How can I calculate the sum of comma separated in the 2nd column











up vote
2
down vote

favorite












sm_agg
Group.1 x
1 1001 8
2 1002 16, 8
3 1003 8
4 1004 16
5 1005 5.33333333333333, 8
6 1006 4
7 1007 4
8 1008 4
9 1009 5.33333333333333
10 1010 8, 5.33333333333333
11 1011 8, 4
12 1012 5.33333333333333
13 1013 5.33333333333333, 8
14 1014 8
15 1015 5.33333333333333
16 1016 5.33333333333333


I want to get like this



sm_agg
Group.1 x
1 1001 8
2 1002 24
3 1003 8
4 1004 16
5 1005 13.3
6 1006 4
7 1007 4
8 1008 4
9 1009 5.33333333333333
10 1010 13.3
11 1011 12
12 1012 5.33333333333333
13 1013 13.3
14 1014 8
15 1015 5.33333333333333
16 1016 5.33333333333333









share|improve this question




























    up vote
    2
    down vote

    favorite












    sm_agg
    Group.1 x
    1 1001 8
    2 1002 16, 8
    3 1003 8
    4 1004 16
    5 1005 5.33333333333333, 8
    6 1006 4
    7 1007 4
    8 1008 4
    9 1009 5.33333333333333
    10 1010 8, 5.33333333333333
    11 1011 8, 4
    12 1012 5.33333333333333
    13 1013 5.33333333333333, 8
    14 1014 8
    15 1015 5.33333333333333
    16 1016 5.33333333333333


    I want to get like this



    sm_agg
    Group.1 x
    1 1001 8
    2 1002 24
    3 1003 8
    4 1004 16
    5 1005 13.3
    6 1006 4
    7 1007 4
    8 1008 4
    9 1009 5.33333333333333
    10 1010 13.3
    11 1011 12
    12 1012 5.33333333333333
    13 1013 13.3
    14 1014 8
    15 1015 5.33333333333333
    16 1016 5.33333333333333









    share|improve this question


























      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      sm_agg
      Group.1 x
      1 1001 8
      2 1002 16, 8
      3 1003 8
      4 1004 16
      5 1005 5.33333333333333, 8
      6 1006 4
      7 1007 4
      8 1008 4
      9 1009 5.33333333333333
      10 1010 8, 5.33333333333333
      11 1011 8, 4
      12 1012 5.33333333333333
      13 1013 5.33333333333333, 8
      14 1014 8
      15 1015 5.33333333333333
      16 1016 5.33333333333333


      I want to get like this



      sm_agg
      Group.1 x
      1 1001 8
      2 1002 24
      3 1003 8
      4 1004 16
      5 1005 13.3
      6 1006 4
      7 1007 4
      8 1008 4
      9 1009 5.33333333333333
      10 1010 13.3
      11 1011 12
      12 1012 5.33333333333333
      13 1013 13.3
      14 1014 8
      15 1015 5.33333333333333
      16 1016 5.33333333333333









      share|improve this question















      sm_agg
      Group.1 x
      1 1001 8
      2 1002 16, 8
      3 1003 8
      4 1004 16
      5 1005 5.33333333333333, 8
      6 1006 4
      7 1007 4
      8 1008 4
      9 1009 5.33333333333333
      10 1010 8, 5.33333333333333
      11 1011 8, 4
      12 1012 5.33333333333333
      13 1013 5.33333333333333, 8
      14 1014 8
      15 1015 5.33333333333333
      16 1016 5.33333333333333


      I want to get like this



      sm_agg
      Group.1 x
      1 1001 8
      2 1002 24
      3 1003 8
      4 1004 16
      5 1005 13.3
      6 1006 4
      7 1007 4
      8 1008 4
      9 1009 5.33333333333333
      10 1010 13.3
      11 1011 12
      12 1012 5.33333333333333
      13 1013 13.3
      14 1014 8
      15 1015 5.33333333333333
      16 1016 5.33333333333333






      r






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 10 at 5:50









      Ronak Shah

      30.4k103753




      30.4k103753










      asked Nov 10 at 5:06









      Kiran Pg

      228




      228
























          3 Answers
          3






          active

          oldest

          votes

















          up vote
          1
          down vote



          accepted










          Try this:



          sm_agg$x <- sapply(strsplit(sm_agg$x, "[ ,]+"), function(i) sum(as.numeric(i)))
          sm_agg
          # Group.1 x
          # 1 1001 8.000000
          # 2 1002 24.000000
          # 3 1003 8.000000
          # 4 1004 16.000000
          # 5 1005 13.333333
          # 6 1006 4.000000
          # 7 1007 4.000000
          # 8 1008 4.000000
          # 9 1009 5.333333
          # 10 1010 13.333333
          # 11 1011 12.000000
          # 12 1012 5.333333
          # 13 1013 13.333333
          # 14 1014 8.000000
          # 15 1015 5.333333
          # 16 1016 5.333333


          Explanation:





          1. For a single entry, we split it by one or more commas/spaces:



            strsplit(sm_agg$x[2], "[, ]+")
            # [[1]]
            # [1] "16" "8"



          2. With that, we want to convert to numbers and add, so



            as.numeric(strsplit(sm_agg$x[2], "[, ]+")[[1]])
            # [1] 16 8
            sum(as.numeric(strsplit(sm_agg$x[2], "[, ]+")[[1]]))
            # [1] 24


          3. We want to do that for every element, so we instead feed the strsplit output into an sapply anon-function.





          If your frame has factors instead of strings, then instead use



          sapply(strsplit(as.character(sm_agg$x), "[ ,]+"), function(i) sum(as.numeric(i)))




          Last Edit



          I think your data is actually an embedded list. When data contains a list-column, it presents like that (which I find a little frustrating, but still ...).



