How to identify calling method from a called method in swift
up vote
0
down vote
favorite
here is a scenario
func callingMethod_A {
self.someCalculation()
}
func callingMethod_B{
self.someCalculation()
}
func someCalculation{
//how to find who called this method? is it callingMethod_A or _B at runtime?
//bla bla
}
how can we get the method name that called it during run time.
thank you.
ios swift
edited Nov 8 at 13:12
Anbu.karthik
59.1k15121111
asked Nov 8 at 13:03
Pavan Kumar
63
add a comment |
up vote
0
down vote
favorite
here is a scenario
func callingMethod_A {
self.someCalculation()
}
func callingMethod_B{
self.someCalculation()
}
func someCalculation{
//how to find who called this method? is it callingMethod_A or _B at runtime?
//bla bla
}
how can we get the method name that called it during run time.
thank you.
ios swift
edited Nov 8 at 13:12
Anbu.karthik
59.1k15121111
asked Nov 8 at 13:03
Pavan Kumar
63
pass the argument to identify the method
– Anbu.karthik
Nov 8 at 13:09
Add argument, or if it's just for debug purpose, look at the callstack.
– Larme
Nov 8 at 13:10
Larme, how do you look at the call stack in code? Is there a way to get the function signature from the call stack?
– Duncan C
Nov 8 at 13:31
While passing the "caller ID" into a method works, there may well be a better way (delegate, return) to accomplish what you want. Why doessomeCalculationneed to know ifcallingMethod_AorcallingMethod_Bcalled it? What happens when you decide to addcallingMethod_Cor changecallingMethod_Ato be callingMethod_A1`?
– dfd
Nov 8 at 13:31
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
here is a scenario
func callingMethod_A {
self.someCalculation()
}
func callingMethod_B{
self.someCalculation()
}
func someCalculation{
//how to find who called this method? is it callingMethod_A or _B at runtime?
//bla bla
}
how can we get the method name that called it during run time.
thank you.
ios swift
edited Nov 8 at 13:12
Anbu.karthik
59.1k15121111
asked Nov 8 at 13:03
Pavan Kumar
63
here is a scenario
func callingMethod_A {
self.someCalculation()
}
func callingMethod_B{
self.someCalculation()
}
func someCalculation{
//how to find who called this method? is it callingMethod_A or _B at runtime?
//bla bla
}
how can we get the method name that called it during run time.
thank you.
ios swift
ios swift
edited Nov 8 at 13:12
Anbu.karthik
59.1k15121111
asked Nov 8 at 13:03
Pavan Kumar
63
edited Nov 8 at 13:12
Anbu.karthik
59.1k15121111
asked Nov 8 at 13:03
Pavan Kumar
63
edited Nov 8 at 13:12
Anbu.karthik
59.1k15121111
edited Nov 8 at 13:12
Anbu.karthik
59.1k15121111
edited Nov 8 at 13:12
Anbu.karthik
59.1k15121111
59.1k15121111
asked Nov 8 at 13:03
Pavan Kumar
63
asked Nov 8 at 13:03
Pavan Kumar
63
asked Nov 8 at 13:03
Pavan Kumar
63
63
pass the argument to identify the method
– Anbu.karthik
Nov 8 at 13:09
Add argument, or if it's just for debug purpose, look at the callstack.
– Larme
Nov 8 at 13:10
Larme, how do you look at the call stack in code? Is there a way to get the function signature from the call stack?
– Duncan C
Nov 8 at 13:31
While passing the "caller ID" into a method works, there may well be a better way (delegate, return) to accomplish what you want. Why doessomeCalculationneed to know ifcallingMethod_AorcallingMethod_Bcalled it? What happens when you decide to addcallingMethod_Cor changecallingMethod_Ato be callingMethod_A1`?
– dfd
Nov 8 at 13:31
add a comment |
pass the argument to identify the method
– Anbu.karthik
Nov 8 at 13:09
Add argument, or if it's just for debug purpose, look at the callstack.
– Larme
Nov 8 at 13:10
Larme, how do you look at the call stack in code? Is there a way to get the function signature from the call stack?
– Duncan C
Nov 8 at 13:31
While passing the "caller ID" into a method works, there may well be a better way (delegate, return) to accomplish what you want. Why doessomeCalculationneed to know ifcallingMethod_AorcallingMethod_Bcalled it? What happens when you decide to addcallingMethod_Cor changecallingMethod_Ato be callingMethod_A1`?
