array isn´t getting mysql data php











up vote
-1
down vote

favorite












I have had my webpages in diferents hostings, and in all this hosting it was working fine, a few days a go, I bought one hosting in godaddy, I made the backup of the database, and then I put it in the hosting of godaddy, but I have a problem, when I am trying to put de data of my query into an array to convert it in a json, it didnt show something. in the other hosting and localhost it is working fine.



$sql1 = "SELECT * FROM table Where somthing='$something'";

$ejecutar_sql1=mysqli_query($con,$sql1);



if (mysqli_num_rows($ejecutar_sql1) > 0){

    $rawdata = array(); 

    $i=0;

    while($row = mysqli_fetch_array($ejecutar_sql1))

    {

        $rawdata[$i] = $row;

        $i++;

    }

    echo json_encode($rawdata);

}



  • If I put echo mysqli_num_rows($ejecutar_sql1); its show me 270.

  • If I put echo $row["id"]; inside the while, it show me all the id.

  • If I put echo count($rawdata); its show me 270.

  • But the echo json_encode($rawdata); it didnt show something.


thanks for the help






php mysql arrays json mysqli







share|improve this question
























  • Should somthing in your query be something ?
    – rpm192
    Nov 9 at 22:34










  • @rpm192 this query is an example, that was the reason that I put that it is show me the number of row of my query it is gettin the data of my database but $rawdata didnt show the info
    – joshrs
    Nov 9 at 22:38










  • Enable error reporting and mysqli_error($con) see what that shows. I've tested your code (also) with no problems.
    – Funk Forty Niner
    Nov 9 at 23:03






  • 1




    Error checking but if you cannot be bothered, Add ini_set('display_errors', 1); ini_set('log_errors',1); error_reporting(E_ALL); mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT); to the top of your script. This will force any mysqli_ errors to generate an Exception that you can see on the browser as well as normal PHP errors.
    – RiggsFolly
    Nov 10 at 0:18






  • 1




    Nobody's going to say this but: The problem is GoDaddy. They are the worst host on the planet. Run (don't walk) to a different host.
    – cale_b
    Nov 10 at 0:19















up vote
-1
down vote

favorite












I have had my webpages in diferents hostings, and in all this hosting it was working fine, a few days a go, I bought one hosting in godaddy, I made the backup of the database, and then I put it in the hosting of godaddy, but I have a problem, when I am trying to put de data of my query into an array to convert it in a json, it didnt show something. in the other hosting and localhost it is working fine.



$sql1 = "SELECT * FROM table Where somthing='$something'";

$ejecutar_sql1=mysqli_query($con,$sql1);



if (mysqli_num_rows($ejecutar_sql1) > 0){

    $rawdata = array(); 

    $i=0;

    while($row = mysqli_fetch_array($ejecutar_sql1))

    {

        $rawdata[$i] = $row;

        $i++;

    }

    echo json_encode($rawdata);

}



  • If I put echo mysqli_num_rows($ejecutar_sql1); its show me 270.

  • If I put echo $row["id"]; inside the while, it show me all the id.

  • If I put echo count($rawdata); its show me 270.

  • But the echo json_encode($rawdata); it didnt show something.


thanks for the help






php mysql arrays json mysqli







share|improve this question
























  • Should somthing in your query be something ?
    – rpm192
    Nov 9 at 22:34










  • @rpm192 this query is an example, that was the reason that I put that it is show me the number of row of my query it is gettin the data of my database but $rawdata didnt show the info
    – joshrs
    Nov 9 at 22:38










  • Enable error reporting and mysqli_error($con) see what that shows. I've tested your code (also) with no problems.
    – Funk Forty Niner
    Nov 9 at 23:03






  • 1




    Error checking but if you cannot be bothered, Add ini_set('display_errors', 1); ini_set('log_errors',1); error_reporting(E_ALL); mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT); to the top of your script. This will force any mysqli_ errors to generate an Exception that you can see on the browser as well as normal PHP errors.
    – RiggsFolly
    Nov 10 at 0:18






  • 1




    Nobody's going to say this but: The problem is GoDaddy. They are the worst host on the planet. Run (don't walk) to a different host.
    – cale_b
    Nov 10 at 0:19













up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











I have had my webpages in diferents hostings, and in all this hosting it was working fine, a few days a go, I bought one hosting in godaddy, I made the backup of the database, and then I put it in the hosting of godaddy, but I have a problem, when I am trying to put de data of my query into an array to convert it in a json, it didnt show something. in the other hosting and localhost it is working fine.



