how to send multi part file from android to rest web service(Spring)?
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I want to send Multipart file from android device to rest service which has developed in Spring.
Here is my android code..
@Override
protected void onActivityResult(int requestCode, int resultCode, @Nullable Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == 1 && resultCode == RESULT_OK && data != null && data.getData() != null) {
Uri filePath = data.getData();
try {
bitmap = MediaStore.Images.Media.getBitmap(getContentResolver(), filePath);
imageView.setImageBitmap(bitmap);
} catch (IOException e) {
e.printStackTrace();
}
try {
String path = getPath(filePath);
//Creating a multi part request
new MultipartUploadRequest(this,"http://localhost:8080/samplerestfullservice/classtest/upload1")
.addFileToUpload(path, "image")//Adding file
.setNotificationConfig(new UploadNotificationConfig())
.setMaxRetries(2)
.startUpload(); //Starting the upload
} catch (Exception exc) {
Toast.makeText(this, exc.getMessage(), Toast.LENGTH_SHORT).show();
}
}
}
public String getPath(Uri uri) {
String projection={MediaStore.Images.Media.DATA};
Cursor cursor=getContentResolver().query(uri,projection,null,null,null);
if(cursor == null){
return null;
}
int columnIndex= cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
cursor.moveToFirst();
String s=cursor.getString(columnIndex);
cursor.close();
return s;
}
And my service code is
@RequestMapping(value = "/upload1", method = RequestMethod.POST, headers = "Content-Type= multipart/form-data" )
@ResponseBody
public void fileUpload(@RequestParam MultipartFile file){
System.out.print("Success");
// rest of the code
}
And I have declared internet permission in manifest.xml but the client request doesn't reach the service.And I don't know is there any compatibility problem.
Please can any one give suggestion.
Thank You.
java
android multipart asked Nov 10 at 5:03
Sunil T
64
add a comment |
up vote
0
down vote
favorite
I want to send Multipart file from android device to rest service which has developed in Spring.
Here is my android code..
@Override
protected void onActivityResult(int requestCode, int resultCode, @Nullable Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == 1 && resultCode == RESULT_OK && data != null && data.getData() != null) {
Uri filePath = data.getData();
try {
bitmap = MediaStore.Images.Media.getBitmap(getContentResolver(), filePath);
imageView.setImageBitmap(bitmap);
} catch (IOException e) {
e.printStackTrace();
}
try {
String path = getPath(filePath);
//Creating a multi part request
new MultipartUploadRequest(this,"http://localhost:8080/samplerestfullservice/classtest/upload1")
.addFileToUpload(path, "image")//Adding file
.setNotificationConfig(new UploadNotificationConfig())
.setMaxRetries(2)
.startUpload(); //Starting the upload
} catch (Exception exc) {
Toast.makeText(this, exc.getMessage(), Toast.LENGTH_SHORT).show();
}
}
}
public String getPath(Uri uri) {
String projection={MediaStore.Images.Media.DATA};
Cursor cursor=getContentResolver().query(uri,projection,null,null,null);
if(cursor == null){
return null;
}
int columnIndex= cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
cursor.moveToFirst();
String s=cursor.getString(columnIndex);
cursor.close();
return s;
}
And my service code is
@RequestMapping(value = "/upload1", method = RequestMethod.POST, headers = "Content-Type= multipart/form-data" )
@ResponseBody
public void fileUpload(@RequestParam MultipartFile file){
System.out.print("Success");
// rest of the code
}
And I have declared internet permission in manifest.xml but the client request doesn't reach the service.And I don't know is there any compatibility problem.
Please can any one give suggestion.
Thank You.
java
android multipart asked Nov 10 at 5:03
Sunil T
64
shouldn't this.addFileToUpload(path, "image")be like.addFileToUpload("file_name", "path")?
– Ali Ahmed
Nov 10 at 5:32
Sorry Ali I didn't get you.."file-name" in the sense file path right
– Sunil T
Nov 10 at 5:41
you have write the path as 1st argument. i think so it should be 2nd.
