Slice of struct can't be plugged into slice of interface in golang [duplicate]
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This question already has an answer here:
golang: slice of struct != slice of interface it implements?
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I have Tag struct and TableAbstruct interface like below example.
[Tag struct]
type Tag struct {
Id int `db:"id"`
Name string `db:"Name"`
}
func (tag Tag) Serialize() string {
...
}
[TableAbstruct interface]
type TableAbstruct interface {
Serialize() string
}
Xxx() function returns TableAbstruct, but actual type is Tag. And below program will work well because Tag includes TableAbstruct interface.
func Xxx() TableAbstruct {
result := TableAbstruct{}
for i := 0; i < 10; i++ {
table_obj := Tag{}
result = append(result, table_obj)
}
return result
}
But I want to write like below and I couldn't. I think the problem is TypeError. But I couldn't understand why the error has occurred.
func Xxx() TableAbstruct {
result := Tag{}
return result
}
go asked Nov 9 at 3:46
mk-tool
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Nov 9 at 6:02
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
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up vote
0
down vote
favorite
This question already has an answer here:
golang: slice of struct != slice of interface it implements?
5 answers
I have Tag struct and TableAbstruct interface like below example.
[Tag struct]
type Tag struct {
Id int `db:"id"`
Name string `db:"Name"`
}
func (tag Tag) Serialize() string {
...
}
[TableAbstruct interface]
type TableAbstruct interface {
Serialize() string
}
Xxx() function returns TableAbstruct, but actual type is Tag. And below program will work well because Tag includes TableAbstruct interface.
func Xxx() TableAbstruct {
result := TableAbstruct{}
for i := 0; i < 10; i++ {
table_obj := Tag{}
result = append(result, table_obj)
}
return result
}
But I want to write like below and I couldn't. I think the problem is TypeError. But I couldn't understand why the error has occurred.
func Xxx() TableAbstruct {
result := Tag{}
return result
}
asked Nov 9 at 3:46
mk-tool
315
marked as duplicate by Volker go
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Nov 9 at 6:02
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up vote
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down vote
favorite
up vote
0
down vote
favorite
This question already has an answer here:
golang: slice of struct != slice of interface it implements?
5 answers
I have Tag struct and TableAbstruct interface like below example.
[Tag struct]
type Tag struct {
Id int `db:"id"`
Name string `db:"Name"`
}
func (tag Tag) Serialize() string {
...
}
[TableAbstruct interface]
type TableAbstruct interface {
Serialize() string
}
Xxx() function returns TableAbstruct, but actual type is Tag. And below program will work well because Tag includes TableAbstruct interface.
func Xxx() TableAbstruct {
result := TableAbstruct{}
for i := 0; i < 10; i++ {
table_obj := Tag{}
result = append(result, table_obj)
}
return result
}
But I want to write like below and I couldn't. I think the problem is TypeError. But I couldn't understand why the error has occurred.
func Xxx() TableAbstruct {
result := Tag{}
return result
}
asked Nov 9 at 3:46
mk-tool
315
This question already has an answer here:
golang: slice of struct != slice of interface it implements?
5 answers
I have Tag struct and TableAbstruct interface like below example.
[Tag struct]
type Tag struct {
Id int `db:"id"`
Name string `db:"Name"`
}
func (tag Tag) Serialize() string {
...
}
[TableAbstruct interface]
type TableAbstruct interface {
Serialize() string
}
Xxx() function returns TableAbstruct, but actual type is Tag. And below program will work well because Tag includes TableAbstruct interface.
func Xxx() TableAbstruct {
result := TableAbstruct{}
for i := 0; i < 10; i++ {
table_obj := Tag{}
result = append(result, table_obj)
}
return result
}
But I want to write like below and I couldn't. I think the problem is TypeError. But I couldn't understand why the error has occurred.
func Xxx() TableAbstruct {
result := Tag{}
return result
}
This question already has an answer here:
golang: slice of struct != slice of interface it implements?
5 answers
go go asked Nov 9 at 3:46
mk-tool
315
asked Nov 9 at 3:46
mk-tool
315
asked Nov 9 at 3:46
mk-tool
315
asked Nov 9 at 3:46
mk-tool
315
asked Nov 9 at 3:46
mk-tool
315
315
marked as duplicate by Volker go
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Nov 9 at 6:02
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1 Answer
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Go does not have any fanciness around slices and types. Put simply, if you say you are going to return TableAbstruct, you have to return that exactly. So if you want to return a Tag, you have to create a slice of TableAbstruct and then go populate it manually:
func Xxx() TableAbstruct {
var returnValue TableAbstruct
for _, t := range result {
returnValue = append(returnValue, t)
}
return returnValue
}
answered Nov 9 at 4:29
poy
5,61753262
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
Go does not have any fanciness around slices and types. Put simply, if you say you are going to return TableAbstruct, you have to return that exactly. So if you want to return a Tag, you have to create a slice of TableAbstruct and then go populate it manually:
func Xxx() TableAbstruct {
var returnValue TableAbstruct
for _, t := range result {
returnValue = append(returnValue, t)
}
return returnValue
}
answered Nov 9 at 4:29
poy
5,61753262
add a comment |
up vote
1
down vote
accepted
Go does not have any fanciness around slices and types. Put simply, if you say you are going to return TableAbstruct, you have to return that exactly. So if you want to return a Tag, you have to create a slice of TableAbstruct and then go populate it manually:
func Xxx() TableAbstruct {
var returnValue TableAbstruct
for _, t := range result {
returnValue = append(returnValue, t)
}
return returnValue
}
answered Nov 9 at 4:29
poy
5,61753262
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
Go does not have any fanciness around slices and types. Put simply, if you say you are going to return TableAbstruct, you have to return that exactly. So if you want to return a Tag, you have to create a slice of TableAbstruct and then go populate it manually:
func Xxx() TableAbstruct {
var returnValue TableAbstruct
for _, t := range result {
returnValue = append(returnValue, t)
}
return returnValue
}
answered Nov 9 at 4:29
poy
5,61753262
Go does not have any fanciness around slices and types. Put simply, if you say you are going to return TableAbstruct, you have to return that exactly. So if you want to return a Tag, you have to create a slice of TableAbstruct and then go populate it manually:
func Xxx() TableAbstruct {
var returnValue TableAbstruct
for _, t := range result {
returnValue = append(returnValue, t)
}
return returnValue
}
answered Nov 9 at 4:29
poy
5,61753262
answered Nov 9 at 4:29
poy
5,61753262
answered Nov 9 at 4:29
poy
5,61753262
answered Nov 9 at 4:29
poy
5,61753262
5,61753262
add a comment |
add a comment |