          I'll generate some fake data to demonstrate what I think you actually have:



          sm2 <- data.frame(Group.1 = c("1001", "1002", "1003", "1005"))
          sm2$x <- list(c(8L), c(16L,8L), c(8L), c(16/3, 8))
          sm2
          # Group.1 x
          # 1 1001 8
          # 2 1002 16, 8
          # 3 1003 8
          # 4 1005 5.333333, 8.000000


          Okay. When we tried strsplit and even as.character, things break and are obviously not number-like:



          as.character(sm2$x)
          # [1] "8" "c(16, 8)" "8"
          # [4] "c(5.33333333333333, 8)"


          When in fact, all we have to do is just sum them up, because they're already numbers.



          sapply(sm2$x, sum)
          # [1] 8.00000 24.00000 8.00000 13.33333


          If by chance one of the nested things is actually a character:



          sm2$y <- list(c("8"), c(16L,8L), c(8L), c(16/3, 8))
          sm2
          # Group.1 x y
          # 1 1001 8 8
          # 2 1002 16, 8 16, 8
          # 3 1003 8 8
          # 4 1005 5.333333, 8.000000 5.333333, 8.000000


          which will cause our "simple" solution to fail.



          sapply(sm2$y, sum)
          # Error in FUN(X[[i]], ...) : invalid 'type' (character) of argument


          Luckily, we can be a bit over-handed and force strings to numbers, and numbers to numbers:



          sapply(sm2$y, function(i) sum(as.numeric(i)))
          # [1] 8.00000 24.00000 8.00000 13.33333
          sapply(sm2$x, function(i) sum(as.numeric(i)))
          # [1] 8.00000 24.00000 8.00000 13.33333





          share|improve this answer























          • when i apply this i got error > as.numeric(strsplit(sm_agg$x[2], "[, ]+")[[1]]) Error in strsplit(sm_agg$x[2], "[, ]+") : non-character argument > sm_agg$x <- sapply(strsplit(sm_agg$x, "[ ,]+"), function(i) sum(as.numeric(i))) Error in strsplit(sm_agg$x, "[ ,]+") : non-character argument >
            – Kiran Pg
            Nov 10 at 5:33








          • 1




            You have factors in your data. In the future, presenting your data in an unambiguous way such as dput(head(sm_agg)) would have prevented this. See my edit for the workaround.
            – r2evans
            Nov 10 at 5:38










          • >sapply(strsplit(as.character(sm_agg$x), "[,]+"), function(i) sum(as.numeric(i))) [1] 8.000000 NA 8.000000 16.000000 NA 4.000000 4.000000 4.000000 5.333333 NA [11] NA 5.333333 NA 8.000000 5.333333 5.333333
            – Kiran Pg
            Nov 10 at 5:57










          • You forgot the space in the pattern. That space is not an accident or a "code style preference". If you want to be even clearer, replace "[ ,]+" (notice the space, total of five chars within the quotes) with "[\s,]+" (no space here, the \s includes spaces and tabs).
            – r2evans
            Nov 10 at 6:05








          • 1




            You can accept it by clicking on the check mark next to vote button.
            – Ronak Shah
            Nov 10 at 11:50


















          up vote
          1
          down vote













          We can use separate_rows to separate comma-separated enteries into different rows and then sum by group.



          library(tidyverse)
          df %>%
          separate_rows(x, sep = ",") %>%
          group_by(Group.1) %>%
          summarise(x = sum(as.numeric(x)))


          # Group.1 x
          # <dbl> <dbl>
          # 1 1001 8
          # 2 1002 24
          # 3 1003 8
          # 4 1004 16
          # 5 1005 13.3
          # 6 1006 4
          # 7 1007 4
          # 8 1008 4
          # 9 1009 5.33
          #10 1010 13.3
          #11 1011 12
          #12 1012 5.33
          #13 1013 13.3
          #14 1014 8
          #15 1015 5.33
          #16 1016 5.33


          data



          df <- structure(list(Group.1 = c(1001, 1002, 1003, 1004, 1005, 1006, 
          1007, 1008, 1009, 1010, 1011, 1012, 1013, 1014, 1015, 1016),
          x = structure(c(5L, 7L, 5L, 6L, 10L, 2L, 1L, 1L, 9L, 11L,
          4L, 8L, 10L, 3L, 8L, 8L), .Label = c(" 4",
          " 4", " 8", " 8, 4",
          " 8", " 16", " 16, 8", " 5.33333333333333",
          " 5.33333333333333", " 5.33333333333333, 8", " 8, 5.33333333333333"
          ), class = "factor")), .Names = c("Group.1", "x"), class =
          "data.frame", row.names = c(NA,
          -16L))





          share|improve this answer




























            up vote
            0
            down vote













            using this method i get asnwer sapply(sm2$y, function(i) sum(as.numeric(i)))






            share|improve this answer























              Your Answer






              StackExchange.ifUsing("editor", function () {
              StackExchange.using("externalEditor", function () {
              StackExchange.using("snippets", function () {
              StackExchange.snippets.init();
              });
              });
              }, "code-snippets");

