How to Split Dataset in R with respect to a column containing NA or it consists a value











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I have a got 76 variables and here my Y is Sale Price, I had combined the train and test data to shape the variables now I want to split it again.



project_train_2= filter(project_final,project_final$SalePrice=='NA')

Pro_train=createDataPartition(project_final,project_final[project_train_2,])


Here Project final is the combined Train and test data, which I want to split with respect to the SalesPrice column either having NA or is having a value.
Those having values have to be in Train and the ones not having the test.



I have used the above command to filter data and there by using the CreatedataPartition code to split the data.



Need help on the same.










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  • I assume you are using dplyr::filter (and not stats::filter, for which this will not work); do not use project_file$ inside of it, just do filter(project_final, SalePrice == 'NA'). Furthermore, is it the literal string "NA" or is it R's NA, in which case you'd want filter(project_final, is.na(SalePrice)).
    – r2evans
    Nov 8 at 13:25










  • filter(project_final, is.na(SalePrice)), thanks this worked.
    – Anand Menon
    Nov 8 at 15:12










  • what will be the command to filter SalePrice which has vallues, I am using the following command however it also gets all the rows with NA as well. project_train_2= filter(project_final,is.integer(SalePrice))
    – Anand Menon
    Nov 9 at 7:37












  • You misunderstand data.frames: everything in a column is the same class, so even the NAs in that column will be marked as integer. Do you want filter(project_final, !is.na(SalePrice)), returning all rows that do not have an NA price?
    – r2evans
    Nov 9 at 16:38










  • Background: there are five types of NA, though they are always printed as the basic NA. There are also: NA_integer_ (what you have, likely), NA_real_ (is numeric), NA_complex_, and NA_character_. The basic NA that is not yet associated with strings or numbers will be a logical, so is.logical(NA) is true, not is.logical(c(1,NA)), instead is.numeric(c(1,NA)). The reason is that everything in a vector must be the same class (logical, integer, numeric, character); each column in a (normal) data.frame is a vector internally, so shares the same-class requirement.
    – r2evans
    Nov 9 at 16:42















up vote
0
down vote

favorite












I have a got 76 variables and here my Y is Sale Price, I had combined the train and test data to shape the variables now I want to split it again.



project_train_2= filter(project_final,project_final$SalePrice=='NA')

Pro_train=createDataPartition(project_final,project_final[project_train_2,])


Here Project final is the combined Train and test data, which I want to split with respect to the SalesPrice column either having NA or is having a value.
Those having values have to be in Train and the ones not having the test.



I have used the above command to filter data and there by using the CreatedataPartition code to split the data.



Need help on the same.










share|improve this question
























  • I assume you are using dplyr::filter (and not stats::filter, for which this will not work); do not use project_file$ inside of it, just do filter(project_final, SalePrice == 'NA'). Furthermore, is it the literal string "NA" or is it R's NA, in which case you'd want filter(project_final, is.na(SalePrice)).
    – r2evans
    Nov 8 at 13:25










  • filter(project_final, is.na(SalePrice)), thanks this worked.
    – Anand Menon
    Nov 8 at 15:12










  • what will be the command to filter SalePrice which has vallues, I am using the following command however it also gets all the rows with NA as well. project_train_2= filter(project_final,is.integer(SalePrice))
    – Anand Menon
    Nov 9 at 7:37












  • You misunderstand data.frames: everything in a column is the same class, so even the NAs in that column will be marked as integer. Do you want filter(project_final, !is.na(SalePrice)), returning all rows that do not have an NA price?
    – r2evans
    Nov 9 at 16:38










  • Background: there are five types of NA, though they are always printed as the basic NA. There are also: NA_integer_ (what you have, likely), NA_real_ (is numeric), NA_complex_, and NA_character_. The basic NA that is not yet associated with strings or numbers will be a logical, so is.logical(NA) is true, not is.logical(c(1,NA)), instead is.numeric(c(1,NA)). The reason is that everything in a vector must be the same class (logical, integer, numeric, character); each column in a (normal) data.frame is a vector internally, so shares the same-class requirement.
    – r2evans
    Nov 9 at 16:42













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have a got 76 variables and here my Y is Sale Price, I had combined the train and test data to shape the variables now I want to split it again.



project_train_2= filter(project_final,project_final$SalePrice=='NA')

Pro_train=createDataPartition(project_final,project_final[project_train_2,])


Here Project final is the combined Train and test data, which I want to split with respect to the SalesPrice column either having NA or is having a value.
Those having values have to be in Train and the ones not having the test.



I have used the above command to filter data and there by using the CreatedataPartition code to split the data.



Need help on the same.










share|improve this question















I have a got 76 variables and here my Y is Sale Price, I had combined the train and test data to shape the variables now I want to split it again.



project_train_2= filter(project_final,project_final$SalePrice=='NA')

Pro_train=createDataPartition(project_final,project_final[project_train_2,])


Here Project final is the combined Train and test data, which I want to split with respect to the SalesPrice column either having NA or is having a value.
Those having values have to be in Train and the ones not having the test.



I have used the above command to filter data and there by using the CreatedataPartition code to split the data.