$sql1 = "SELECT * FROM table Where somthing='$something'";

$ejecutar_sql1=mysqli_query($con,$sql1);



if (mysqli_num_rows($ejecutar_sql1) > 0){

    $rawdata = array(); 

    $i=0;

    while($row = mysqli_fetch_array($ejecutar_sql1))

    {

        $rawdata[$i] = $row;

        $i++;

    }

    echo json_encode($rawdata);

}



  • If I put echo mysqli_num_rows($ejecutar_sql1); its show me 270.

  • If I put echo $row["id"]; inside the while, it show me all the id.

  • If I put echo count($rawdata); its show me 270.

  • But the echo json_encode($rawdata); it didnt show something.


thanks for the help






php mysql arrays json mysqli







share|improve this question















I have had my webpages in diferents hostings, and in all this hosting it was working fine, a few days a go, I bought one hosting in godaddy, I made the backup of the database, and then I put it in the hosting of godaddy, but I have a problem, when I am trying to put de data of my query into an array to convert it in a json, it didnt show something. in the other hosting and localhost it is working fine.



$sql1 = "SELECT * FROM table Where somthing='$something'";

$ejecutar_sql1=mysqli_query($con,$sql1);



if (mysqli_num_rows($ejecutar_sql1) > 0){

    $rawdata = array(); 

    $i=0;

    while($row = mysqli_fetch_array($ejecutar_sql1))

    {

        $rawdata[$i] = $row;

        $i++;

    }

    echo json_encode($rawdata);

}



  • If I put echo mysqli_num_rows($ejecutar_sql1); its show me 270.

  • If I put echo $row["id"]; inside the while, it show me all the id.

  • If I put echo count($rawdata); its show me 270.

  • But the echo json_encode($rawdata); it didnt show something.


thanks for the help






php mysql arrays json mysqli




php mysql arrays json mysqli






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 10 at 4:42









paulsm4

76.4k999124




76.4k999124










asked Nov 9 at 22:31









joshrs

134




134












  • Should somthing in your query be something ?
    – rpm192
    Nov 9 at 22:34










  • @rpm192 this query is an example, that was the reason that I put that it is show me the number of row of my query it is gettin the data of my database but $rawdata didnt show the info
    – joshrs
    Nov 9 at 22:38










  • Enable error reporting and mysqli_error($con) see what that shows. I've tested your code (also) with no problems.
    – Funk Forty Niner
    Nov 9 at 23:03






  • 1




    Error checking but if you cannot be bothered, Add ini_set('display_errors', 1); ini_set('log_errors',1); error_reporting(E_ALL); mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT); to the top of your script. This will force any mysqli_ errors to generate an Exception that you can see on the browser as well as normal PHP errors.
    – RiggsFolly
    Nov 10 at 0:18






  • 1




    Nobody's going to say this but: The problem is GoDaddy. They are the worst host on the planet. Run (don't walk) to a different host.
    – cale_b
    Nov 10 at 0:19


















  • Should somthing in your query be something ?
    – rpm192
    Nov 9 at 22:34










  • @rpm192 this query is an example, that was the reason that I put that it is show me the number of row of my query it is gettin the data of my database but $rawdata didnt show the info
    – joshrs
    Nov 9 at 22:38










  • Enable error reporting and mysqli_error($con) see what that shows. I've tested your code (also) with no problems.
    – Funk Forty Niner
    Nov 9 at 23:03






  • 1




    Error checking but if you cannot be bothered, Add ini_set('display_errors', 1); ini_set('log_errors',1); error_reporting(E_ALL); mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT); to the top of your script. This will force any mysqli_ errors to generate an Exception that you can see on the browser as well as normal PHP errors.
    – RiggsFolly
    Nov 10 at 0:18






  • 1




    Nobody's going to say this but: The problem is GoDaddy. They are the worst host on the planet. Run (don't walk) to a different host.
    – cale_b
    Nov 10 at 0:19
















Should somthing in your query be something ?
– rpm192
Nov 9 at 22:34




Should somthing in your query be something ?
– rpm192
Nov 9 at 22:34












@rpm192 this query is an example, that was the reason that I put that it is show me the number of row of my query it is gettin the data of my database but $rawdata didnt show the info
– joshrs
Nov 9 at 22:38