              StackExchange.ready(function() {
              var channelOptions = {
              tags: "".split(" "),
              id: "1"
              };
              initTagRenderer("".split(" "), "".split(" "), channelOptions);

              StackExchange.using("externalEditor", function() {
              // Have to fire editor after snippets, if snippets enabled
              if (StackExchange.settings.snippets.snippetsEnabled) {
              StackExchange.using("snippets", function() {
              createEditor();
              });
              }
              else {
              createEditor();
              }
              });

              function createEditor() {
              StackExchange.prepareEditor({
              heartbeatType: 'answer',
              convertImagesToLinks: true,
              noModals: true,
              showLowRepImageUploadWarning: true,
              reputationToPostImages: 10,
              bindNavPrevention: true,
              postfix: "",
              imageUploader: {
              brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
              contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
              allowUrls: true
              },
              onDemand: true,
              discardSelector: ".discard-answer"
              ,immediatelyShowMarkdownHelp:true
              });


              }
              });














              draft saved

              draft discarded


















              StackExchange.ready(
              function () {
              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53236148%2fhow-can-i-calculate-the-sum-of-comma-separated-in-the-2nd-column%23new-answer', 'question_page');
              }
              );

              Post as a guest















              Required, but never shown

























              3 Answers
              3






              active

              oldest

              votes








              3 Answers
              3






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes








              up vote
              1
              down vote



              accepted










              Try this:



              sm_agg$x <- sapply(strsplit(sm_agg$x, "[ ,]+"), function(i) sum(as.numeric(i)))
              sm_agg
              # Group.1 x
              # 1 1001 8.000000
              # 2 1002 24.000000
              # 3 1003 8.000000
              # 4 1004 16.000000
              # 5 1005 13.333333
              # 6 1006 4.000000
              # 7 1007 4.000000
              # 8 1008 4.000000
              # 9 1009 5.333333
              # 10 1010 13.333333
              # 11 1011 12.000000
              # 12 1012 5.333333
              # 13 1013 13.333333
              # 14 1014 8.000000
              # 15 1015 5.333333
              # 16 1016 5.333333


              Explanation:





              1. For a single entry, we split it by one or more commas/spaces:



                strsplit(sm_agg$x[2], "[, ]+")
                # [[1]]
                # [1] "16" "8"



              2. With that, we want to convert to numbers and add, so



                as.numeric(strsplit(sm_agg$x[2], "[, ]+")[[1]])
                # [1] 16 8
                sum(as.numeric(strsplit(sm_agg$x[2], "[, ]+")[[1]]))
                # [1] 24


              3. We want to do that for every element, so we instead feed the strsplit output into an sapply anon-function.





              If your frame has factors instead of strings, then instead use



              sapply(strsplit(as.character(sm_agg$x), "[ ,]+"), function(i) sum(as.numeric(i)))




              Last Edit



              I think your data is actually an embedded list. When data contains a list-column, it presents like that (which I find a little frustrating, but still ...).



              I'll generate some fake data to demonstrate what I think you actually have:



              sm2 <- data.frame(Group.1 = c("1001", "1002", "1003", "1005"))
              sm2$x <- list(c(8L), c(16L,8L), c(8L), c(16/3, 8))
              sm2
              # Group.1 x
              # 1 1001 8
              # 2 1002 16, 8
              # 3 1003 8
              # 4 1005 5.333333, 8.000000


              Okay. When we tried strsplit and even as.character, things break and are obviously not number-like:



              as.character(sm2$x)
              # [1] "8" "c(16, 8)" "8"
              # [4] "c(5.33333333333333, 8)"


              When in fact, all we have to do is just sum them up, because they're already numbers.



              sapply(sm2$x, sum)
              # [1] 8.00000 24.00000 8.00000 13.33333


              If by chance one of the nested things is actually a character:



              sm2$y <- list(c("8"), c(16L,8L), c(8L), c(16/3, 8))
              sm2
              # Group.1 x y
              # 1 1001 8 8
              # 2 1002 16, 8 16, 8
              # 3 1003 8 8
              # 4 1005 5.333333, 8.000000 5.333333, 8.000000


              which will cause our "simple" solution to fail.



              sapply(sm2$y, sum)
              # Error in FUN(X[[i]], ...) : invalid 'type' (character) of argument


              Luckily, we can be a bit over-handed and force strings to numbers, and numbers to numbers:



              sapply(sm2$y, function(i) sum(as.numeric(i)))
              # [1] 8.00000 24.00000 8.00000 13.33333
              sapply(sm2$x, function(i) sum(as.numeric(i)))
              # [1] 8.00000 24.00000 8.00000 13.33333





              share|improve this answer























              • when i apply this i got error > as.numeric(strsplit(sm_agg$x[2], "[, ]+")[[1]]) Error in strsplit(sm_agg$x[2], "[, ]+") : non-character argument > sm_agg$x <- sapply(strsplit(sm_agg$x, "[ ,]+"), function(i) sum(as.numeric(i))) Error in strsplit(sm_agg$x, "[ ,]+") : non-character argument >
                – Kiran Pg
                Nov 10 at 5:33