Need help on the same.







r






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edited Nov 8 at 13:22









EstevaoLuis

1,07831727




1,07831727










asked Nov 8 at 13:17









Anand Menon

11




11












  • I assume you are using dplyr::filter (and not stats::filter, for which this will not work); do not use project_file$ inside of it, just do filter(project_final, SalePrice == 'NA'). Furthermore, is it the literal string "NA" or is it R's NA, in which case you'd want filter(project_final, is.na(SalePrice)).
    – r2evans
    Nov 8 at 13:25










  • filter(project_final, is.na(SalePrice)), thanks this worked.
    – Anand Menon
    Nov 8 at 15:12










  • what will be the command to filter SalePrice which has vallues, I am using the following command however it also gets all the rows with NA as well. project_train_2= filter(project_final,is.integer(SalePrice))
    – Anand Menon
    Nov 9 at 7:37












  • You misunderstand data.frames: everything in a column is the same class, so even the NAs in that column will be marked as integer. Do you want filter(project_final, !is.na(SalePrice)), returning all rows that do not have an NA price?
    – r2evans
    Nov 9 at 16:38










  • Background: there are five types of NA, though they are always printed as the basic NA. There are also: NA_integer_ (what you have, likely), NA_real_ (is numeric), NA_complex_, and NA_character_. The basic NA that is not yet associated with strings or numbers will be a logical, so is.logical(NA) is true, not is.logical(c(1,NA)), instead is.numeric(c(1,NA)). The reason is that everything in a vector must be the same class (logical, integer, numeric, character); each column in a (normal) data.frame is a vector internally, so shares the same-class requirement.
    – r2evans
    Nov 9 at 16:42


















  • I assume you are using dplyr::filter (and not stats::filter, for which this will not work); do not use project_file$ inside of it, just do filter(project_final, SalePrice == 'NA'). Furthermore, is it the literal string "NA" or is it R's NA, in which case you'd want filter(project_final, is.na(SalePrice)).
    – r2evans
    Nov 8 at 13:25










  • filter(project_final, is.na(SalePrice)), thanks this worked.
    – Anand Menon
    Nov 8 at 15:12










  • what will be the command to filter SalePrice which has vallues, I am using the following command however it also gets all the rows with NA as well. project_train_2= filter(project_final,is.integer(SalePrice))
    – Anand Menon
    Nov 9 at 7:37












  • You misunderstand data.frames: everything in a column is the same class, so even the NAs in that column will be marked as integer. Do you want filter(project_final, !is.na(SalePrice)), returning all rows that do not have an NA price?
    – r2evans
    Nov 9 at 16:38










  • Background: there are five types of NA, though they are always printed as the basic NA. There are also: NA_integer_ (what you have, likely), NA_real_ (is numeric), NA_complex_, and NA_character_. The basic NA that is not yet associated with strings or numbers will be a logical, so is.logical(NA) is true, not is.logical(c(1,NA)), instead is.numeric(c(1,NA)). The reason is that everything in a vector must be the same class (logical, integer, numeric, character); each column in a (normal) data.frame is a vector internally, so shares the same-class requirement.
    – r2evans
    Nov 9 at 16:42
















I assume you are using dplyr::filter (and not stats::filter, for which this will not work); do not use project_file$ inside of it, just do filter(project_final, SalePrice == 'NA'). Furthermore, is it the literal string "NA" or is it R's NA, in which case you'd want filter(project_final, is.na(SalePrice)).
– r2evans
Nov 8 at 13:25




I assume you are using dplyr::filter (and not stats::filter, for which this will not work); do not use project_file$ inside of it, just do filter(project_final, SalePrice == 'NA'). Furthermore, is it the literal string "NA" or is it R's NA, in which case you'd want filter(project_final, is.na(SalePrice)).
– r2evans
Nov 8 at 13:25












filter(project_final, is.na(SalePrice)), thanks this worked.
– Anand Menon
Nov 8 at 15:12




filter(project_final, is.na(SalePrice)), thanks this worked.
– Anand Menon
Nov 8 at 15:12












what will be the command to filter SalePrice which has vallues, I am using the following command however it also gets all the rows with NA as well. project_train_2= filter(project_final,is.integer(SalePrice))
– Anand Menon
Nov 9 at 7:37






what will be the command to filter SalePrice which has vallues, I am using the following command however it also gets all the rows with NA as well. project_train_2= filter(project_final,is.integer(SalePrice))
– Anand Menon
Nov 9 at 7:37














You misunderstand data.frames: everything in a column is the same class, so even the NAs in that column will be marked as integer. Do you want filter(project_final, !is.na(SalePrice)), returning all rows that do not have an NA price?
– r2evans
Nov 9 at 16:38




You misunderstand data.frames: everything in a column is the same class, so even the NAs in that column will be marked as integer. Do you want filter(project_final, !is.na(SalePrice)), returning all rows that do not have an NA price?
– r2evans
Nov 9 at 16:38












Background: there are five types of NA, though they are always printed as the basic NA. There are also: NA_integer_ (what you have, likely), NA_real_ (is numeric), NA_complex_, and NA_character_. The basic NA that is not yet associated with strings or numbers will be a logical, so is.logical(NA) is true, not is.logical(c(1,NA)), instead is.numeric(c(1,NA)). The reason is that everything in a vector must be the same class (logical, integer, numeric, character); each column in a (normal) data.frame is a vector internally, so shares the same-class requirement.
– r2evans
Nov 9 at 16:42




Background: there are five types of NA, though they are always printed as the basic NA. There are also: NA_integer_ (what you have, likely), NA_real_ (is numeric), NA_complex_, and NA_character_. The basic NA that is not yet associated with strings or numbers will be a logical, so is.logical(NA) is true, not is.logical(c(1,NA)), instead is.numeric(c(1,NA)). The reason is that everything in a vector must be the same class (logical, integer, numeric, character); each column in a (normal) data.frame is a vector internally, so shares the same-class requirement.
– r2evans
Nov 9 at 16:42

















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