– dfd
Nov 8 at 13:31
pass the argument to identify the method
– Anbu.karthik
Nov 8 at 13:09
pass the argument to identify the method
– Anbu.karthik
Nov 8 at 13:09
Add argument, or if it's just for debug purpose, look at the callstack.
– Larme
Nov 8 at 13:10
Add argument, or if it's just for debug purpose, look at the callstack.
– Larme
Nov 8 at 13:10
Larme, how do you look at the call stack in code? Is there a way to get the function signature from the call stack?
– Duncan C
Nov 8 at 13:31
Larme, how do you look at the call stack in code? Is there a way to get the function signature from the call stack?
– Duncan C
Nov 8 at 13:31
While passing the "caller ID" into a method works, there may well be a better way (delegate, return) to accomplish what you want. Why does
someCalculation need to know if callingMethod_A or callingMethod_B called it? What happens when you decide to add callingMethod_C or change callingMethod_A to be callingMethod_A1`?– dfd
Nov 8 at 13:31
While passing the "caller ID" into a method works, there may well be a better way (delegate, return) to accomplish what you want. Why does
someCalculation need to know if callingMethod_A or callingMethod_B called it? What happens when you decide to add callingMethod_C or change callingMethod_A to be callingMethod_A1`?– dfd
Nov 8 at 13:31
add a comment |
2 Answers
2
active
oldest
votes
up vote
1
down vote
I worked out a way to do this, for Swift code anyway:
Define a String parameter callingFunction and give it a default value of #function. Do not pass anything from the caller and the compiler provides the calling function name.
Building on @Anu.Krthik's answer:
func someCalculation (parameter: String, callingMethod: String = #function ) {
print("In `(#function)`, called by `(callingMethod)`")
}
func foo(string: String) {
someCalculation(parameter: string)
}
foo(string: "bar")
The above prints
In `someCalculation(parameter:callingMethod:)`, called by `foo(string:)`
However, beware that this technique can be subverted if the caller provides a value for the callingFunction parameter. if you call it with:
func foo(string: String) {
someCalculation(parameter: string, callingMethod: "bogusFunctionName()")
}
You get the output
In `someCalculation(parameter:callingMethod:)`, called by `bogusFunctionName()`
instead.
answered Nov 8 at 13:30
Duncan C
90.6k13112192
add a comment |
up vote
1
down vote
You can use Thread.callStackSymbols like this
func callingMethod_A() {
self.someCalculation()
}
func callingMethod_B(){
self.someCalculation()
}
func someCalculation(){
let origin = Thread.callStackSymbols
print(origin[0])
print(origin[1])
}
answered Nov 8 at 14:06
Raul Mantilla
595
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
I worked out a way to do this, for Swift code anyway:
Define a String parameter callingFunction and give it a default value of #function. Do not pass anything from the caller and the compiler provides the calling function name.
Building on @Anu.Krthik's answer:
func someCalculation (parameter: String, callingMethod: String = #function ) {
print("In `(#function)`, called by `(callingMethod)`")
}
func foo(string: String) {
someCalculation(parameter: string)
}
foo(string: "bar")
The above prints
In `someCalculation(parameter:callingMethod:)`, called by `foo(string:)`
However, beware that this technique can be subverted if the caller provides a value for the callingFunction parameter. if you call it with:
func foo(string: String) {
someCalculation(parameter: string, callingMethod: "bogusFunctionName()")
}
You get the output
In `someCalculation(parameter:callingMethod:)`, called by `bogusFunctionName()`
instead.
answered Nov 8 at 13:30
Duncan C
90.6k13112192
add a comment |
up vote
1
down vote
I worked out a way to do this, for Swift code anyway:
Define a String parameter callingFunction and give it a default value of #function. Do not pass anything from the caller and the compiler provides the calling function name.
Building on @Anu.Krthik's answer:
func someCalculation (parameter: String, callingMethod: String = #function ) {
print("In `(#function)`, called by `(callingMethod)`")
}
func foo(string: String) {
someCalculation(parameter: string)
}
foo(string: "bar")
The above prints
In `someCalculation(parameter:callingMethod:)`, called by `foo(string:)`
However, beware that this technique can be subverted if the caller provides a value for the callingFunction parameter. if you call it with:
func foo(string: String) {
someCalculation(parameter: string, callingMethod: "bogusFunctionName()")
}
You get the output
In `someCalculation(parameter:callingMethod:)`, called by `bogusFunctionName()`
instead.
answered Nov 8 at 13:30
Duncan C
90.6k13112192
add a comment |
up vote
1
down vote
up vote
1
down vote
I worked out a way to do this, for Swift code anyway:
Define a String parameter callingFunction and give it a default value of #function. Do not pass anything from the caller and the compiler provides the calling function name.