              • 1




                You have factors in your data. In the future, presenting your data in an unambiguous way such as dput(head(sm_agg)) would have prevented this. See my edit for the workaround.
                – r2evans
                Nov 10 at 5:38










              • >sapply(strsplit(as.character(sm_agg$x), "[,]+"), function(i) sum(as.numeric(i))) [1] 8.000000 NA 8.000000 16.000000 NA 4.000000 4.000000 4.000000 5.333333 NA [11] NA 5.333333 NA 8.000000 5.333333 5.333333
                – Kiran Pg
                Nov 10 at 5:57










              • You forgot the space in the pattern. That space is not an accident or a "code style preference". If you want to be even clearer, replace "[ ,]+" (notice the space, total of five chars within the quotes) with "[\s,]+" (no space here, the \s includes spaces and tabs).
                – r2evans
                Nov 10 at 6:05








              • 1




                You can accept it by clicking on the check mark next to vote button.
                – Ronak Shah
                Nov 10 at 11:50















              up vote
              1
              down vote



              accepted










              Try this:



              sm_agg$x <- sapply(strsplit(sm_agg$x, "[ ,]+"), function(i) sum(as.numeric(i)))
              sm_agg
              # Group.1 x
              # 1 1001 8.000000
              # 2 1002 24.000000
              # 3 1003 8.000000
              # 4 1004 16.000000
              # 5 1005 13.333333
              # 6 1006 4.000000
              # 7 1007 4.000000
              # 8 1008 4.000000
              # 9 1009 5.333333
              # 10 1010 13.333333
              # 11 1011 12.000000
              # 12 1012 5.333333
              # 13 1013 13.333333
              # 14 1014 8.000000
              # 15 1015 5.333333
              # 16 1016 5.333333


              Explanation:





              1. For a single entry, we split it by one or more commas/spaces:



                strsplit(sm_agg$x[2], "[, ]+")
                # [[1]]
                # [1] "16" "8"



              2. With that, we want to convert to numbers and add, so



                as.numeric(strsplit(sm_agg$x[2], "[, ]+")[[1]])
                # [1] 16 8
                sum(as.numeric(strsplit(sm_agg$x[2], "[, ]+")[[1]]))
                # [1] 24


              3. We want to do that for every element, so we instead feed the strsplit output into an sapply anon-function.





              If your frame has factors instead of strings, then instead use



              sapply(strsplit(as.character(sm_agg$x), "[ ,]+"), function(i) sum(as.numeric(i)))




              Last Edit



              I think your data is actually an embedded list. When data contains a list-column, it presents like that (which I find a little frustrating, but still ...).



              I'll generate some fake data to demonstrate what I think you actually have:



              sm2 <- data.frame(Group.1 = c("1001", "1002", "1003", "1005"))
              sm2$x <- list(c(8L), c(16L,8L), c(8L), c(16/3, 8))
              sm2
              # Group.1 x
              # 1 1001 8
              # 2 1002 16, 8
              # 3 1003 8
              # 4 1005 5.333333, 8.000000


              Okay. When we tried strsplit and even as.character, things break and are obviously not number-like:



              as.character(sm2$x)
              # [1] "8" "c(16, 8)" "8"
              # [4] "c(5.33333333333333, 8)"


              When in fact, all we have to do is just sum them up, because they're already numbers.



              sapply(sm2$x, sum)
              # [1] 8.00000 24.00000 8.00000 13.33333


              If by chance one of the nested things is actually a character:



              sm2$y <- list(c("8"), c(16L,8L), c(8L), c(16/3, 8))
              sm2
              # Group.1 x y
              # 1 1001 8 8
              # 2 1002 16, 8 16, 8
              # 3 1003 8 8
              # 4 1005 5.333333, 8.000000 5.333333, 8.000000


              which will cause our "simple" solution to fail.



              sapply(sm2$y, sum)
              # Error in FUN(X[[i]], ...) : invalid 'type' (character) of argument


              Luckily, we can be a bit over-handed and force strings to numbers, and numbers to numbers:



              sapply(sm2$y, function(i) sum(as.numeric(i)))
              # [1] 8.00000 24.00000 8.00000 13.33333
              sapply(sm2$x, function(i) sum(as.numeric(i)))
              # [1] 8.00000 24.00000 8.00000 13.33333





              share|improve this answer























              • when i apply this i got error > as.numeric(strsplit(sm_agg$x[2], "[, ]+")[[1]]) Error in strsplit(sm_agg$x[2], "[, ]+") : non-character argument > sm_agg$x <- sapply(strsplit(sm_agg$x, "[ ,]+"), function(i) sum(as.numeric(i))) Error in strsplit(sm_agg$x, "[ ,]+") : non-character argument >
                – Kiran Pg
                Nov 10 at 5:33








              • 1




                You have factors in your data. In the future, presenting your data in an unambiguous way such as dput(head(sm_agg)) would have prevented this. See my edit for the workaround.
                – r2evans
                Nov 10 at 5:38










              • >sapply(strsplit(as.character(sm_agg$x), "[,]+"), function(i) sum(as.numeric(i))) [1] 8.000000 NA 8.000000 16.000000 NA 4.000000 4.000000 4.000000 5.333333 NA [11] NA 5.333333 NA 8.000000 5.333333 5.333333
                – Kiran Pg
                Nov 10 at 5:57