@rpm192 this query is an example, that was the reason that I put that it is show me the number of row of my query it is gettin the data of my database but $rawdata didnt show the info
– joshrs
Nov 9 at 22:38












Enable error reporting and mysqli_error($con) see what that shows. I've tested your code (also) with no problems.
– Funk Forty Niner
Nov 9 at 23:03




Enable error reporting and mysqli_error($con) see what that shows. I've tested your code (also) with no problems.
– Funk Forty Niner
Nov 9 at 23:03




1




1




Error checking but if you cannot be bothered, Add ini_set('display_errors', 1); ini_set('log_errors',1); error_reporting(E_ALL); mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT); to the top of your script. This will force any mysqli_ errors to generate an Exception that you can see on the browser as well as normal PHP errors.
– RiggsFolly
Nov 10 at 0:18




Error checking but if you cannot be bothered, Add ini_set('display_errors', 1); ini_set('log_errors',1); error_reporting(E_ALL); mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT); to the top of your script. This will force any mysqli_ errors to generate an Exception that you can see on the browser as well as normal PHP errors.
– RiggsFolly
Nov 10 at 0:18




1




1




Nobody's going to say this but: The problem is GoDaddy. They are the worst host on the planet. Run (don't walk) to a different host.
– cale_b
Nov 10 at 0:19




Nobody's going to say this but: The problem is GoDaddy. They are the worst host on the planet. Run (don't walk) to a different host.
– cale_b
Nov 10 at 0:19












2 Answers
2






active

oldest

votes

















up vote
1
down vote



accepted










OK -




  1. Your code worked fine on other hosts, before you moved to GoDaddy, correct?


  2. You believe that you imported the data correctly - because you're able to fetch 270 rows. Correct?


  3. The only thing that's failing is json_encode(), correct?



SUGGESTIONS:




  • Check the encoding: php JSON_encode not working


  • Apply error handling to json_encode. For example, echo json_last_error() in your PHP. You might also consider adding JSON_THROW_ON_ERROR option parameter.







share|improve this answer





















  • I tried with this post, but it show that its ok, it doesnt has problem with the encode
    – joshrs
    Nov 9 at 23:05










  • Q: Are questions 1 and 2 correct? The code used to work, and you're successfully fetching data into $rawdata? Please confirm. Q: Have you TRIED adding json_last_error() yet? If json_last_error() returns anything, please copy/paste it into your post.
    – paulsm4
    Nov 10 at 1:13












  • I solved the problem, some words had acents like corazón in the second o, but I dont know why in the other hosting I didnt have this problem and in godady yes
    – joshrs
    Nov 10 at 2:18










  • I'm glad you found the root cause. If you read the link I cited above, you'd see the accepted answer says Malformed UTF-8 characters, possibly incorrectly encoded. See also: PHP json encode - Malformed UTF-8 characters, possibly incorrectly encoded. STRONG SUGGESTION: try to put good error checking/recovery throughout your code. Including things like json_last_error().
    – paulsm4
    Nov 10 at 4:39












  • thank you very much
    – joshrs
    Nov 10 at 15:36


















up vote
-2
down vote













you need to shift (remove) the first object of the array
use firstly



<?php array_shift($rawdata);?>


then you use what you want 



 echo json_encode($rawdata);





share|improve this answer

















  • 2




    What problem would this solve?
    – miken32
    Nov 9 at 22:46











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote



accepted










OK -




  1. Your code worked fine on other hosts, before you moved to GoDaddy, correct?


  2. You believe that you imported the data correctly - because you're able to fetch 270 rows. Correct?


  3. The only thing that's failing is json_encode(), correct?



SUGGESTIONS:




  • Check the encoding: php JSON_encode not working


  • Apply error handling to json_encode. For example, echo json_last_error() in your PHP. You might also consider adding JSON_THROW_ON_ERROR option parameter.







share|improve this answer





















  • I tried with this post, but it show that its ok, it doesnt has problem with the encode
    – joshrs
    Nov 9 at 23:05










  • Q: Are questions 1 and 2 correct? The code used to work, and you're successfully fetching data into $rawdata? Please confirm. Q: Have you TRIED adding json_last_error() yet? If json_last_error() returns anything, please copy/paste it into your post.
    – paulsm4
    Nov 10 at 1:13