– Ali Ahmed
Nov 10 at 5:45
No Ali 1st argument should be path and 2nd should be parameter name like this......MultipartUploadRequest addFileToUpload(final String path, final String parameterName)
– Sunil T
Nov 10 at 5:50
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I want to send Multipart file from android device to rest service which has developed in Spring.
Here is my android code..
@Override
protected void onActivityResult(int requestCode, int resultCode, @Nullable Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == 1 && resultCode == RESULT_OK && data != null && data.getData() != null) {
Uri filePath = data.getData();
try {
bitmap = MediaStore.Images.Media.getBitmap(getContentResolver(), filePath);
imageView.setImageBitmap(bitmap);
} catch (IOException e) {
e.printStackTrace();
}
try {
String path = getPath(filePath);
//Creating a multi part request
new MultipartUploadRequest(this,"http://localhost:8080/samplerestfullservice/classtest/upload1")
.addFileToUpload(path, "image")//Adding file
.setNotificationConfig(new UploadNotificationConfig())
.setMaxRetries(2)
.startUpload(); //Starting the upload
} catch (Exception exc) {
Toast.makeText(this, exc.getMessage(), Toast.LENGTH_SHORT).show();
}
}
}
public String getPath(Uri uri) {
String projection={MediaStore.Images.Media.DATA};
Cursor cursor=getContentResolver().query(uri,projection,null,null,null);
if(cursor == null){
return null;
}
int columnIndex= cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
cursor.moveToFirst();
String s=cursor.getString(columnIndex);
cursor.close();
return s;
}
And my service code is
@RequestMapping(value = "/upload1", method = RequestMethod.POST, headers = "Content-Type= multipart/form-data" )
@ResponseBody
public void fileUpload(@RequestParam MultipartFile file){
System.out.print("Success");
// rest of the code
}
And I have declared internet permission in manifest.xml but the client request doesn't reach the service.And I don't know is there any compatibility problem.
Please can any one give suggestion.
Thank You.
java
android multipart asked Nov 10 at 5:03
Sunil T
64
I want to send Multipart file from android device to rest service which has developed in Spring.
Here is my android code..
@Override
protected void onActivityResult(int requestCode, int resultCode, @Nullable Intent data) {
super.onActivityResult(requestCode, resultCode, data);
if (requestCode == 1 && resultCode == RESULT_OK && data != null && data.getData() != null) {
Uri filePath = data.getData();
try {
bitmap = MediaStore.Images.Media.getBitmap(getContentResolver(), filePath);
imageView.setImageBitmap(bitmap);
} catch (IOException e) {
e.printStackTrace();
}
try {
String path = getPath(filePath);
//Creating a multi part request
new MultipartUploadRequest(this,"http://localhost:8080/samplerestfullservice/classtest/upload1")
.addFileToUpload(path, "image")//Adding file
.setNotificationConfig(new UploadNotificationConfig())
.setMaxRetries(2)
.startUpload(); //Starting the upload
} catch (Exception exc) {
Toast.makeText(this, exc.getMessage(), Toast.LENGTH_SHORT).show();
}
}
}
public String getPath(Uri uri) {
String projection={MediaStore.Images.Media.DATA};
Cursor cursor=getContentResolver().query(uri,projection,null,null,null);
if(cursor == null){
return null;
}
int columnIndex= cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
cursor.moveToFirst();
String s=cursor.getString(columnIndex);
cursor.close();
return s;
}
And my service code is
@RequestMapping(value = "/upload1", method = RequestMethod.POST, headers = "Content-Type= multipart/form-data" )
@ResponseBody
public void fileUpload(@RequestParam MultipartFile file){
System.out.print("Success");
// rest of the code
}
And I have declared internet permission in manifest.xml but the client request doesn't reach the service.And I don't know is there any compatibility problem.
Please can any one give suggestion.
Thank You.
java
android multipart java
android multipart asked Nov 10 at 5:03
Sunil T
64
asked Nov 10 at 5:03
Sunil T
64
asked Nov 10 at 5:03
Sunil T
64
asked Nov 10 at 5:03
Sunil T
64
asked Nov 10 at 5:03
Sunil T
64
64
shouldn't this.addFileToUpload(path, "image")be like.addFileToUpload("file_name", "path")?