              • You forgot the space in the pattern. That space is not an accident or a "code style preference". If you want to be even clearer, replace "[ ,]+" (notice the space, total of five chars within the quotes) with "[\s,]+" (no space here, the \s includes spaces and tabs).
                – r2evans
                Nov 10 at 6:05








              • 1




                You can accept it by clicking on the check mark next to vote button.
                – Ronak Shah
                Nov 10 at 11:50













              up vote
              1
              down vote



              accepted







              up vote
              1
              down vote



              accepted






              Try this:



              sm_agg$x <- sapply(strsplit(sm_agg$x, "[ ,]+"), function(i) sum(as.numeric(i)))
              sm_agg
              # Group.1 x
              # 1 1001 8.000000
              # 2 1002 24.000000
              # 3 1003 8.000000
              # 4 1004 16.000000
              # 5 1005 13.333333
              # 6 1006 4.000000
              # 7 1007 4.000000
              # 8 1008 4.000000
              # 9 1009 5.333333
              # 10 1010 13.333333
              # 11 1011 12.000000
              # 12 1012 5.333333
              # 13 1013 13.333333
              # 14 1014 8.000000
              # 15 1015 5.333333
              # 16 1016 5.333333


              Explanation:





              1. For a single entry, we split it by one or more commas/spaces:



                strsplit(sm_agg$x[2], "[, ]+")
                # [[1]]
                # [1] "16" "8"



              2. With that, we want to convert to numbers and add, so



                as.numeric(strsplit(sm_agg$x[2], "[, ]+")[[1]])
                # [1] 16 8
                sum(as.numeric(strsplit(sm_agg$x[2], "[, ]+")[[1]]))
                # [1] 24


              3. We want to do that for every element, so we instead feed the strsplit output into an sapply anon-function.





              If your frame has factors instead of strings, then instead use



              sapply(strsplit(as.character(sm_agg$x), "[ ,]+"), function(i) sum(as.numeric(i)))




              Last Edit



              I think your data is actually an embedded list. When data contains a list-column, it presents like that (which I find a little frustrating, but still ...).



              I'll generate some fake data to demonstrate what I think you actually have:



              sm2 <- data.frame(Group.1 = c("1001", "1002", "1003", "1005"))
              sm2$x <- list(c(8L), c(16L,8L), c(8L), c(16/3, 8))
              sm2
              # Group.1 x
              # 1 1001 8
              # 2 1002 16, 8
              # 3 1003 8
              # 4 1005 5.333333, 8.000000


              Okay. When we tried strsplit and even as.character, things break and are obviously not number-like:



              as.character(sm2$x)
              # [1] "8" "c(16, 8)" "8"
              # [4] "c(5.33333333333333, 8)"


              When in fact, all we have to do is just sum them up, because they're already numbers.



              sapply(sm2$x, sum)
              # [1] 8.00000 24.00000 8.00000 13.33333


              If by chance one of the nested things is actually a character:



              sm2$y <- list(c("8"), c(16L,8L), c(8L), c(16/3, 8))
              sm2
              # Group.1 x y
              # 1 1001 8 8
              # 2 1002 16, 8 16, 8
              # 3 1003 8 8
              # 4 1005 5.333333, 8.000000 5.333333, 8.000000


              which will cause our "simple" solution to fail.



              sapply(sm2$y, sum)
              # Error in FUN(X[[i]], ...) : invalid 'type' (character) of argument


              Luckily, we can be a bit over-handed and force strings to numbers, and numbers to numbers:



              sapply(sm2$y, function(i) sum(as.numeric(i)))
              # [1] 8.00000 24.00000 8.00000 13.33333
              sapply(sm2$x, function(i) sum(as.numeric(i)))
              # [1] 8.00000 24.00000 8.00000 13.33333





              share|improve this answer














              Try this:



              sm_agg$x <- sapply(strsplit(sm_agg$x, "[ ,]+"), function(i) sum(as.numeric(i)))
              sm_agg
              # Group.1 x
              # 1 1001 8.000000
              # 2 1002 24.000000
              # 3 1003 8.000000
              # 4 1004 16.000000
              # 5 1005 13.333333
              # 6 1006 4.000000
              # 7 1007 4.000000
              # 8 1008 4.000000
              # 9 1009 5.333333
              # 10 1010 13.333333
              # 11 1011 12.000000
              # 12 1012 5.333333
              # 13 1013 13.333333
              # 14 1014 8.000000
              # 15 1015 5.333333
              # 16 1016 5.333333


              Explanation:





              1. For a single entry, we split it by one or more commas/spaces:



                strsplit(sm_agg$x[2], "[, ]+")
                # [[1]]
                # [1] "16" "8"



              2. With that, we want to convert to numbers and add, so



                as.numeric(strsplit(sm_agg$x[2], "[, ]+")[[1]])
                # [1] 16 8
                sum(as.numeric(strsplit(sm_agg$x[2], "[, ]+")[[1]]))
                # [1] 24


              3. We want to do that for every element, so we instead feed the strsplit output into an sapply anon-function.





              If your frame has factors instead of strings, then instead use



              sapply(strsplit(as.character(sm_agg$x), "[ ,]+"), function(i) sum(as.numeric(i)))




              Last Edit



              I think your data is actually an embedded list. When data contains a list-column, it presents like that (which I find a little frustrating, but still ...).