  • I solved the problem, some words had acents like corazón in the second o, but I dont know why in the other hosting I didnt have this problem and in godady yes
    – joshrs
    Nov 10 at 2:18










  • I'm glad you found the root cause. If you read the link I cited above, you'd see the accepted answer says Malformed UTF-8 characters, possibly incorrectly encoded. See also: PHP json encode - Malformed UTF-8 characters, possibly incorrectly encoded. STRONG SUGGESTION: try to put good error checking/recovery throughout your code. Including things like json_last_error().
    – paulsm4
    Nov 10 at 4:39












  • thank you very much
    – joshrs
    Nov 10 at 15:36















up vote
1
down vote



accepted










OK -




  1. Your code worked fine on other hosts, before you moved to GoDaddy, correct?


  2. You believe that you imported the data correctly - because you're able to fetch 270 rows. Correct?


  3. The only thing that's failing is json_encode(), correct?



SUGGESTIONS:




  • Check the encoding: php JSON_encode not working


  • Apply error handling to json_encode. For example, echo json_last_error() in your PHP. You might also consider adding JSON_THROW_ON_ERROR option parameter.







share|improve this answer





















  • I tried with this post, but it show that its ok, it doesnt has problem with the encode
    – joshrs
    Nov 9 at 23:05










  • Q: Are questions 1 and 2 correct? The code used to work, and you're successfully fetching data into $rawdata? Please confirm. Q: Have you TRIED adding json_last_error() yet? If json_last_error() returns anything, please copy/paste it into your post.
    – paulsm4
    Nov 10 at 1:13












  • I solved the problem, some words had acents like corazón in the second o, but I dont know why in the other hosting I didnt have this problem and in godady yes
    – joshrs
    Nov 10 at 2:18










  • I'm glad you found the root cause. If you read the link I cited above, you'd see the accepted answer says Malformed UTF-8 characters, possibly incorrectly encoded. See also: PHP json encode - Malformed UTF-8 characters, possibly incorrectly encoded. STRONG SUGGESTION: try to put good error checking/recovery throughout your code. Including things like json_last_error().
    – paulsm4
    Nov 10 at 4:39












  • thank you very much
    – joshrs
    Nov 10 at 15:36













up vote
1
down vote



accepted







up vote
1
down vote



accepted






OK -




  1. Your code worked fine on other hosts, before you moved to GoDaddy, correct?


  2. You believe that you imported the data correctly - because you're able to fetch 270 rows. Correct?


  3. The only thing that's failing is json_encode(), correct?



SUGGESTIONS:




  • Check the encoding: php JSON_encode not working


  • Apply error handling to json_encode. For example, echo json_last_error() in your PHP. You might also consider adding JSON_THROW_ON_ERROR option parameter.







share|improve this answer












OK -




  1. Your code worked fine on other hosts, before you moved to GoDaddy, correct?


  2. You believe that you imported the data correctly - because you're able to fetch 270 rows. Correct?


  3. The only thing that's failing is json_encode(), correct?



SUGGESTIONS:




  • Check the encoding: php JSON_encode not working


  • Apply error handling to json_encode. For example, echo json_last_error() in your PHP. You might also consider adding JSON_THROW_ON_ERROR option parameter.








share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 9 at 22:39









paulsm4

76.4k999124




76.4k999124












  • I tried with this post, but it show that its ok, it doesnt has problem with the encode
    – joshrs
    Nov 9 at 23:05










  • Q: Are questions 1 and 2 correct? The code used to work, and you're successfully fetching data into $rawdata? Please confirm. Q: Have you TRIED adding json_last_error() yet? If json_last_error() returns anything, please copy/paste it into your post.
    – paulsm4
    Nov 10 at 1:13












  • I solved the problem, some words had acents like corazón in the second o, but I dont know why in the other hosting I didnt have this problem and in godady yes
    – joshrs
    Nov 10 at 2:18










  • I'm glad you found the root cause. If you read the link I cited above, you'd see the accepted answer says Malformed UTF-8 characters, possibly incorrectly encoded. See also: PHP json encode - Malformed UTF-8 characters, possibly incorrectly encoded. STRONG SUGGESTION: try to put good error checking/recovery throughout your code. Including things like json_last_error().
    – paulsm4
    Nov 10 at 4:39












