Xtykutl

I have following dataframe in pandas

    start_date        start_time        end_time

    2018-01-01        23:55:00          00:05:00

    2018-01-02        00:05:00          00:10:00

    2018-01-03        23:59:00          00:05:00

I want to calculate the time difference. But, for 1st and 3rd observation, there is a date change in end_time.

How can I do it in pandas?

Currently, I am using the logic where end_time is less than start_time I am creating one more column called end_date where it increments the start_date by 1 and then subtracts the time.

Is there any other way to do it?

Solution working with timedeltas - if difference are days equal -1 then add one day:

df['start_time'] = pd.to_timedelta(df['start_time'])

df['end_time'] = pd.to_timedelta(df['end_time'])



d =  df['end_time'] - df['start_time']

df['diff'] = d.mask(d.dt.days == -1, d + pd.Timedelta(1, unit='d'))

print (df)

   start_date start_time end_time     diff

0  2018-01-01   23:55:00 00:05:00 00:10:00

1  2018-01-02   00:05:00 00:10:00 00:05:00

2  2018-01-03   23:59:00 00:05:00 00:06:00

Another solution:

s = df['end_time'] - df['start_time']

df['diff'] = np.where(df['end_time'] < df['start_time'], 

                      s + pd.Timedelta(1, unit='d'), 

                      s)

print (df)



   start_date start_time end_time     diff

0  2018-01-01   23:55:00 00:05:00 00:10:00

1  2018-01-02   00:05:00 00:10:00 00:05:00

2  2018-01-03   23:59:00 00:05:00 00:06:00