              I'll generate some fake data to demonstrate what I think you actually have:



              sm2 <- data.frame(Group.1 = c("1001", "1002", "1003", "1005"))
              sm2$x <- list(c(8L), c(16L,8L), c(8L), c(16/3, 8))
              sm2
              # Group.1 x
              # 1 1001 8
              # 2 1002 16, 8
              # 3 1003 8
              # 4 1005 5.333333, 8.000000


              Okay. When we tried strsplit and even as.character, things break and are obviously not number-like:



              as.character(sm2$x)
              # [1] "8" "c(16, 8)" "8"
              # [4] "c(5.33333333333333, 8)"


              When in fact, all we have to do is just sum them up, because they're already numbers.



              sapply(sm2$x, sum)
              # [1] 8.00000 24.00000 8.00000 13.33333


              If by chance one of the nested things is actually a character:



              sm2$y <- list(c("8"), c(16L,8L), c(8L), c(16/3, 8))
              sm2
              # Group.1 x y
              # 1 1001 8 8
              # 2 1002 16, 8 16, 8
              # 3 1003 8 8
              # 4 1005 5.333333, 8.000000 5.333333, 8.000000


              which will cause our "simple" solution to fail.



              sapply(sm2$y, sum)
              # Error in FUN(X[[i]], ...) : invalid 'type' (character) of argument


              Luckily, we can be a bit over-handed and force strings to numbers, and numbers to numbers:



              sapply(sm2$y, function(i) sum(as.numeric(i)))
              # [1] 8.00000 24.00000 8.00000 13.33333
              sapply(sm2$x, function(i) sum(as.numeric(i)))
              # [1] 8.00000 24.00000 8.00000 13.33333






              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Nov 10 at 6:36

























              answered Nov 10 at 5:13









              r2evans

              25.3k32856




              25.3k32856












              • when i apply this i got error > as.numeric(strsplit(sm_agg$x[2], "[, ]+")[[1]]) Error in strsplit(sm_agg$x[2], "[, ]+") : non-character argument > sm_agg$x <- sapply(strsplit(sm_agg$x, "[ ,]+"), function(i) sum(as.numeric(i))) Error in strsplit(sm_agg$x, "[ ,]+") : non-character argument >
                – Kiran Pg
                Nov 10 at 5:33








              • 1




                You have factors in your data. In the future, presenting your data in an unambiguous way such as dput(head(sm_agg)) would have prevented this. See my edit for the workaround.
                – r2evans
                Nov 10 at 5:38










              • >sapply(strsplit(as.character(sm_agg$x), "[,]+"), function(i) sum(as.numeric(i))) [1] 8.000000 NA 8.000000 16.000000 NA 4.000000 4.000000 4.000000 5.333333 NA [11] NA 5.333333 NA 8.000000 5.333333 5.333333
                – Kiran Pg
                Nov 10 at 5:57










              • You forgot the space in the pattern. That space is not an accident or a "code style preference". If you want to be even clearer, replace "[ ,]+" (notice the space, total of five chars within the quotes) with "[\s,]+" (no space here, the \s includes spaces and tabs).
                – r2evans
                Nov 10 at 6:05








              • 1




                You can accept it by clicking on the check mark next to vote button.
                – Ronak Shah
                Nov 10 at 11:50


















              • when i apply this i got error > as.numeric(strsplit(sm_agg$x[2], "[, ]+")[[1]]) Error in strsplit(sm_agg$x[2], "[, ]+") : non-character argument > sm_agg$x <- sapply(strsplit(sm_agg$x, "[ ,]+"), function(i) sum(as.numeric(i))) Error in strsplit(sm_agg$x, "[ ,]+") : non-character argument >
                – Kiran Pg
                Nov 10 at 5:33








              • 1




                You have factors in your data. In the future, presenting your data in an unambiguous way such as dput(head(sm_agg)) would have prevented this. See my edit for the workaround.
                – r2evans
                Nov 10 at 5:38










              • >sapply(strsplit(as.character(sm_agg$x), "[,]+"), function(i) sum(as.numeric(i))) [1] 8.000000 NA 8.000000 16.000000 NA 4.000000 4.000000 4.000000 5.333333 NA [11] NA 5.333333 NA 8.000000 5.333333 5.333333
                – Kiran Pg
                Nov 10 at 5:57










              • You forgot the space in the pattern. That space is not an accident or a "code style preference". If you want to be even clearer, replace "[ ,]+" (notice the space, total of five chars within the quotes) with "[\s,]+" (no space here, the \s includes spaces and tabs).
                – r2evans
                Nov 10 at 6:05








              • 1




                You can accept it by clicking on the check mark next to vote button.
                – Ronak Shah
                Nov 10 at 11:50
















              when i apply this i got error > as.numeric(strsplit(sm_agg$x[2], "[, ]+")[[1]]) Error in strsplit(sm_agg$x[2], "[, ]+") : non-character argument > sm_agg$x <- sapply(strsplit(sm_agg$x, "[ ,]+"), function(i) sum(as.numeric(i))) Error in strsplit(sm_agg$x, "[ ,]+") : non-character argument >
              – Kiran Pg
              Nov 10 at 5:33






              when i apply this i got error > as.numeric(strsplit(sm_agg$x[2], "[, ]+")[[1]]) Error in strsplit(sm_agg$x[2], "[, ]+") : non-character argument > sm_agg$x <- sapply(strsplit(sm_agg$x, "[ ,]+"), function(i) sum(as.numeric(i))) Error in strsplit(sm_agg$x, "[ ,]+") : non-character argument >
              – Kiran Pg
              Nov 10 at 5:33