– Ali Ahmed
Nov 10 at 5:32
Sorry Ali I didn't get you.."file-name" in the sense file path right
– Sunil T
Nov 10 at 5:41
you have write the path as 1st argument. i think so it should be 2nd.
– Ali Ahmed
Nov 10 at 5:45
No Ali 1st argument should be path and 2nd should be parameter name like this......MultipartUploadRequest addFileToUpload(final String path, final String parameterName)
– Sunil T
Nov 10 at 5:50
add a comment |
shouldn't this.addFileToUpload(path, "image")be like.addFileToUpload("file_name", "path")?
– Ali Ahmed
Nov 10 at 5:32
Sorry Ali I didn't get you.."file-name" in the sense file path right
– Sunil T
Nov 10 at 5:41
you have write the path as 1st argument. i think so it should be 2nd.
– Ali Ahmed
Nov 10 at 5:45
No Ali 1st argument should be path and 2nd should be parameter name like this......MultipartUploadRequest addFileToUpload(final String path, final String parameterName)
– Sunil T
Nov 10 at 5:50
shouldn't this
.addFileToUpload(path, "image") be like .addFileToUpload("file_name", "path")?– Ali Ahmed
Nov 10 at 5:32
shouldn't this
.addFileToUpload(path, "image") be like .addFileToUpload("file_name", "path")?– Ali Ahmed
Nov 10 at 5:32
Sorry Ali I didn't get you.."file-name" in the sense file path right
– Sunil T
Nov 10 at 5:41
Sorry Ali I didn't get you.."file-name" in the sense file path right
– Sunil T
Nov 10 at 5:41
you have write the path as 1st argument. i think so it should be 2nd.
– Ali Ahmed
Nov 10 at 5:45
you have write the path as 1st argument. i think so it should be 2nd.
– Ali Ahmed
Nov 10 at 5:45
No Ali 1st argument should be path and 2nd should be parameter name like this......MultipartUploadRequest addFileToUpload(final String path, final String parameterName)
– Sunil T
Nov 10 at 5:50
No Ali 1st argument should be path and 2nd should be parameter name like this......MultipartUploadRequest addFileToUpload(final String path, final String parameterName)
– Sunil T
Nov 10 at 5:50
add a comment |
1 Answer
1
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0
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I have wrote lightweight and easy to use library that solves your problem. It is described here https://stackoverflow.com/a/53253933/8849079:)
answered Nov 18 at 14:36
Igor
1044
add a comment |
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1 Answer
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active
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oldest
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up vote
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I have wrote lightweight and easy to use library that solves your problem. It is described here https://stackoverflow.com/a/53253933/8849079:)
answered Nov 18 at 14:36
Igor
1044
add a comment |
up vote
0
down vote
I have wrote lightweight and easy to use library that solves your problem. It is described here https://stackoverflow.com/a/53253933/8849079:)
answered Nov 18 at 14:36
Igor
1044
add a comment |
up vote
0
down vote
up vote
0
down vote
I have wrote lightweight and easy to use library that solves your problem. It is described here https://stackoverflow.com/a/53253933/8849079:)
answered Nov 18 at 14:36
Igor
1044
I have wrote lightweight and easy to use library that solves your problem. It is described here https://stackoverflow.com/a/53253933/8849079:)
answered Nov 18 at 14:36
Igor
1044
answered Nov 18 at 14:36
Igor
1044
answered Nov 18 at 14:36
Igor
1044
answered Nov 18 at 14:36
Igor
1044
1044
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add a comment |
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shouldn't this
.addFileToUpload(path, "image")be like.addFileToUpload("file_name", "path")?– Ali Ahmed
Nov 10 at 5:32
Sorry Ali I didn't get you.."file-name" in the sense file path right
– Sunil T
Nov 10 at 5:41
you have write the path as 1st argument. i think so it should be 2nd.
– Ali Ahmed
Nov 10 at 5:45
No Ali 1st argument should be path and 2nd should be parameter name like this......MultipartUploadRequest addFileToUpload(final String path, final String parameterName)
– Sunil T
Nov 10 at 5:50