Pandas Dataframe - select columns with a specific value in a specific row
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1
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I want to select columns with a specific value (say 1) in a specific row (say first row) for Pandas Dataframe
python pandas dataframe
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up vote
1
down vote
favorite
I want to select columns with a specific value (say 1) in a specific row (say first row) for Pandas Dataframe
python pandas dataframe
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I want to select columns with a specific value (say 1) in a specific row (say first row) for Pandas Dataframe
python pandas dataframe
I want to select columns with a specific value (say 1) in a specific row (say first row) for Pandas Dataframe
python pandas dataframe
python pandas dataframe
asked Nov 8 at 11:09
ghos-h
718717
718717
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add a comment |
2 Answers
2
active
oldest
votes
up vote
0
down vote
accepted
Use iloc
with boolean indexing
, for performance is better filtering index
not DataFrame
and then select index (see performance):
df = pd.DataFrame({
'A':list('abcdef'),
'B':[4,5,4,5,5,4],
'C':[7,8,9,4,2,3],
'D':[1,3,5,7,1,0],
'E':[5,3,6,9,2,4],
'F':list('aaabbb')
})
print (df)
A B C D E F
0 a 4 7 1 5 a
1 b 5 8 3 3 a
2 c 4 9 5 6 a
3 d 5 4 7 9 b
4 e 5 2 1 2 b
5 f 4 3 0 4 b
s = df.iloc[0]
a = s.index[s == 1]
print (a)
Index(['D'], dtype='object')
a = s.index.values[(s == 1)]
print (a)
['D']
add a comment |
up vote
0
down vote
You can use iloc
to extract a row as a series, then apply your condition:
row = df.iloc[0] # extract first row as series
res = row[res == 1].index # filter for values equal to 1 and get columns via index
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
Use iloc
with boolean indexing
, for performance is better filtering index
not DataFrame
and then select index (see performance):
df = pd.DataFrame({
'A':list('abcdef'),
'B':[4,5,4,5,5,4],
'C':[7,8,9,4,2,3],
'D':[1,3,5,7,1,0],
'E':[5,3,6,9,2,4],
'F':list('aaabbb')
})
print (df)
A B C D E F
0 a 4 7 1 5 a
1 b 5 8 3 3 a
2 c 4 9 5 6 a
3 d 5 4 7 9 b
4 e 5 2 1 2 b
5 f 4 3 0 4 b
s = df.iloc[0]
a = s.index[s == 1]
print (a)
Index(['D'], dtype='object')
a = s.index.values[(s == 1)]
print (a)
['D']
add a comment |
up vote
0
down vote
accepted
Use iloc
with boolean indexing
, for performance is better filtering index
not DataFrame
and then select index (see performance):
df = pd.DataFrame({
'A':list('abcdef'),
'B':[4,5,4,5,5,4],
'C':[7,8,9,4,2,3],
'D':[1,3,5,7,1,0],
'E':[5,3,6,9,2,4],
'F':list('aaabbb')
})
print (df)
A B C D E F
0 a 4 7 1 5 a
1 b 5 8 3 3 a
2 c 4 9 5 6 a
3 d 5 4 7 9 b
4 e 5 2 1 2 b
5 f 4 3 0 4 b
s = df.iloc[0]
a = s.index[s == 1]
print (a)
Index(['D'], dtype='object')
a = s.index.values[(s == 1)]
print (a)
['D']
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
Use iloc
with boolean indexing
, for performance is better filtering index
not DataFrame
and then select index (see performance):
df = pd.DataFrame({
'A':list('abcdef'),
'B':[4,5,4,5,5,4],
'C':[7,8,9,4,2,3],
'D':[1,3,5,7,1,0],
'E':[5,3,6,9,2,4],
'F':list('aaabbb')
})
print (df)
A B C D E F
0 a 4 7 1 5 a
1 b 5 8 3 3 a
2 c 4 9 5 6 a
3 d 5 4 7 9 b
4 e 5 2 1 2 b
5 f 4 3 0 4 b
s = df.iloc[0]
a = s.index[s == 1]
print (a)
Index(['D'], dtype='object')
a = s.index.values[(s == 1)]
print (a)
['D']
Use iloc
with boolean indexing
, for performance is better filtering index
not DataFrame
and then select index (see performance):
df = pd.DataFrame({
'A':list('abcdef'),
'B':[4,5,4,5,5,4],
'C':[7,8,9,4,2,3],
'D':[1,3,5,7,1,0],
'E':[5,3,6,9,2,4],
'F':list('aaabbb')
})
print (df)
A B C D E F
0 a 4 7 1 5 a
1 b 5 8 3 3 a
2 c 4 9 5 6 a
3 d 5 4 7 9 b
4 e 5 2 1 2 b
5 f 4 3 0 4 b
s = df.iloc[0]
a = s.index[s == 1]
print (a)
Index(['D'], dtype='object')
a = s.index.values[(s == 1)]
print (a)
['D']
edited Nov 8 at 11:27
answered Nov 8 at 11:16
jezrael
306k20240316
306k20240316
add a comment |
add a comment |
up vote
0
down vote
You can use iloc
to extract a row as a series, then apply your condition:
row = df.iloc[0] # extract first row as series
res = row[res == 1].index # filter for values equal to 1 and get columns via index
add a comment |
up vote
0
down vote
You can use iloc
to extract a row as a series, then apply your condition:
row = df.iloc[0] # extract first row as series
res = row[res == 1].index # filter for values equal to 1 and get columns via index
add a comment |
up vote
0
down vote
up vote
0
down vote
You can use iloc
to extract a row as a series, then apply your condition:
row = df.iloc[0] # extract first row as series
res = row[res == 1].index # filter for values equal to 1 and get columns via index
You can use iloc
to extract a row as a series, then apply your condition:
row = df.iloc[0] # extract first row as series
res = row[res == 1].index # filter for values equal to 1 and get columns via index
answered Nov 8 at 11:14
jpp
81.7k194795
81.7k194795
add a comment |
add a comment |
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