              1




              1




              You have factors in your data. In the future, presenting your data in an unambiguous way such as dput(head(sm_agg)) would have prevented this. See my edit for the workaround.
              – r2evans
              Nov 10 at 5:38




              You have factors in your data. In the future, presenting your data in an unambiguous way such as dput(head(sm_agg)) would have prevented this. See my edit for the workaround.
              – r2evans
              Nov 10 at 5:38












              >sapply(strsplit(as.character(sm_agg$x), "[,]+"), function(i) sum(as.numeric(i))) [1] 8.000000 NA 8.000000 16.000000 NA 4.000000 4.000000 4.000000 5.333333 NA [11] NA 5.333333 NA 8.000000 5.333333 5.333333
              – Kiran Pg
              Nov 10 at 5:57




              >sapply(strsplit(as.character(sm_agg$x), "[,]+"), function(i) sum(as.numeric(i))) [1] 8.000000 NA 8.000000 16.000000 NA 4.000000 4.000000 4.000000 5.333333 NA [11] NA 5.333333 NA 8.000000 5.333333 5.333333
              – Kiran Pg
              Nov 10 at 5:57












              You forgot the space in the pattern. That space is not an accident or a "code style preference". If you want to be even clearer, replace "[ ,]+" (notice the space, total of five chars within the quotes) with "[\s,]+" (no space here, the \s includes spaces and tabs).
              – r2evans
              Nov 10 at 6:05






              You forgot the space in the pattern. That space is not an accident or a "code style preference". If you want to be even clearer, replace "[ ,]+" (notice the space, total of five chars within the quotes) with "[\s,]+" (no space here, the \s includes spaces and tabs).
              – r2evans
              Nov 10 at 6:05






              1




              1




              You can accept it by clicking on the check mark next to vote button.
              – Ronak Shah
              Nov 10 at 11:50




              You can accept it by clicking on the check mark next to vote button.
              – Ronak Shah
              Nov 10 at 11:50












              up vote
              1
              down vote













              We can use separate_rows to separate comma-separated enteries into different rows and then sum by group.



              library(tidyverse)
              df %>%
              separate_rows(x, sep = ",") %>%
              group_by(Group.1) %>%
              summarise(x = sum(as.numeric(x)))


              # Group.1 x
              # <dbl> <dbl>
              # 1 1001 8
              # 2 1002 24
              # 3 1003 8
              # 4 1004 16
              # 5 1005 13.3
              # 6 1006 4
              # 7 1007 4
              # 8 1008 4
              # 9 1009 5.33
              #10 1010 13.3
              #11 1011 12
              #12 1012 5.33
              #13 1013 13.3
              #14 1014 8
              #15 1015 5.33
              #16 1016 5.33


              data



              df <- structure(list(Group.1 = c(1001, 1002, 1003, 1004, 1005, 1006, 
              1007, 1008, 1009, 1010, 1011, 1012, 1013, 1014, 1015, 1016),
              x = structure(c(5L, 7L, 5L, 6L, 10L, 2L, 1L, 1L, 9L, 11L,
              4L, 8L, 10L, 3L, 8L, 8L), .Label = c(" 4",
              " 4", " 8", " 8, 4",
              " 8", " 16", " 16, 8", " 5.33333333333333",
              " 5.33333333333333", " 5.33333333333333, 8", " 8, 5.33333333333333"
              ), class = "factor")), .Names = c("Group.1", "x"), class =
              "data.frame", row.names = c(NA,
              -16L))





              share|improve this answer

























                up vote
                1
                down vote













                We can use separate_rows to separate comma-separated enteries into different rows and then sum by group.



                library(tidyverse)
                df %>%
                separate_rows(x, sep = ",") %>%
                group_by(Group.1) %>%
                summarise(x = sum(as.numeric(x)))


                # Group.1 x
                # <dbl> <dbl>
                # 1 1001 8
                # 2 1002 24
                # 3 1003 8
                # 4 1004 16
                # 5 1005 13.3
                # 6 1006 4
                # 7 1007 4
                # 8 1008 4
                # 9 1009 5.33
                #10 1010 13.3
                #11 1011 12
                #12 1012 5.33
                #13 1013 13.3
                #14 1014 8
                #15 1015 5.33
                #16 1016 5.33


                data



                df <- structure(list(Group.1 = c(1001, 1002, 1003, 1004, 1005, 1006, 
                1007, 1008, 1009, 1010, 1011, 1012, 1013, 1014, 1015, 1016),
                x = structure(c(5L, 7L, 5L, 6L, 10L, 2L, 1L, 1L, 9L, 11L,
                4L, 8L, 10L, 3L, 8L, 8L), .Label = c(" 4",
                " 4", " 8", " 8, 4",
                " 8", " 16", " 16, 8", " 5.33333333333333",
                " 5.33333333333333", " 5.33333333333333, 8", " 8, 5.33333333333333"
                ), class = "factor")), .Names = c("Group.1", "x"), class =
                "data.frame", row.names = c(NA,
                -16L))





                share|improve this answer























                  up vote
                  1
                  down vote










                  up vote
                  1
                  down vote









                  We can use separate_rows to separate comma-separated enteries into different rows and then sum by group.