  • thank you very much
    – joshrs
    Nov 10 at 15:36


















  • I tried with this post, but it show that its ok, it doesnt has problem with the encode
    – joshrs
    Nov 9 at 23:05










  • Q: Are questions 1 and 2 correct? The code used to work, and you're successfully fetching data into $rawdata? Please confirm. Q: Have you TRIED adding json_last_error() yet? If json_last_error() returns anything, please copy/paste it into your post.
    – paulsm4
    Nov 10 at 1:13












  • I solved the problem, some words had acents like corazón in the second o, but I dont know why in the other hosting I didnt have this problem and in godady yes
    – joshrs
    Nov 10 at 2:18










  • I'm glad you found the root cause. If you read the link I cited above, you'd see the accepted answer says Malformed UTF-8 characters, possibly incorrectly encoded. See also: PHP json encode - Malformed UTF-8 characters, possibly incorrectly encoded. STRONG SUGGESTION: try to put good error checking/recovery throughout your code. Including things like json_last_error().
    – paulsm4
    Nov 10 at 4:39












  • thank you very much
    – joshrs
    Nov 10 at 15:36
















I tried with this post, but it show that its ok, it doesnt has problem with the encode
– joshrs
Nov 9 at 23:05




I tried with this post, but it show that its ok, it doesnt has problem with the encode
– joshrs
Nov 9 at 23:05












Q: Are questions 1 and 2 correct? The code used to work, and you're successfully fetching data into $rawdata? Please confirm. Q: Have you TRIED adding json_last_error() yet? If json_last_error() returns anything, please copy/paste it into your post.
– paulsm4
Nov 10 at 1:13






Q: Are questions 1 and 2 correct? The code used to work, and you're successfully fetching data into $rawdata? Please confirm. Q: Have you TRIED adding json_last_error() yet? If json_last_error() returns anything, please copy/paste it into your post.
– paulsm4
Nov 10 at 1:13














I solved the problem, some words had acents like corazón in the second o, but I dont know why in the other hosting I didnt have this problem and in godady yes
– joshrs
Nov 10 at 2:18




I solved the problem, some words had acents like corazón in the second o, but I dont know why in the other hosting I didnt have this problem and in godady yes
– joshrs
Nov 10 at 2:18












I'm glad you found the root cause. If you read the link I cited above, you'd see the accepted answer says Malformed UTF-8 characters, possibly incorrectly encoded. See also: PHP json encode - Malformed UTF-8 characters, possibly incorrectly encoded. STRONG SUGGESTION: try to put good error checking/recovery throughout your code. Including things like json_last_error().
– paulsm4
Nov 10 at 4:39






I'm glad you found the root cause. If you read the link I cited above, you'd see the accepted answer says Malformed UTF-8 characters, possibly incorrectly encoded. See also: PHP json encode - Malformed UTF-8 characters, possibly incorrectly encoded. STRONG SUGGESTION: try to put good error checking/recovery throughout your code. Including things like json_last_error().
– paulsm4
Nov 10 at 4:39














thank you very much
– joshrs
Nov 10 at 15:36




thank you very much
– joshrs
Nov 10 at 15:36












up vote
-2
down vote













you need to shift (remove) the first object of the array
use firstly



<?php array_shift($rawdata);?>


then you use what you want 



 echo json_encode($rawdata);





share|improve this answer

















  • 2




    What problem would this solve?
    – miken32
    Nov 9 at 22:46















up vote
-2
down vote













you need to shift (remove) the first object of the array
use firstly



<?php array_shift($rawdata);?>


then you use what you want 



 echo json_encode($rawdata);





share|improve this answer

















  • 2




    What problem would this solve?
    – miken32
    Nov 9 at 22:46













up vote
-2
down vote










up vote
-2
down vote









you need to shift (remove) the first object of the array
use firstly



<?php array_shift($rawdata);?>


then you use what you want 



 echo json_encode($rawdata);





share|improve this answer












you need to shift (remove) the first object of the array
use firstly



<?php array_shift($rawdata);?>


then you use what you want 



 echo json_encode($rawdata);






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 9 at 22:38









Abanoub Istfanous

1




1








  • 2




    What problem would this solve?
    – miken32
    Nov 9 at 22:46














  • 2




    What problem would this solve?
    – miken32
    Nov 9 at 22:46








2




2




What problem would this solve?
– miken32
Nov 9 at 22:46




What problem would this solve?
– miken32
Nov 9 at 22:46


















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