|improve this answer





















            • yes he have decimals java.lang.NumberFormatException: For input string: "2.5" at java.lang.Integer.parseInt(Integer.java:608)
              – Milos Lulic
              Nov 8 at 9:01










            • Thank you very much. you save my day!
              – Solahin Sourjah
              Nov 8 at 9:08













            up vote
            1
            down vote










            up vote
            1
            down vote









            //convert value into int
            int x=Integer.parseInt(mrate);
            int y=Integer.parseInt(replacetext);


            If you've got decimal values, use Double or Float instead of Integer






            share|improve this answer












            //convert value into int
            int x=Integer.parseInt(mrate);
            int y=Integer.parseInt(replacetext);


            If you've got decimal values, use Double or Float instead of Integer







            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 8 at 8:56









            Bruno

            9261618




            9261618












            • yes he have decimals java.lang.NumberFormatException: For input string: "2.5" at java.lang.Integer.parseInt(Integer.java:608)
              – Milos Lulic
              Nov 8 at 9:01










            • Thank you very much. you save my day!
              – Solahin Sourjah
              Nov 8 at 9:08


















            • yes he have decimals java.lang.NumberFormatException: For input string: "2.5" at java.lang.Integer.parseInt(Integer.java:608)
              – Milos Lulic
              Nov 8 at 9:01










            • Thank you very much. you save my day!
              – Solahin Sourjah
              Nov 8 at 9:08
















            yes he have decimals java.lang.NumberFormatException: For input string: "2.5" at java.lang.Integer.parseInt(Integer.java:608)
            – Milos Lulic
            Nov 8 at 9:01




            yes he have decimals java.lang.NumberFormatException: For input string: "2.5" at java.lang.Integer.parseInt(Integer.java:608)
            – Milos Lulic
            Nov 8 at 9:01












            Thank you very much. you save my day!
            – Solahin Sourjah
            Nov 8 at 9:08




            Thank you very much. you save my day!
            – Solahin Sourjah
            Nov 8 at 9:08


















             

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