Building on @Anu.Krthik's answer:
func someCalculation (parameter: String, callingMethod: String = #function ) {
print("In `(#function)`, called by `(callingMethod)`")
}
func foo(string: String) {
someCalculation(parameter: string)
}
foo(string: "bar")
The above prints
In `someCalculation(parameter:callingMethod:)`, called by `foo(string:)`
However, beware that this technique can be subverted if the caller provides a value for the callingFunction parameter. if you call it with:
func foo(string: String) {
someCalculation(parameter: string, callingMethod: "bogusFunctionName()")
}
You get the output
In `someCalculation(parameter:callingMethod:)`, called by `bogusFunctionName()`
instead.
answered Nov 8 at 13:30
Duncan C
90.6k13112192
I worked out a way to do this, for Swift code anyway:
Define a String parameter callingFunction and give it a default value of #function. Do not pass anything from the caller and the compiler provides the calling function name.
Building on @Anu.Krthik's answer:
func someCalculation (parameter: String, callingMethod: String = #function ) {
print("In `(#function)`, called by `(callingMethod)`")
}
func foo(string: String) {
someCalculation(parameter: string)
}
foo(string: "bar")
The above prints
In `someCalculation(parameter:callingMethod:)`, called by `foo(string:)`
However, beware that this technique can be subverted if the caller provides a value for the callingFunction parameter. if you call it with:
func foo(string: String) {
someCalculation(parameter: string, callingMethod: "bogusFunctionName()")
}
You get the output
In `someCalculation(parameter:callingMethod:)`, called by `bogusFunctionName()`
instead.
answered Nov 8 at 13:30
Duncan C
90.6k13112192
answered Nov 8 at 13:30
Duncan C
90.6k13112192
answered Nov 8 at 13:30
Duncan C
90.6k13112192
answered Nov 8 at 13:30
Duncan C
90.6k13112192
90.6k13112192
add a comment |
add a comment |
up vote
1
down vote
You can use Thread.callStackSymbols like this
func callingMethod_A() {
self.someCalculation()
}
func callingMethod_B(){
self.someCalculation()
}
func someCalculation(){
let origin = Thread.callStackSymbols
print(origin[0])
print(origin[1])
}
answered Nov 8 at 14:06
Raul Mantilla
595
add a comment |
up vote
1
down vote
You can use Thread.callStackSymbols like this
func callingMethod_A() {
self.someCalculation()
}
func callingMethod_B(){
self.someCalculation()
}
func someCalculation(){
let origin = Thread.callStackSymbols
print(origin[0])
print(origin[1])
}
answered Nov 8 at 14:06
Raul Mantilla
595
add a comment |
up vote
1
down vote
up vote
1
down vote
You can use Thread.callStackSymbols like this
func callingMethod_A() {
self.someCalculation()
}
func callingMethod_B(){
self.someCalculation()
}
func someCalculation(){
let origin = Thread.callStackSymbols
print(origin[0])
print(origin[1])
}
answered Nov 8 at 14:06
Raul Mantilla
595
You can use Thread.callStackSymbols like this
func callingMethod_A() {
self.someCalculation()
}
func callingMethod_B(){
self.someCalculation()
}
func someCalculation(){
let origin = Thread.callStackSymbols
print(origin[0])
print(origin[1])
}
answered Nov 8 at 14:06
Raul Mantilla
595
answered Nov 8 at 14:06
Raul Mantilla
595
answered Nov 8 at 14:06
Raul Mantilla
595
answered Nov 8 at 14:06
Raul Mantilla
595
595
add a comment |
add a comment |
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pass the argument to identify the method
– Anbu.karthik
Nov 8 at 13:09
Add argument, or if it's just for debug purpose, look at the callstack.
– Larme
Nov 8 at 13:10
Larme, how do you look at the call stack in code? Is there a way to get the function signature from the call stack?
– Duncan C
Nov 8 at 13:31
While passing the "caller ID" into a method works, there may well be a better way (delegate, return) to accomplish what you want. Why does
someCalculationneed to know ifcallingMethod_AorcallingMethod_Bcalled it? What happens when you decide to addcallingMethod_Cor changecallingMethod_Ato be callingMethod_A1`?– dfd
Nov 8 at 13:31