                  library(tidyverse)
                  df %>%
                  separate_rows(x, sep = ",") %>%
                  group_by(Group.1) %>%
                  summarise(x = sum(as.numeric(x)))


                  # Group.1 x
                  # <dbl> <dbl>
                  # 1 1001 8
                  # 2 1002 24
                  # 3 1003 8
                  # 4 1004 16
                  # 5 1005 13.3
                  # 6 1006 4
                  # 7 1007 4
                  # 8 1008 4
                  # 9 1009 5.33
                  #10 1010 13.3
                  #11 1011 12
                  #12 1012 5.33
                  #13 1013 13.3
                  #14 1014 8
                  #15 1015 5.33
                  #16 1016 5.33


                  data



                  df <- structure(list(Group.1 = c(1001, 1002, 1003, 1004, 1005, 1006, 
                  1007, 1008, 1009, 1010, 1011, 1012, 1013, 1014, 1015, 1016),
                  x = structure(c(5L, 7L, 5L, 6L, 10L, 2L, 1L, 1L, 9L, 11L,
                  4L, 8L, 10L, 3L, 8L, 8L), .Label = c(" 4",
                  " 4", " 8", " 8, 4",
                  " 8", " 16", " 16, 8", " 5.33333333333333",
                  " 5.33333333333333", " 5.33333333333333, 8", " 8, 5.33333333333333"
                  ), class = "factor")), .Names = c("Group.1", "x"), class =
                  "data.frame", row.names = c(NA,
                  -16L))





                  share|improve this answer












                  We can use separate_rows to separate comma-separated enteries into different rows and then sum by group.



                  library(tidyverse)
                  df %>%
                  separate_rows(x, sep = ",") %>%
                  group_by(Group.1) %>%
                  summarise(x = sum(as.numeric(x)))


                  # Group.1 x
                  # <dbl> <dbl>
                  # 1 1001 8
                  # 2 1002 24
                  # 3 1003 8
                  # 4 1004 16
                  # 5 1005 13.3
                  # 6 1006 4
                  # 7 1007 4
                  # 8 1008 4
                  # 9 1009 5.33
                  #10 1010 13.3
                  #11 1011 12
                  #12 1012 5.33
                  #13 1013 13.3
                  #14 1014 8
                  #15 1015 5.33
                  #16 1016 5.33


                  data



                  df <- structure(list(Group.1 = c(1001, 1002, 1003, 1004, 1005, 1006, 
                  1007, 1008, 1009, 1010, 1011, 1012, 1013, 1014, 1015, 1016),
                  x = structure(c(5L, 7L, 5L, 6L, 10L, 2L, 1L, 1L, 9L, 11L,
                  4L, 8L, 10L, 3L, 8L, 8L), .Label = c(" 4",
                  " 4", " 8", " 8, 4",
                  " 8", " 16", " 16, 8", " 5.33333333333333",
                  " 5.33333333333333", " 5.33333333333333, 8", " 8, 5.33333333333333"
                  ), class = "factor")), .Names = c("Group.1", "x"), class =
                  "data.frame", row.names = c(NA,
                  -16L))






                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Nov 10 at 5:46









                  Ronak Shah

                  30.4k103753




                  30.4k103753






















                      up vote
                      0
                      down vote













                      using this method i get asnwer sapply(sm2$y, function(i) sum(as.numeric(i)))






                      share|improve this answer



























                        up vote
                        0
                        down vote













                        using this method i get asnwer sapply(sm2$y, function(i) sum(as.numeric(i)))






                        share|improve this answer

























                          up vote
                          0
                          down vote










                          up vote
                          0
                          down vote









                          using this method i get asnwer sapply(sm2$y, function(i) sum(as.numeric(i)))






                          share|improve this answer














                          using this method i get asnwer sapply(sm2$y, function(i) sum(as.numeric(i)))







                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited Nov 10 at 10:32

























                          answered Nov 10 at 10:04









                          Kiran Pg

                          228




                          228






























                              draft saved

                              draft discarded




















































                              Thanks for contributing an answer to Stack Overflow!


                              • Please be sure to answer the question. Provide details and share your research!

                              But avoid



                              • Asking for help, clarification, or responding to other answers.

                              • Making statements based on opinion; back them up with references or personal experience.


                              To learn more, see our tips on writing great answers.





                              Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


                              Please pay close attention to the following guidance:


                              • Please be sure to answer the question. Provide details and share your research!

                              But avoid



                              • Asking for help, clarification, or responding to other answers.

                              • Making statements based on opinion; back them up with references or personal experience.


                              To learn more, see our tips on writing great answers.




                              draft saved


                              draft discarded














                              StackExchange.ready(
                              function () {
                              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53236148%2fhow-can-i-calculate-the-sum-of-comma-separated-in-the-2nd-column%23new-answer', 'question_page');
                              }
                              );

                              Post as a guest















                              Required, but never shown





















































                              Required, but never shown














                              Required, but never shown












                              Required, but never shown







                              Required, but never shown

































                              Required, but never shown














                              Required, but never shown












                              Required, but never shown







                              Required, but never shown







                              Popular posts from this blog

                              Schultheiß

                              Liste der Kulturdenkmale in Wilsdruff

                              Android Play Services Check